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Conditional Probability: Blood Supply Only about \(70 \%\) of all donated human blood can be used in hospitals. The remaining \(30 \%\) cannot be used because of various infections in the blood. Suppose a blood bank has 10 newly donated pints of blood. Let \(r\) be a binomial random variable that represents the number of "good" pints that can be used. (a) Based on questionnaires completed by the donors, it is believed that at least 6 of the 10 pints are usable. What is the probability that at least 8 of the pints are usable, given this belief is true? Compute \(P(8 \leq r \mid 6 \leq r)\). (b) Assuming the belief that at least 6 of the pints are usable is true, what is the probability that all 10 pints can be used? Compute \(P(r=10 \mid 6 \leq r)\).

Short Answer

Expert verified
(a) \( P(8 \leq r \mid 6 \leq r) \approx 0.379 \). (b) \( P(r = 10 \mid 6 \leq r) \approx 0.0332 \).

Step by step solution

01

Calculate the Probability of Usable Pints

We know that for a donated pint of blood, there is a probability of 0.7 that it is usable. Hence, we can use a binomial distribution for this scenario, where the probability of success is 0.7, and the number of trials (pints of blood) is 10.
02

Define the Conditional Probability

We need to find the conditional probabilities for certain events given that at least 6 pints are usable. In probability terms, we want to calculate \( P(8 \leq r \mid 6 \leq r) \) and \( P(r = 10 \mid 6 \leq r) \). According to conditional probability formulas, \( P(A \mid B) = \frac{P(A \cap B)}{P(B)} \).
03

Calculate \( P(6 \leq r) \)

Calculate the probability that at least 6 pints are usable. This is given by the sum of probabilities from 6 to 10 usable pints:\[P(6 \leq r) = P(r = 6) + P(r = 7) + P(r = 8) + P(r = 9) + P(r = 10)\]Use the binomial probability formula: \[P(r = k) = \binom{n}{k} p^k (1-p)^{n-k}\]Plug in values for each \(k\).
04

Calculate \( P(8 \leq r) \)

Calculate the probability that at least 8 pints are usable:\[P(8 \leq r) = P(r = 8) + P(r = 9) + P(r = 10)\]Again, use the binomial probability formula for each value of \(k\), plugging in the respective numbers.
05

Find \( P(8 \leq r \mid 6 \leq r) \)

Using the conditional probability formula, calculate:\[P(8 \leq r \mid 6 \leq r) = \frac{P(8 \leq r \cap 6 \leq r)}{P(6 \leq r)} = \frac{P(8 \leq r)}{P(6 \leq r)}\]Substitute the probabilities found in steps 3 and 4.
06

Calculate \( P(r = 10 \mid 6 \leq r) \)

To find the probability that all 10 pints are usable given that at least 6 are usable, use:\[P(r = 10 \mid 6 \leq r) = \frac{P(r = 10 \cap 6 \leq r)}{P(6 \leq r)} = \frac{P(r = 10)}{P(6 \leq r)}\]Substitute the values calculated previously for \(P(r = 10)\) and \(P(6 \leq r)\).
07

Example Calculation Result

Using a calculator or software to solve the binomial probabilities:- \(P(6 \leq r) \approx 0.8497\)- \(P(8 \leq r) \approx 0.3222\)- \(P(8 \leq r \mid 6 \leq r) = \frac{0.3222}{0.8497} \approx 0.379\)- \(P(r = 10) \approx 0.0282\)- \(P(r = 10 \mid 6 \leq r) = \frac{0.0282}{0.8497} \approx 0.0332\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
A binomial distribution is a statistical method used to model situations where there are two possible outcomes: success or failure. It is particularly useful when dealing with a fixed number of independent trials and a constant probability of success in each trial. In the context of our blood supply problem, each pint of blood donated can either be usable or not usable.

Here, we have 10 trials (10 pints), and the probability of success, which means a pint being usable, is 0.7 or 70%. This scenario perfectly fits the binomial distribution because each pint of blood is an independent trial, with the outcome not affecting the others.

The binomial distribution is governed by a specific formula: \[P(r = k) = \binom{n}{k} p^k (1-p)^{n-k}\] where:
  • \(n\) is the total number of trials,
  • \(k\) is the number of successful trials you are counting,
  • \(p\) is the probability of success on each trial.
This formula helps calculate the probability of achieving exactly \(k\) usable pints.
Probability of Success
Probability of success, frequently denoted by \(p\), refers to the chance that our event of interest will occur in any single trial. In the case of the blood bank problem, the probability of a pint of blood being usable is 0.7. This number was likely estimated based on prior data or research regarding blood donations.

A key point to remember when working with probabilities is that \(p\) + \(q\) = 1, where \(q\) is the probability of failure. So, with a probability of success of 0.7, the probability of failure \(q\), or a pint not being usable, is 0.3.

The success probability is crucial for calculating results in a binomial setting, as it directly influences how likely or unlikely certain outcomes are. As you'll see in our exercise, understanding and using the probability of success enables you to compute the probabilities for events like having exactly 8 usable pints or all 10 pints being usable.
Random Variable
In statistics, a random variable is a numerical representation of the outcomes of a random phenomenon. It is a key component when dealing with probability distributions as it helps in interpreting the results. In our blood donation example, the random variable \(r\) represents the number of usable pints of blood out of the 10 donated pints.

Random variables can be discrete or continuous. In this particular case, \(r\) is a discrete random variable, meaning it takes on specific, countable values - such as 6, 7, 8, 9, or 10 - rather than any value in a range.

Understanding \(r\) as a random variable enables you to apply formulas like the binomial probability formula to calculate the likelihood of different scenarios occurring. This turns complex real-world problems into manageable mathematical challenges.
Conditional Probability Formula
Conditional probability is the probability of one event occurring with some relationship to one or more other events. It is expressed by \(P(A \mid B)\), which means the probability of event \(A\) occurring given that \(B\) has occurred.

In the context of our exercise, we want to calculate probabilities such as \(P(8 \leq r \mid 6 \leq r)\) and \(P(r = 10 \mid 6 \leq r)\). These represent the likelihood of 8 or more pints being usable if we know that at least 6 are, and the probability that all 10 pints are usable under the same condition.

The formula for conditional probability is: \[P(A \mid B) = \frac{P(A \cap B)}{P(B)}\] Here, \(P(A \cap B)\) is the probability that both events \(A\) and \(B\) happen, while \(P(B)\) is the probability that event \(B\) happens. Understanding and applying this formula helps solve various problems by narrowing down the focus to outcomes given specific conditions or preliminary events.

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Most popular questions from this chapter

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