/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Josh and Kendra each calculated ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Josh and Kendra each calculated a \(90 \%\) confidence interval for the difference of means using a Student's \(t\) distribution for random samples of size \(n_{1}=20\) and \(n_{2}=31 .\) Kendra followed the convention of using the smaller sample size to compute d.f. \(=19 .\) Josh used his calculator and Satterthwaite's approximation and obtained d.f. \(\approx 36.3 .\) Which confidence interval is shorter? Which confidence interval is more conservative in the sense that the margin of error is larger?

Short Answer

Expert verified
Josh's confidence interval is shorter; Kendra's is more conservative with a larger margin of error.

Step by step solution

01

Understanding Degrees of Freedom (d.f.)

Josh and Kendra are calculating confidence intervals with different degrees of freedom. Kendra uses d.f. = 19, derived from using the formula for the smallest sample size minus 1, i.e., \(d.f. = n_1 - 1 = 20 - 1 = 19\). On the other hand, Josh uses Satterthwaite's approximation to find \(d.f. \approx 36.3\).
02

Implication of Degrees of Freedom on Confidence Interval

A higher degree of freedom typically results in a narrower t-distribution, which in turn results in a shorter confidence interval. Therefore, with \(d.f. \approx 36.3\), Josh's confidence interval is likely to be shorter compared to Kendra's with \(d.f. = 19\).
03

Margin of Error and Conservativeness

The margin of error is calculated as \(t \times S.E.\) (Standard Error), where \(t\) is the t-score corresponding to the given degrees of freedom and confidence level. The t-score decreases with an increase in the degrees of freedom for the same confidence level. Hence, Kendra's interval with \(d.f. = 19\) will have a larger t-score, resulting in a larger margin of error, making it more conservative.
04

Conclusion

Josh's confidence interval is shorter due to the higher degrees of freedom (\(d.f. \approx 36.3\)), while Kendra's confidence interval is more conservative with a larger margin of error due to a lower degrees of freedom (\(d.f. = 19\)).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
Degrees of Freedom (d.f.) is a fundamental concept in statistics that describes how many values in a calculation can vary freely. It is especially important in the context of hypothesis testing and confidence intervals.
In the example of Josh and Kendra, when you have two samples, the degrees of freedom are typically calculated as the smaller sample size minus one. So for Kendra, who uses the smaller sample size of 20, the degrees of freedom are 19 (20 - 1).
Degrees of freedom impact the shape of the t-distribution. Generally, the greater the degrees of freedom, the more the t-distribution resembles a normal distribution. This is why Josh, who calculates a higher d.f. using Satterthwaite's approximation, ends up with a smaller confidence interval.
Confidence Interval
Confidence intervals are a range of values, derived from sample data, that are likely to contain the population parameter. They are associated with a specific degree of confidence, such as 90%.
In essence, a 90% confidence interval means that if you drew random samples and calculated intervals for each, 90% of them would contain the true parameter. It's a way to express uncertainty and variability in your estimate while stating how sure you are of this range.
In the exercise, both Josh and Kendra calculate a 90% confidence interval, but the approach to degrees of freedom affects their intervals' lengths. With more degrees of freedom, Josh's confidence interval is shorter, indicating more precision due to a narrower t-distribution.
  • Higher confidence level = wider interval.
  • More precision = narrower interval.
Student's t-distribution
The Student's t-distribution is a type of probability distribution that is an alternative to the normal distribution, particularly useful for small sample sizes.
When sample sizes are small or the population standard deviation is unknown, statisticians prefer using the t-distribution to estimate population parameters.
This distribution is characterized by being thicker in the tails compared to a normal distribution, meaning it's more likely to produce values extremely above or below the mean. The exact shape and spread depend on the degrees of freedom; as they increase, the t-distribution begins to resemble a normal distribution more closely.
Josh and Kendra's situation highlights how using different degrees of freedom (19 vs. approx 36.3) results in different shapes for this distribution, thus impacting the precision of their confidence intervals.
Satterthwaite's Approximation
Satterthwaite's Approximation is a method used to estimate degrees of freedom in the case of unequal sample sizes or variances.
When samples have different sizes or variances, it's not straightforward to determine the exact degrees of freedom, which affects the calculation of confidence intervals significantly. Satterthwaite's formula provides a more accurate estimate than just using the smallest sample size minus one.
By using this approximation, Josh is able to calculate a degree of freedom of approximately 36.3, which is higher than Kendra's fixed 19. This yields a more precise confidence interval, demonstrating the benefit of a broader and more complex calculation over a simple deduction based on the minimum sample size.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How much do wild mountain lions weigh? The 77 th Annual Report of the New Mexico Department of Game and Fish, edited by Bill Montoya, gave the following information. Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains gave the following weights (pounds): \(\begin{array}{llllll}68 & 104 & 128 & 122 & 60 & 64\end{array}\) (a) Use a calculator with mean and sample standard deviation keys to verify that \(\bar{x}=91.0\) pounds and \(s \approx 30.7\) pounds. (b) Find a \(75 \%\) confidence interval for the population average weight \(\mu\) of all adult mountain lions in the specified region.

Santa Fe black-on-white is a type of pottery commonly found at archaeological excavations in Bandelier National Monument. At one excavation site a sample of 592 potsherds was found, of which 360 were identified as Santa Fe black-on- white (Bandelier Archaeological Excavation Project: Summer 1990 Excavations at Burnt Mesa Pueblo and Casa del Rito, edited by Kohler and Root, Washington State University). (a) Let \(p\) represent the population proportion of Santa Fe black-on-white potsherds at the excavation site. Find a point estimate for \(p\). (b) Find a \(95 \%\) confidence interval for \(p .\) Give a brief statement of the meaning of the confidence interval. (c) Do you think the conditions \(n p>5\) and \(n q>5\) are satisfied in this problem? Why would this be important?

How hard is it to reach a businessperson by phone? Let \(p\) be the proportion of calls to businesspeople for which the caller reaches the person being called on the first try. (a) If you have no preliminary estimate for \(p\), how many business phone calls should you include in a random sample to be \(80 \%\) sure that the point estimate \(\hat{p}\) will be within a distance of \(0.03\) from \(p ?\) (b) The Book of Odds, by Shook and Shook (Signet), reports that businesspeople can be reached by a single phone call approximately \(17 \%\) of the time. Using this (national) estimate for \(p\), answer part (a).

Consider college officials in admissions, registration, counseling, financial aid, campus ministry, food services, and so on. How much money do these people make each year? Suppose you read in your local newspaper that 45 officials in student services earned an average of \(\bar{x}=\$ 50,340\) each year (Reference: Cbronicle of Higher Education). (a) Assume that \(\sigma=\$ 16,920\) for salaries of college officials in student services. Find a \(90 \%\) confidence interval for the population mean salaries of such personnel. What is the margin of error? (b) Assume that \(\sigma=\$ 10,780\) for salaries of college officials in student services. Find a \(90 \%\) confidence interval for the population mean salaries of such personnel. What is the margin of error? (c) Assume that \(\sigma=\$ 4830\) for salaries of college officials in student services. Find a \(90 \%\) confidence interval for the population mean salaries of such personnel. What is the margin of error? (d) Compare the margins of error for parts (a) through (c). As the standard deviation decreases, does the margin of error decrease? (e) Compare the lengths of the confidence intervals for parts (a) through (c). As the standard deviation decreases, does the length of a \(90 \%\) confidence interval decrease?

A New York Times/CBS poll asked the question, "What do you think is the most important problem facing this country today?" Nineteen percent of the respondents answered "crime and violence." The margin of sampling error was plus or minus 3 percentage points. Following the convention that the margin of error is based on a \(95 \%\) confidence interval, find a \(95 \%\) confidence interval for the percentage of the population that would respond "crime and violence" to the question asked by the pollsters.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.