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Sociology: Ethics The one-time fling! Have you ever purchased an article of clothing (dress, sports jacket, etc.), worn the item once to a party, and then returned the purchase? This is called a one-time fling. About \(10 \%\) of all adults deliberately do a one-time fling and feel no guilt about it (Source: Are You Normal?, by Bernice Kanner, St. Martin's Press). In a group of seven adult friends, what is the probability that (a) no one has done a one-time fling? (b) at least one person has done a one-time fling? (c) no more than two people have done a one-time fling?

Short Answer

Expert verified
(a) 0.478, (b) 0.522, (c) 0.948

Step by step solution

01

Understand the Problem

We are given that the probability of an adult deliberately doing a one-time fling and feeling no guilt is 10% or 0.10. We need to find the probability of certain numbers of people doing a one-time fling in a group of seven friends.
02

Identify the Distribution

Since we are dealing with a fixed number of trials (7 people) and only two possible outcomes for each trial (either they did or did not do a one-time fling), this problem follows a binomial distribution. Let \( p = 0.10 \) be the probability of success (doing a one-time fling) and \( n = 7 \) be the number of trials (people).
03

Calculate Probability of No One Doing a One-Time Fling

To find the probability that no one has done a one-time fling, we calculate the probability of 0 successes out of 7 using the binomial formula: \[ P(X = 0) = \binom{7}{0} (0.10)^0 (0.90)^7 \]. Calculate this value to get the answer.
04

Probability of At Least One Person Doing a One-Time Fling

The probability of at least one person doing a one-time fling is the complement of the probability of no one doing it. Thus, \( P(\text{at least 1}) = 1 - P(X = 0) \). Substitute the value from Step 3 to find this probability.
05

Calculate Probability of No More Than Two People

To find the probability that no more than two people have done a one-time fling, we need to sum the probabilities of 0, 1, and 2 successes. Use the binomial formula for each: \[ P(X = 1) = \binom{7}{1} (0.10)^1 (0.90)^6 \] and \[ P(X = 2) = \binom{7}{2} (0.10)^2 (0.90)^5 \]. Then calculate \( P(X = 0) + P(X = 1) + P(X = 2) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
When tackling problems involving likelihoods, probability calculations are essential. Probability quantifies the chance of a certain event happening. In the case of our exercise, we want to understand the likelihood of a group of individuals engaging in a one-time fling. The foundation of these calculations is rooted in understanding the possible outcomes and predicting how often a particular outcome occurs.

For example, if we want to find the probability that no one in a group has done a one-time fling, we first determine the probability of a single individual not doing it. If the chance of doing the fling is 0.10, then not doing it is 0.90. Extending this logic to seven people (independent trials), we multiply the probability 0.90 by itself seven times. Thus, the probability of this scenario can be calculated as: \( (0.90)^7 \).
  • Understanding individual probabilities
  • Multiplying them across multiple independent trials
  • Calculating overall probability of an outcome
Binomial Probability Formula
The binomial probability formula is a powerful tool in calculating the probability of a specific number of successes in a series of independent trials. It is used when each trial can only result in a success or a failure (like a yes or no situation). The formula is:\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]where:
  • \( n \) is the total number of trials
  • \( k \) is the number of desired successes
  • \( p \) is the probability of success on a single trial
  • \( 1-p \) (the probability of a failure) raised to the power of the remaining trials (\( n-k \))
In our exercise, calculating the probability that no one or no more than two people engage in a fling uses this binomial formula by substituting the values for events (0, 1, or 2 successes) to find precise probabilities.
Complement Rule
The complement rule is a handy approach when dealing with probability calculations because sometimes it's easier to calculate the probability of the complement of an event and subtract from one. Simply put, the probability of an event not occurring is 1 minus the probability that it does occur.
  • The formula is: \( P( ext{at least one}) = 1 - P( ext{none}) \)
In the one-time fling problem, if we want to know the probability that at least one person has done a one-time fling, we first calculate the probability that no one has done it (which we've done earlier), and then subtract this result from 1. This rule often simplifies numerous probability calculations and is a useful tool in statistical problems like this scenario.
Binomial Trials
Binomial trials are instances of repeated experiments where each trial only results in a success or a failure. The situations where we can use binomial trials have some key characteristics: each trial is independent, the number of trials is fixed, and the probability of success remains constant throughout.

In the current example with the seven adult friends, each person can be considered a separate trial where the individual either did a one-time fling (success) or did not (failure). Binomial trials simplify these types of problems by using systematic calculations to find probabilities for various outcomes (0, 1, or more than 2 engaging in the behavior). Understanding that these trials are grounded in a consistent environment enables us to apply the binomial formula effectively and predict outcomes more reliably.

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Most popular questions from this chapter

Fundraiser: Hiking Club The college hiking club is having a fundraiser to buy new equipment for fall and winter outings. The club is selling Chinese fortune cookies at a price of \(\$ 1\) per cookie. Each cookie contains a piece of paper with a different number written on it. A random drawing will determine which number is the winner of a dinner for two at a local Chinese restaurant. The dinner is valued at \(\$ 35\). Since the fortune cookies were donated to the club, we can ignore the cost of the cookies. The club sold 719 cookies before the drawing. (a) Lisa bought 15 cookies. What is the probability she will win the dinner for two? What is the probability she will not win? (b) Interpretation Lisa's expected earnings can be found by multiplying the value of the dinner by the probability that she will win. What are Lisa's expected earnings? How much did she effectively contribute to the hiking club?

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Marketing: Photograpby Does the kid factor make a difference? If you are talking photography, the answer may be yes! The following table is based on information from American Demographics (Vol. 19, No. 7 ). \begin{tabular}{l|cc} \hline Ages of children in household, years & Under 2 & None under 21 \\ \hline Percent of U.S. households that buy photo gear & \(80 \% 6\) & \(50 \%\) \\\ \hline \end{tabular} Let us say you are a market research person who interviews a random sample of 10 households. (a) Suppose you interview 10 households with children under the age of 2 years. Let \(r\) represent the number of such households that buy photo gear. Make a histogram showing the probability distribution of \(r\) for \(r=0\) through \(r=10 .\) Find the mean and standard deviation of this probability distribution. (b) Suppose that the 10 households are chosen to have no children under 21 years old. Let \(r\) represent the number of such households that buy photo gear. Make a histogram showing the probability distribution of \(r\) for \(r=0\) through \(r=10 .\) Find the mean and standard deviation of this probability distribution. (c) Interpretation Compare the distributions in parts (a) and (b). You are designing TV ads to sell photo gear. Could you justify featuring ads of parents taking pictures of toddlers? Explain your answer.

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