/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Let \(z\) be a random variable w... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(z\) be a random variable with a standard normal distribution. Find the indicated probability, and shade the corresponding area under the standard normal curve. $$ P(z \leq 0) $$

Short Answer

Expert verified
The probability \( P(z \leq 0) \) is 0.5.

Step by step solution

01

Understand the Standard Normal Distribution

In a standard normal distribution, the random variable \( z \) follows a normal distribution with a mean of 0 and a standard deviation of 1. Therefore, the probability is calculated over the range of \( z \) values on this curve.
02

General Rule for Symmetrical Distribution

In a standard normal distribution, the mean divides the distribution into two symmetrical halves. Thus, the probability for any value of \( z \) that is less than the mean (which is 0 in a standard normal distribution) is equal to 0.5.
03

Use the Properties of the Cumulative Distribution Function (CDF)

The cumulative distribution function (CDF) for the standard normal distribution represents the probability that a random variable \( z \) takes on a value less than or equal to \( x \). For a mean of 0 in a standard normal distribution, \( P(z \leq 0) \) is the probability at the mean, which is always 0.5.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cumulative Distribution Function
The cumulative distribution function, often abbreviated as CDF, is a critical concept in understanding the behavior of probability distributions. It provides the probability that a random variable takes on a value less than or equal to a specific point. Simply put, the CDF accumulates probabilities up to a certain value, F(x) = P(X≤x).
For the standard normal distribution, where the random variable is denoted by \( z \), the CDF is an essential tool to find probabilities associated with the normal curve. Since this curve is symmetrical about its mean of 0, the cumulative distribution function plays a pivotal role in probabilistic analysis.
Consider the problem \( P(z \leq 0) \). To solve this using the CDF, you assess the probability of a standard normal variable being less than or equal to its mean. For standard normal, this probability is exactly 0.5. This is because, at the mean, the CDF covers half the area under the curve on the left side.
Mean of a Distribution
The mean of a distribution, particularly in a standard normal distribution, has a vital role. It is the average of all data points, a central value that divides the data into two equal halves. In mathematical terms, the mean is denoted by \( \mu \). In a standard normal distribution, the mean \( \mu \) is conveniently set at 0.
This symmetrical nature of the standard normal distribution around its mean is significant. Since it is centered at zero and equally spaced, it simplifies the calculation of probabilities for \( z \) values. Here, the mean implies that half of the data lies below zero and half above zero.
When you calculate \( P(z \leq 0) \), you leverage the mean’s central position. Knowing that half the data is to the left of 0, this equates to a probability of 0.5 for \( z \leq 0 \). This property is crucial in probabilistic and statistical calculations involving the standard normal distribution.
Random Variable
A random variable is a fundamental concept in probability and statistics. It represents a variable whose possible values are drawn from a random process. Random variables can be discrete or continuous, depending on whether they take on isolated values or range over a continuum.
In a standard normal distribution, the random variable \( z \) is continuous. This means it can take any real value, although it is most likely closer to its mean. The distribution is defined by its mean (0) and standard deviation (1).
Understanding the behavior of this random variable is essential when determining probabilities. For example, when you see \( P(z \leq 0) \), you're seeing the probability that \( z \) falls at or below 0. Being a central part of probability theory, random variables like \( z \) enable the calculation of probabilities and the application of distribution functions like the CDF.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the \(z\) value described and sketch the area described. Find \(z\) such that \(5 \%\) of the standard normal curve lies to the right of \(z\).

Find the \(z\) value described and sketch the area described. Find \(z\) such that \(97.5 \%\) of the standard normal curve lies to the left of \(z\)

The college physical education department offered an advanced first aid course last semester. The scores on the comprehensive final exam were normally distributed, and the \(z\) scores for some of the students are shown below: $$ \begin{array}{lcl} \text { Robert, } 1.10 & \text { Juan, } 1.70 & \text { Susan, }-2.00 \\ \text { Joel, } 0.00 & \text { Jan, }-0.80 & \text { Linda, } 1.60 \end{array} $$ (a) Which of these students scored above the mean? (b) Which of these students scored on the mean? (c) Which of these students scored below the mean? (d) If the mean score was \(\mu=150\) with standard deviation \(\sigma=20\), what was the final exam score for each student?

Coal is carried from a mine in West Virginia to a power plant in New York in hopper cars on a long train. The automatic hopper car loader is set to put 75 tons of coal into each car. The actual weights of coal loaded into each car are normally distributed, with mean \(\mu=75\) tons and standard deviation \(\sigma=0.8\) ton. (a) What is the probability that one car chosen at random will have less than \(74.5\) tons of coal? (b) What is the probability that 20 cars chosen at random will have a mean load weight \(\bar{x}\) of less than \(74.5\) tons of coal? (c) Suppose the weight of coal in one car was less than \(74.5\) tons. Would that fact make you suspect that the loader had slipped out of adjustment? Suppose the weight of coal in 20 cars selected at random had an average \(\bar{x}\) of less than \(74.5\) tons. Would that fact make you suspect that the loader had slipped out of adjustment? Why?

Assuming that the heights of college women are normally distributed with mean 65 inches and standard deviation \(2.5\) inches (based on information from Statistical Abstract of the United States, 112 th Edition), answer the following questions. Hint: Use Problems 5 and 6 and Figure \(6-3\). (a) What percentage of women are taller than 65 inches? (b) What percentage of women are shorter than 65 inches? (c) What percentage of women are between \(62.5\) inches and \(67.5\) inches? (d) What percentage of women are between 60 inches and 70 inches?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.