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Law Enforcement: Burglaries The Honolulu Advertiser stated that in Honolulu there was an average of 661 burglaries per 100,000 households in a given year. In the Kohola Drive neighborhood there are 316 homes. Let \(r=\) number of these homes that will be burglarized in a year. (a) Explain why the Poisson approximation to the binomial would be a good choice for the random variable \(r\). What is \(n\) ? What is \(p ?\) What is \(\lambda\) to the nearest tenth? (b) What is the probability that there will be no burglaries this year in the Kohola Drive neighborhood? (c) What is the probability that there will be no more than one burglary in the Kohola Drive neighborhood? (d) What is the probability that there will be two or more burglaries in the Kohola Drive neighborhood?

Short Answer

Expert verified
(a) Poisson is appropriate; \(n=316\), \(p=0.00661\), \(\lambda=2.1\). (b) \(0.1225\). (c) \(0.3797\). (d) \(0.6203\).

Step by step solution

01

Understanding the problem

We're instructed to use the Poisson approximation, which is suitable when the number of trials is large and the probability of success is small. Here, we need to determine the probability of a number of burglaries occurring in Kohola Drive.
02

Define parameters for approximation

We define the parameters: the number of trials, \(n\), which is the number of homes, 316 in this case. The probability of a burglary in a single home is \(p = \frac{661}{100,000}\). The mean of the distribution \(\lambda = np\) is calculated to use in the Poisson approximation.
03

Calculating \(\lambda\)

First, calculate \(p = \frac{661}{100000} \approx 0.00661\). Now calculate \(\lambda\) as \(\lambda = 316 \times 0.00661 \approx 2.1\). Thus, \(\lambda = 2.1\) to the nearest tenth.
04

Probability of no burglaries (r=0)

Using the Poisson formula \(P(r; \lambda) = \frac{e^{-\lambda} \lambda^r}{r!}\), we calculate \(P(r=0; 2.1) = \frac{e^{-2.1} \times 2.1^0}{0!} = e^{-2.1}\). Compute \(e^{-2.1} \approx 0.1225\).
05

Probability of no more than one burglary

For \(P(r \leq 1)\), calculate \(P(r=0)\) and \(P(r=1)\). \(P(r=1; 2.1) = \frac{e^{-2.1} \times 2.1^1}{1!} = 2.1 \times e^{-2.1}\). In step 4, \(P(r=0)\approx 0.1225\) and \(P(r=1)\approx 0.2572\). Sum these: \(0.1225 + 0.2572 \approx 0.3797\).
06

Probability of two or more burglaries

The probability of two or more burglaries is the complement of having 0 or 1 burglary. Thus, \(P(r \geq 2) = 1 - P(r \leq 1)\). With \(P(r \leq 1)\approx 0.3797\), then \(P(r \geq 2) \approx 1 - 0.3797 = 0.6203\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
The binomial distribution is a discrete probability distribution that is used to model the number of successes in a fixed number of independent trials, where each trial has two possible outcomes: success or failure. In a binomial distribution, the trials are identical, and each has the same probability of success, denoted by \( p \). The number of trials is denoted by \( n \), and the random variable \( X \) represents the number of successes in these \( n \) trials.
  • Formula: The probability of exactly \( r \) successes in \( n \) trials is given by the formula:
\[P(X = r) = \binom{n}{r} p^r (1-p)^{n-r}\]
  • Parameters: It involves two parameters: \( n \) (the number of trials) and \( p \) (probability of success on a single trial).
  • Characteristics: The trials are independent. The probability of success stays constant for each trial.

In the context of the burglaries problem, if we were to use a binomial distribution, each home represents a trial, and a burglary at a home represents a success. However, with a large number of homes and a relatively small probability of a burglary, the Poisson approximation offers a simplified and more practical approach.
Probability Calculation
Probability calculation is the process of determining how likely an event is to occur. It is a fundamental concept in statistics and involves the use of formulas and equations to derive probabilities. Probability is expressed as a number between 0 and 1, where 0 indicates impossibility, and 1 indicates certainty.
  • Basic Formula: Probability of an event \( A \) is calculated as:
\[P(A) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}\]
For the problem of burglaries, calculating the probability involves determining the likelihood of a specific number of burglaries happening in the Kohola Drive neighborhood.
  • No Burglaries: For zero burglaries, we use the Poisson formula with \( \lambda = 2.1 \), leading us to \( P(r = 0) = e^{-2.1} \approx 0.1225 \).
  • No More Than One Burglary: The sum of probabilities for zero \( P(r = 0) \) and one burglary \( P(r = 1) \), gives us \( P(r \leq 1) \approx 0.3797 \).
  • Two or More Burglaries: This probability is the complement of \( P(r \leq 1) \), calculated as \( 1 - 0.3797 \approx 0.6203 \).

By understanding these calculations, students can gain insight into how probabilities build upon each other to describe the likelihood of various outcomes.
Probability Distribution
A probability distribution is a statistical function that describes all the possible values and likelihoods that a random variable can take within a given range. Two common types of probability distributions are the binomial distribution and the Poisson distribution, each serving different roles based on the characteristics of the data.
  • Discrete vs. Continuous: Probability distributions can be discrete (taking on a countable number of possible values) or continuous (where the variable can take any value within a range).
  • Poisson Distribution: This is particularly useful for modeling the number of events that occur independently within a fixed interval of time or space. It is used as an approximation of the binomial distribution when \( n \) is large and \( p \) is small.
  • Characteristic Feature: In Poisson, the mean \( \lambda \) also serves as the variance, depicting how spread out values are likely to be around that mean.

In the given problem, the Poisson distribution is applicable because it efficiently calculates the probabilities of burglary occurrences within a large number of homes. With \( \lambda = np \), where \( n = 316 \) and \( p \approx 0.00661 \), it helps predict how many burglaries might take place, streamlining the computation while maintaining accuracy.

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Most popular questions from this chapter

Statistical Literacy When using the Poisson distribution, which parameter of the distribution is used in probability computations? What is the symbol used for this parameter?

Poisson Approximation to the Binomial: Comparisons (a) For \(n=100, p=0.02\), and \(r=2\), compute \(P(r)\) using the formula for the binomial distribution and your calculator: $$ P(r)=C_{n, t} p^{r}(1-p)^{n-r} $$ (b) For \(n=100, p=0.02\), and \(r=2\), estimate \(P(r)\) using the Poisson approximation to the binomial. (c) Compare the results of parts (a) and (b). Does it appear that the Poisson distribution with \(\lambda=n p\) provides a good approximation for \(P(r=2) ?\) (d) Repeat parts (a) to (c) for \(r=3\).

Airlines: Lost Bags USA Today reported that for all airlines, the number of lost bags was May: \(6.02\) per 1000 passengers December: \(12.78\) per 1000 passengers Note: A passenger could lose more than one bag. (a) Let \(r=\) number of bags lost per 1000 passengers in May. Explain why the Poisson distribution would be a good choice for the random variable \(r\). What is \(\lambda\) to the nearest tenth? (b) In the month of May, what is the probability that out of 1000 passengers, no bags are lost? that 3 or more bags are lost? that 6 or more bags are lost? (c) In the month of December, what is the probability that out of 1000 passengers, no bags are lost? that 6 or more bags are lost? that 12 or more bags are lost? (Round \(\lambda\) to the nearest whole number.)

Rude Drivers: Tailgating Do you tailgate the car in front of you? About \(35 \%\) of all drivers will tailgate before passing, thinking they can make the car in front of them go faster (Source: Bernice Kanner, Are You Normal?, St. Martin's Press). Suppose that you are driving a considerable distance on a two-lane highway and are passed by 12 vehicles. (a) Let \(r\) be the number of vehicles that tailgate before passing. Make a histogram showing the probability distribution of \(r\) for \(r=0\) through \(r=12\). (b) Compute the expected number of vehicles out of 12 that will tailgate. (c) Compute the standard deviation of this distribution.

Law Enforcement: Property Crime Does crime pay? The FBI Standard Survey of Crimes shows that for about \(80 \%\) of all property crimes (burglary, larceny, car theft, etc.), the criminals are never found and the case is never solved (Source: True Odds, by James Walsh, Merrit Publishing). Suppose a neighborhood district in a large city suffers repeated property crimes, not always perpetuated by the same criminals. The police are investigating six property crime cases in this district. (a) What is the probability that none of the crimes will ever be solved? (b) What is the probability that at least one crime will be solved? (c) What is the expected number of crimes that will be solved? What is the standard deviation? (d) Quota Problem How many property crimes \(n\) must the police investigate before they can be at least \(90 \%\) sure of solving one or more cases?

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