Chapter 6: Problem 45
Let \(z\) be a random variable with a standard normal distribution. Find the indicated probability, and shade the corresponding area under the standard normal curve. $$ P(0 \leq z \leq 1.62) $$
Short Answer
Expert verified
The probability \( P(0 \leq z \leq 1.62) \) is approximately 0.4474.
Step by step solution
01
Understand the Standard Normal Distribution
A standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. The random variable, denoted by \( z \), follows this distribution.
02
Identify the Required Probability
We need to find the probability that \( z \) is between 0 and 1.62, i.e., \( P(0 \leq z \leq 1.62) \). This is the area under the standard normal curve between these two points.
03
Use the Z-table
Consult a Z-table to find the values associated with \( z = 1.62 \) and \( z = 0 \). The Z-table provides the cumulative probability from the far left up to a given \( z \) value.
04
Find Probability for \( z = 1.62 \)
Look up the Z-table for the value of \( z = 1.62 \). The table shows that \( P(Z \leq 1.62) \approx 0.9474 \), meaning about 94.74% of the data lies below 1.62.
05
Find Probability for \( z = 0 \)
For \( z = 0 \), the standard normal distribution is symmetric around the mean, thus \( P(Z \leq 0) = 0.5 \) or 50%.
06
Calculate the Desired Probability
Subtract the probability found for \( z = 0 \) from that of \( z = 1.62 \): \( P(0 \leq z \leq 1.62) = P(Z \leq 1.62) - P(Z \leq 0) = 0.9474 - 0.5 = 0.4474 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Standard Deviation
Standard deviation is a key concept in statistics that measures how much the values in a data set deviate from the mean of that set. In simpler terms, it tells us how spread out the data is. In the context of a standard normal distribution, the standard deviation is always 1. This is because the standard normal distribution, also known as the Z-distribution, has been standardized.
This means that the original data has been transformed in such a way that the average, or mean, is 0 and the spread of the data, or standard deviation, is 1. These transformations allow us to use the Z-table effectively.
This means that the original data has been transformed in such a way that the average, or mean, is 0 and the spread of the data, or standard deviation, is 1. These transformations allow us to use the Z-table effectively.
- A lower standard deviation means the data is closer to the mean.
- A higher standard deviation indicates a wider spread of data points.
Exploring Probability in Statistics
Probability is a measure of the likelihood that a specific event will occur. In the realm of normal distributions, we often discuss probabilities in terms of areas under the curve.
For a standard normal distribution, this area represents the probability that a value, or random variable, falls within a certain interval. When we are calculating probabilities like in the exercise above, we use these intervals to express likelihoods.
For a standard normal distribution, this area represents the probability that a value, or random variable, falls within a certain interval. When we are calculating probabilities like in the exercise above, we use these intervals to express likelihoods.
- Probability values range from 0 to 1.
- An area under the curve approaching 1 signifies a higher probability.
- In our example, a probability of 0.4474 means there is a 44.74% chance that the random variable falls between the two Z-values.
Decoding the Z-table
The Z-table, also known as the standard normal table, is a crucial tool that lists Z-scores alongside their cumulative probabilities. This table helps us quickly find how much of the data falls below a certain Z-score in a standard normal distribution.
To use a Z-table, simply locate the row that corresponds to the first decimal of the Z-score and the column that represents the second decimal. You then find where they intersect to get the probability.
To use a Z-table, simply locate the row that corresponds to the first decimal of the Z-score and the column that represents the second decimal. You then find where they intersect to get the probability.
- The values represent cumulative probabilities, including all probabilities at and below a given Z-score.
- In practice, for a \( z = 1.62 \), the probability \( P(Z \leq 1.62) \) is approximately 0.9474, meaning 94.74% of values fall below this Z-score.
- Similarly, \( P(Z \leq 0) \), which corresponds to the mean, is always 0.5 or 50%.