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You roll two fair dice, a green one and a red one. (a) Are the outcomes on the dice independent? (b) Find \(P(5\) on green die and 3 on red die). (c) Find \(P(3\) on green die and 5 on red die). (d) Find \(P((5\) on green die and 3 on red die) or \((3\) on green die and 5 on red die)).

Short Answer

Expert verified
(a) Yes, the outcomes are independent. (b) \(\frac{1}{36}\). (c) \(\frac{1}{36}\). (d) \(\frac{1}{18}\).

Step by step solution

01

Define Independence of Dice Outcomes

Two events are independent if the occurrence of one event does not affect the occurrence of the other. When two fair dice are rolled, the result of one die does not influence the result of the other. Thus, the outcomes on the green and red dice are independent.
02

Probability of 5 on Green Die and 3 on Red Die

The probability of rolling a 5 on a six-sided die is \(\frac{1}{6}\), and the probability of rolling a 3 on another six-sided die is \(\frac{1}{6}\). Since the two rolls are independent, the probability of both events occurring together is the product of their individual probabilities: \[ P(5\text{ on green and } 3\text{ on red}) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} \]
03

Probability of 3 on Green Die and 5 on Red Die

Similarly, the probability of rolling a 3 on the green die is \(\frac{1}{6}\) and a 5 on the red die is \(\frac{1}{6}\). Hence, the probability of these two independent events occurring together is:\[ P(3\text{ on green and } 5\text{ on red}) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} \]
04

Probability of Either Outcome Occurring

To find the probability of either rolling a 5 on the green die and 3 on the red die or a 3 on the green die and 5 on the red die, we use the addition rule for mutually exclusive events:\[ P((5\text{ on green and } 3\text{ on red}) \text{ or } (3\text{ on green and } 5\text{ on red})) = \frac{1}{36} + \frac{1}{36} = \frac{2}{36} = \frac{1}{18} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
Independent events are a fundamental concept in probability, especially when dealing with multiple random occurrences. When we say two events are independent, we mean that the outcome of one event has no effect on the outcome of the other event. For example, when rolling two fair dice, the numbers shown on the green die have no bearing on what numbers will appear on the red die. This means each die operates independently from the other, without interference.

To determine if events are independent, we can use a simple test. We examine whether the probability of both events happening is equal to the product of their individual probabilities. If:
  • The probability of Event A and Event B happening together is the same as multiplying their individual probabilities, then they are independent:
  • \[P(A \text{ and } B) = P(A) \times P(B)\]
  • For our dice example, rolling a specific number on one die doesn’t change the chances of a particular result on the other.
Understanding independence in events helps solve complex problems in probability with ease.
Combinatorics
Combinatorics is a branch of mathematics that deals with counting, arranging, and analyzing combinations and permutations. It's essential when evaluating probabilities because it helps us calculate how many ways events can occur. For instance, when rolling a pair of dice, combinatorics allows us to discern the different possible results.

In probability, we often ask questions like: how many ways can you roll a sum of 7 with two dice? Here’s where combinatorics shines. We can count all the likely pairs of die results that produce a sum of 7:
  • (1,6), (2,5), (3,4), (4,3), (5,2), and (6,1)
There are 6 combinations, thus illustrating how combinatorics is used to determine outcome frequencies.

Another aspect is arranging items, such as in permutations where order matters. Consider different ways to arrange two events, like getting a 5 on one die and another number on the second dice. By calculating possible combinations, combinatorics gives us deeper insight into probability outcomes.
Mutually Exclusive Events
Mutually exclusive events refer to scenarios where the occurrence of one event prevents the occurrence of another. In other words, both events cannot happen at the same time. Take, for instance, doing an exercise where two different sums of numbers from rolling two dice are considered.

If you roll the green die to land on a 5 and the red die on a 3, this outcome is exclusive and different from rolling the green die to land on a 3 and the red one on a 5. These two scenarios don’t overlap, making them mutually exclusive.

When dealing with probabilities of mutually exclusive events, the addition rule comes into play. If Event A and Event B cannot occur simultaneously, the probability of either event occurring is the sum of their individual probabilities.
  • So, if either rolling a 5 on green and 3 on red or a 3 on green and 5 on red are our choices:
  • \[P(\text{Event A or Event B}) = P(\text{Event A}) + P(\text{Event B})\]
This clear distinction helps when evaluating any problem where separate outcomes are involved.

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Most popular questions from this chapter

Given \(P(A)=0.7\) and \(P(B)=0.8\) : (a) If \(A\) and \(B\), are independent events, compute \(P(A\) and \(B)\). (b) If \(P(B \mid A)=0.3\), compute \(P(A\) and \(B)\).

Agriculture: Cotton A botanist has developed a new hybrid cotton plant that can withstand insects better than other cotton plants. However, there is some concern about the germination of seeds from the new plant. To estimate the probability that a seed from the new plant will germinate, a random sample of 3000 seeds was planted in warm, moist soil. Of these seeds, 2430 germinated. (a) Use relative frequencies to estimate the probability that a seed will germinate. What is your estimate? (b) Use relative frequencies to estimate the probability that a seed will not germinate. What is your estimate? (c) Either a seed germinates or it does not. What is the sample space in this problem? Do the probabilities assigned to the sample space add up to \(1 ?\) Should they add up to 1 ? Explain. (d) Are the outcomes in the sample space of part (c) equally likely?

Expand Your Knowledge: Odds Against Betting odds are usually stated against the event happening (against winning). The odds against event \(W\) are the ratio \(\frac{P(n o t W)}{P(W)}=\frac{P\left(W^{c}\right)}{P(W)}\). In horse racing, the betting odds are based on the probability that the horse does not win. (a) Show that if we are given the odds against an event \(W\) as \(a: b\), the probability of not \(W\) is \(P\left(W^{c}\right)=\frac{a}{a+b} .\) Hint \(:\) Solve the equation \(\frac{a}{b}=\frac{P\left(W^{c}\right)}{1-P\left(W^{c}\right)}\) for \(P\left(W^{c}\right)\) (b) In a recent Kentucky Derby, the betting odds for the favorite horse, Point Given, were 9 to \(5 .\) Use these odds to compute the probability that Point Given would lose the race. What is the probability that Point Given would win the race? (c) In the same race, the betting odds for the horse Monarchos were 6 to 1 . Use these odds to estimate the probability that Monarchos would lose the race. What is the probability that Monarchos would win the race? (d) Invisible Ink was a long shot, with betting odds of 30 to \(1 .\) Use these odds to estimate the probability that Invisible Ink would lose the race. What is the probability the horse would win the race? For further information on the Kentucky Derby, visit the Brase/Brase statistics site at http://www.cengage .com/statistics/brase and find the link to the Kentucky Derby.

Answer questions true or false and give a brief explanation for each answer. Hint: Review the summary of basic probability rules.If \(A\) and \(B\) are both mutually exclusive and independent, then at least one of \(P(A)\) or \(P(B)\) must be zero.

Suppose two events \(A\) and \(B\) are independent, with \(P(A) \neq 0\) and \(P(B) \neq 0 .\) By working through the following steps, you'll see why two independent events are not mutually exclusive. (a) What formula is used to compute \(P(A\) and \(B) ?\) Is \(P(A\) and \(B) \neq 0 ?\) Explain. (b) Using the information from part (a), can you conclude that events \(A\) and \(B\) are not mutually exclusive?

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