/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Assume that \(x\) has a normal d... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Assume that \(x\) has a normal distribution with the specified mean and standard deviation. Find the indicated probabilities. $$ P(40 \leq x \leq 47) ; \mu=50 ; \sigma=15 $$

Short Answer

Expert verified
The probability that 40 ≤ x ≤ 47 is approximately 0.1693.

Step by step solution

01

Understand the Problem

We need to find the probability that a normally distributed random variable, \(x\), with a mean \(\mu = 50\) and a standard deviation \(\sigma = 15\) falls between 40 and 47, inclusive.
02

Standardize the Values

To use standard normal distribution tables, we need to convert the given values to standard scores, or \(z\)-scores, using the formula: \(z = \frac{x - \mu}{\sigma}\).Calculate \(z\) for \(x = 40\): \(z_1 = \frac{40 - 50}{15} = -0.67\).Calculate \(z\) for \(x = 47\): \(z_2 = \frac{47 - 50}{15} = -0.20\).
03

Lookup \(z\)-scores in Standard Normal Distribution Table

Using a standard normal distribution table (or a calculator), find the probability corresponding to \(z_1 = -0.67\) and \(z_2 = -0.20\).For \(z_1 = -0.67\), the probability \(P(Z < -0.67) \approx 0.2514\).For \(z_2 = -0.20\), the probability \(P(Z < -0.20) \approx 0.4207\).
04

Calculate the Probability Between the Two \(z\)-scores

The probability that \(x\) falls between 40 and 47 is \(P(40 \leq x \leq 47) = P(z_2) - P(z_1) = 0.4207 - 0.2514\).
05

Compute the Final Probability

Subtract the probabilities to find the answer: \(P(40 \leq x \leq 47) = 0.4207 - 0.2514 = 0.1693\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

z-scores
When dealing with normal distributions, you'll often need to convert your raw data points into z-scores. A z-score represents how many standard deviations an element is from the mean. The formula for finding a z-score is given by \(z = \frac{x - \mu}{\sigma}\), where \(x\) is the data point, \(\mu\) is the mean of the dataset, and \(\sigma\) is the standard deviation.

This transformation helps us understand where our particular data point fits in a normal distribution. Once transformed into z-scores, you can use these values to look up probabilities in a standard normal distribution table. This table shows the area under the curve to the left of a particular z-score, giving the likelihood that the value of a random variable is less than your specified value. For instance, in solving the given exercise, converting our limits of 40 and 47 into z-scores helps us identify segments of the data's distribution.

In practice, these z-score calculations allow researchers, scientists, and statisticians to initially assess where data points stand in relation to the rest of a dataset or in comparison to a theoretical population. It offers a universal way to compare and interpret data.
probability
Probability allows us to quantify the likelihood of an event happening. In the context of a normal distribution, when you're asked for a probability that a certain value falls between two points, you're essentially looking for the area under the distribution curve that lies between those values.

In the given problem, we calculated the probability that the variable \(x\) falls between 40 and 47 for a normally distributed data set with a mean of 50 and a standard deviation of 15. We achieved this by converting these values into their corresponding z-scores and using the standard normal distribution table to find the area under the curve.

The beauty of using probability with normal distributions is its standardization. By converting any normal distribution into a standard form using z-scores, you only need a single standard normal distribution table to find probabilities. This simplifies the process significantly, making it a critical tool for statistical analysis.
standard deviation
Standard deviation is a measure of how spread out the numbers in a data set are around the mean. When we say that a dataset has a larger standard deviation, it means the data is more spread out, and when it's smaller, the data points tend to be closer to the mean.

In our exercise, the standard deviation was \(\sigma = 15\). This tells us about the variability of our normal distribution. When calculating probabilities or converting raw scores to standardized scores, this value helps adjust for the spread of data points.

Understanding standard deviation is fundamental because it provides insight into the reliability and precision of the mean as the central value. A small standard deviation indicates that observations are closely clustered around the mean, suggesting consistent data. Conversely, a larger standard deviation indicates observations are more spread out, which can suggest more variability in the data.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Most exhibition shows open in the morning and close in the late evening. A study of Saturday arrival times showed that the average arrival time was 3 hours and 48 minutes after the doors opened, and the standard deviation was estimated at about 52 minutes. Assume that the arrival times follow a normal distribution. (a) At what time after the doors open will \(90 \%\) of the people who are coming to the Saturday show have arrived? (b) At what time after the doors open will only \(15 \%\) of the people who are coming to the Saturday show have arrived? (c) Do you think the probability distribution of arrival times for Friday might be different from the distribution of arrival times for Saturday? Explain.

The heights of 18 -year-old men are approximately normally distributed, with mean 68 inches and standard deviation 3 inches (based on information from Statistical Abstract of the United States, 112 th Edition). (a) What is the probability that an 18 -year-old man selected at random is between 67 and 69 inches tall? (b) If a random sample of nine 18 -year-old men is selected, what is the probability that the mean height \(\bar{x}\) is between 67 and 69 inches? (c) Compare your answers to parts (a) and (b). Is the probability in part (b) much higher? Why would you expect this?

More than a decade ago, high levels of lead in the blood put \(88 \%\) of children at risk. A concerted effort was made to remove lead from the environment. Now, according to the Third National Health and Nutrition Examination Survey (NHANES III) conducted by the Centers for Disease Control, only \(9 \%\) of children in the United States are at risk of high blood-lead levels. (a) In a random sample of 200 children taken more than a decade ago, what is the probability that 50 or more had high blood-lead levels? (b) In a random sample of 200 children taken now, what is the probability that 50 or more have high blood-lead levels?

Suppose we have a binomial experiment with \(n=40\) trials and probability of success \(p=0.85\) (a) Is it appropriate to use a normal approximation to this binomial distribution? Why? (b) Compute \(\mu\) and \(\sigma\) of the approximating normal distribution. (c) Use a continuity correction factor to convert the statement \(r<30\) successes to a statement about the corresponding normal variable \(x\). (d) Estimate \(P(r<30)\). (e) Is it unusual for a binomial experiment with 40 trials and probability of success \(0.85\) to have fewer than 30 successes? Explain.

Find the \(z\) value described and sketch the area described. Find \(z\) such that \(5.2 \%\) of the standard normal curve lies to the left of \(z\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.