/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Why do we use \(1 / 4\) in place... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Why do we use \(1 / 4\) in place of \(p(1-p)\) in formula (22) for sample size when the probability of success \(p\) is unknown? (a) Show that \(p(1-p)=1 / 4-(p-1 / 2)^{2}\). (b) Why is \(p(1-p)\) never greater than \(1 / 4\) ?

Short Answer

Expert verified
The expression \( p(1-p) = 1/4 - (p - 1/2)^2 \) shows it's never greater than 1/4, maxed at \( p = 1/2 \).

Step by step solution

01

Understand the Relationship Given

The question provides a transformation for the expression \( p(1-p) \) as \( 1 / 4 - (p - 1 / 2)^{2} \). You should start by recognizing that this form represents a difference between 1/4 and a squared term.
02

Expand the Expression for \( p(1-p) \)

Let's expand \( p(1-p) \) directly: \[ p(1-p) = p - p^2 \]. Now, compare this to the expression given, \( 1/4 - (p - 1/2)^2 \).
03

Recognize the Square Completion Form

Expand the squared term: \[ (p - 1/2)^2 = p^2 - p + 1/4. \] Notice that this matches the \( p - p^2 \) term from Step 2, meaning we can write \( p(1-p) = 1/4 - (p - 1/2)^2 \) by rearranging.
04

Justify Why this Expression is Never Greater than 1/4

Since \( (p - 1/2)^2 \) is always non-negative for any real number \( p \), the maximum value that \( p(1-p) \) can take is when \( (p - 1/2)^2 = 0 \). This happens at \( p = 1/2 \), where \( p(1-p) = 1/4 \). Thus, \( p(1-p) \) is at most 1/4.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size
Understanding sample size is crucial when conducting statistical research. It refers to the number of observations or data points collected from a larger population. Sample size can significantly impact the accuracy and reliability of your study's results. Larger samples tend to provide more reliable estimates because they reduce the variability that can arise from random sampling errors.
To determine an appropriate sample size, you often use formulas that consider the probability of success in a given study. However, when the probability of success, denoted as \( p \), isn't known, a default estimation is required. This is where the transformation of \( p(1-p) \) to \( 1/4 - (p-1/2)^2 \) becomes useful, as it accounts for the most conservative estimate, assuming maximum variability at \( p = 0.5 \).
  • A larger sample size generally means better representation of the population.
  • Choosing appropriate sample size can help minimize errors in the results.
Probability of Success
The probability of success, commonly denoted as \( p \), represents the likelihood of a specific outcome occurring. Understanding this concept is essential in fields that employ probability and statistics. It dictates how results are interpreted in various studies or experiments.
When dealing with sample size calculations, knowing the probability of success helps determine how large a sample you need to achieve desired accuracy. If \( p \), the probability of success, is unknown, the equation \( p(1-p) = 1/4 - (p-1/2)^2 \) assumes its maximum when \( p = 0.5 \), representing highest uncertainty, hence the most conservative guideline for sample size estimation.
  • This probability is crucial for designing experiments and understanding risks or chances in any scenario.
  • It forms the basis for many statistical inferences.
Quadratic Expression
A quadratic expression is an algebraic expression of the form \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants and \( x \) is the variable. In the exercise, the expression \( (p - 1/2)^2 = p^2 - p + 1/4 \) is expanded from a quadratic form that provides insight into the behavior of \( p(1-p) \). Such expressions help in solving various algebraic problems by allowing factoring, completing the square, or using the quadratic formula.
The quadratic nature of this expression \( p(1-p) \) further explains why it's never greater than 1/4 because it derives from properties of squared terms, which are always non-negative. This understanding provides a deeper comprehension of how probabilities interact within statistical formulas.
  • Quadratic expressions are fundamental in both algebra and calculus for modeling curves.
  • The manipulation of these expressions is essential for understanding their implications in problem-solving.
Completing the Square
Completing the square is a mathematical technique used to simplify quadratic expressions. It involves altering the expression into a perfect square by adding and subtracting terms appropriately. This method is beneficial in algebra for solving quadratic equations and analyzing functions.
In the exercise, the expression \(1/4 - (p - 1/2)^2\) uses completing the square to showcase \(p(1-p)\) as a transformation. By rewriting the expression in this completed square form, it becomes evident that \(p(1-p)\) has its maximum value at 1/4 when \(p = 0.5\), with \((p-1/2)^2\) contributing a non-negative term thereafter. This technique demonstrates one of the many applications of completing the square in statistical formulas.
  • Helps in transforming quadratic expressions into easier-to-analyze forms.
  • Vital for deriving solutions and understanding properties of quadratic functions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a marketing survey, a random sample of 730 women shoppers revealed that 628 remained loyal to their favorite supermarket during the past year (i.e., did not switch stores). (Source: Trends in the United States: Consumer Attitudes and the Supermarket, The Research Department, Food Marketing Institute.) (a) Let \(p\) represent the proportion of all women shoppers who remain loyal to their favorite supermarket. Find a point estimate for \(p\). (b) Find a \(95 \%\) confidence interval for \(p\). Give a brief explanation of the meaning of the interval. (c) As a news writer, how would you report the survey results regarding the percentage of women supermarket shoppers who remained loyal to their favorite supermarket during the past year? What is the margin of error based on a \(95 \%\) confidence interval?

As the degrees of freedom increase, what distribution does the Student's \(t\) distribution become more like?

Thirty small communities in Connecticut (population near 10,000 each) gave an average of \(\bar{x}=138.5\) reported cases of larceny per year. Assume that \(\sigma\) is known to be \(42.6\) cases per year (Reference: Crime in the United States, Federal Bureau of Investigation). (a) Find a \(90 \%\) confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (b) Find a \(95 \%\) confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (c) Find a \(99 \%\) confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (d) Compare the margins of error for parts (a) through (c). As the confidence levels increase, do the margins of error increase? (e) Compare the lengths of the confidence intervals for parts (a) through (c). As the confidence levels increase, do the confidence intervals increase in length?

Consider college officials in admissions, registration, counseling, financial aid, campus ministry, food services, and so on. How much money do these people make each year? Suppose you read in your local newspaper that 45 officials in student services earned an average of \(\bar{x}=\$ 50,340\) each year (Reference: Cbronicle of Higher Education). (a) Assume that \(\sigma=\$ 16,920\) for salaries of college officials in student services. Find a \(90 \%\) confidence interval for the population mean salaries of such personnel. What is the margin of error? (b) Assume that \(\sigma=\$ 10,780\) for salaries of college officials in student services. Find a \(90 \%\) confidence interval for the population mean salaries of such personnel. What is the margin of error? (c) Assume that \(\sigma=\$ 4830\) for salaries of college officials in student services. Find a \(90 \%\) confidence interval for the population mean salaries of such personnel. What is the margin of error? (d) Compare the margins of error for parts (a) through (c). As the standard deviation decreases, does the margin of error decrease? (e) Compare the lengths of the confidence intervals for parts (a) through (c). As the standard deviation decreases, does the length of a \(90 \%\) confidence interval decrease?

In the Focus Problem at the beginning of this chapter, a study was described comparing the hatch ratios of wood duck nesting boxes. Group I nesting boxes were well separated from each other and well hidden by available brush. There were a total of 474 eggs in group I boxes, of which a field count showed about 270 hatched. Group II nesting boxes were placed in highly visible locations and grouped closely together. There were a total of 805 eggs in group II boxes, of which a field count showed about 270 hatched. (a) Find a point estimate \(\hat{p}_{1}\) for \(p_{1}\), the proportion of eggs that hatch in group I nest box placements. Find a \(95 \%\) confidence interval for \(p_{1}\). (b) Find a point estimate \(\hat{p}_{2}\) for \(p_{2}\), the proportion of eggs that hatch in group II nest box placements. Find a \(95 \%\) confidence interval for \(p_{2}\). (c) Find a \(95 \%\) confidence interval for \(p_{1}-p_{2} .\) Does the interval indicate that the proportion of eggs hatched from group I nest boxes is higher than, lower than, or equal to the proportion of eggs hatched from group II nest boxes? (d) What conclusions about placement of nest boxes can be drawn? In the article discussed in the Focus Problem, additional concerns are raised about the higher cost of placing and maintaining group I nest box placements. Also at issue is the cost efficiency per successful wood duck hatch.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.