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Let \(z\) be a random variable with a standard normal distribution. Find the indicated probability, and shade the corresponding area under the standard normal curve. $$ P(z \leq-0.13) $$

Short Answer

Expert verified
The probability is approximately 0.4483.

Step by step solution

01

Understand the Standard Normal Distribution

The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. The values of the random variable "z" follow this distribution.
02

Identify the Cumulative Probability

The problem asks for the probability that the standard normal variable "z" is less than or equal to -0.13. This corresponds to finding the cumulative probability up to z = -0.13.
03

Use the Z-Table

To find the probability, use the standard normal (z) table, which shows cumulative probabilities. Locate the row for z = -0.1 and the column for 0.03 to find the cumulative probability for z = -0.13.
04

Find the Specific Probability

From the z-table, the value at the intersection of the -0.1 row and the 0.03 column is approximately 0.4483. This indicates that the probability of z being less than or equal to -0.13 is 0.4483.
05

Shade the Corresponding Area in the Standard Normal Curve

On a standard normal distribution curve, shade the area to the left of z = -0.13. This shaded region represents the probability that z is less than or equal to -0.13.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cumulative Probability
In the realm of statistics, cumulative probability is a vital concept when working with distributions like the standard normal distribution. Cumulative probability refers to the probability that a random variable is less than or equal to a particular value. It provides us an accumulated sum of probabilities up to that point. This means if you're asked to find the cumulative probability for a value of \(z = -0.13\), you’ll be calculating the probability of the variable being less than or equal to this value.

Understanding cumulative probability is crucial because it helps answer questions about how likely it is for a variable to fall within a certain range. In graphical terms, on a standard normal distribution curve, this is the area under the curve to the left of your specified value.
For instance, if you are asked to find \(P(z \leq -0.13)\), you are essentially shading the area from negative infinity up to \(-0.13\) on the curve. This shaded portion represents the cumulative probability.
Z-Table
A Z-table, also known as the standard normal table, is an essential tool used to find cumulative probabilities associated with standard normal distribution variables. It provides a straightforward way to determine the likelihood of a random variable falling below a particular z-score.

The table displays cumulative probabilities for different z-values, allowing you to look up these values quickly. To use the table, you locate the appropriate row and column intersection. For example, with a z-score of \(-0.13\), you would find the row corresponding to \(-0.1\) and then the column that represents \(0.03\) to precisely capture the value \(-0.13\).
  • The Z-table is arranged in a structured format where rows represent the integer and first decimal place (e.g., \(-0.1\)) of z-scores.
  • Columns represent the hundredths decimal places (e.g., the column for \(0.03\)).
This table is an invaluable aid when manually calculating probabilities in tests or assignments, making the process less cumbersome.
Probability Calculation
Once you've understood the use of cumulative probability and how to read a Z-table, calculating the probability for a standard normal distribution variable becomes a straightforward task. The solution requires a series of simple steps to ensure accuracy.

After identifying the necessary cumulative probability (as done previously), locate it on the Z-table. For \(z = -0.13\), the probability can be found where the \(-0.1\) row meets the \(0.03\) column. In our example, this intersection gives a value of approximately 0.4483, indicating that there is a 44.83% chance that a random variable under this distribution will be less than \(-0.13\).
  • This value directly translates to the shaded area under the standard normal curve.
  • It's crucial to practice looking up values in the Z-table as proficiency with it aids in quick calculations during exams.
Grasping these steps equips students with the capability to tackle similar probability queries with ease.

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Most popular questions from this chapter

A person's blood glucose level and diabetes are closely related. Let \(x\) be a random variable measured in milligrams of glucose per deciliter (1/10 of a liter) of blood. After a 12 -hour fast, the random variable \(x\) will have a distribution that is approximately normal with mean \(\mu=85\) and standard deviation \(\sigma=25\) (Source: Diagnostic Tests with Nursing Implications, edited by \(S .\) Loeb, Springhouse Press). Note: After 50 years of age, both the mean and standard deviation tend to increase. What is the probability that, for an adult (under 50 years old) after a 12 -hour fast, (a) \(x\) is more than 60 ? (b) \(x\) is less than \(110 ?\) (c) \(x\) is between 60 and 110? (d) \(x\) is greater than 140 (borderline diabetes starts at 140\() ?\)

Let \(z\) be a random variable with a standard normal distribution. Find the indicated probability, and shade the corresponding area under the standard normal curve. $$ P(-2.37 \leq z \leq 0) $$

Do you take the free samples offered in supermarkets? About \(60 \%\) of all customers will take free samples. Furthermore, of those who take the free samples, about \(37 \%\) will buy what they have sampled. (See reference in Problem 8.) Suppose you set up a counter in a supermarket offering free samples of a new product. The day you are offering free samples, 317 customers pass by your counter. (a) What is the probability that more than 180 take your free sample? (b) What is the probability that fewer than 200 take your free sample? (c) What is the probability that a customer takes a free sample and buys the product? Hint: Use the multiplication rule for dependent events. Notice that we are given the conditional probability \(P(\) buy \(\mid\) sample \()=0.37\), while \(P(\) sample \()=0.60\) (d) What is the probability that between 60 and 80 customers will take the free sample and buy the product? Hint: Use the probability of success calculated in part \((\mathrm{c})\).

Sketch the areas under the standard normal curve over the indicated intervals, and find the specified areas. Between \(z=-1.98\) and \(z=-0.03\)

Do you try to pad an insurance claim to cover your deductible? About \(40 \%\) of all U.S. adults will try to pad their insurance claims! (Source: Are You Normal?, by Bernice Kanner, St. Martin's Press.) Suppose that you are the director of an insurance adjustment office. Your office has just received 128 insurance claims to be processed in the next few days. What is the probability that (a) half or more of the claims have been padded? (b) fewer than 45 of the claims have been padded? (c) from 40 to 64 of the claims have been padded? (d) more than 80 of the claims have not been padded?

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