/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 The home run percentage is the n... [FREE SOLUTION] | 91Ó°ÊÓ

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The home run percentage is the number of home runs per 100 times at bat. A random sample of 43 professional baseball players gave the following data for home run percentages (Reference: The Baseball Encyclopedia, Macmillan). $$ \begin{array}{llllllllll} 1.6 & 2.4 & 1.2 & 6.6 & 2.3 & 0.0 & 1.8 & 2.5 & 6.5 & 1.8 \\ 2.7 & 2.0 & 1.9 & 1.3 & 2.7 & 1.7 & 1.3 & 2.1 & 2.8 & 1.4 \\ 3.8 & 2.1 & 3.4 & 1.3 & 1.5 & 2.9 & 2.6 & 0.0 & 4.1 & 2.9 \\ 1.9 & 2.4 & 0.0 & 1.8 & 3.1 & 3.8 & 3.2 & 1.6 & 4.2 & 0.0 \\ 1.2 & 1.8 & 2.4 & & & & & & & \end{array} $$ (a) Use a calculator with mean and standard deviation keys to verify that \(\bar{x} \approx 2.29\) and \(s \approx 1.40 .\) (b) Compute a \(90 \%\) confidence interval for the population mean \(\mu\) of home run percentages for all professional baseball players. Hint: If you use Table 6 of Appendix II, be sure to use the closest \(d\). \(f\). that is smaller. (c) Compute a \(99 \%\) confidence interval for the population mean \(\mu\) of home run percentages for all professional baseball players. (d) The home run percentages for three professional players are Tim Huelett, \(2.5 \quad\) Herb Hunter, \(2.0 \quad\) Jackie Jensen, \(3.8\) Examine your confidence intervals and describe how the home run percentages for these players compare to the population average. (e) In previous problems, we assumed the \(x\) distribution was normal or approximately normal. Do we need to make such an assumption in this problem? Why or why not? Hint: See the central limit theorem in Section \(7.2 .\)

Short Answer

Expert verified
(a) Verified mean and sd; (b) 90% CI: approx (1.89, 2.69); (c) 99% CI: approx (1.61, 2.97); (d) Tim and Herb are inside, Jackie outside 90% CI; (e) No need for normality due to CLT.

Step by step solution

01

Verify Sample Mean and Standard Deviation

The provided data set contains 43 values of home run percentages. First, let's calculate the sample mean \( \bar{x} \) and the sample standard deviation \( s \). Utilize a calculator's statistical mode for this purpose, ensuring all data points are entered correctly. Verify that the results are \( \bar{x} \approx 2.29 \) and \( s \approx 1.40 \).
02

Compute 90% Confidence Interval

To compute the 90% confidence interval for the population mean \( \mu \), use the formula: \( \bar{x} \pm t_{\alpha/2} \frac{s}{\sqrt{n}} \), where \( n = 43 \) is the sample size, \( \bar{x} \approx 2.29 \), \( s \approx 1.40 \), and \( t_{\alpha/2} \) is the t-score from the t-distribution table for \( df = n-1 = 42 \). For 90% confidence, \( \alpha = 0.1 \), so \( t_{0.05} \approx 1.682 \). Calculate the margin of error and find the interval.
03

Compute 99% Confidence Interval

For the 99% confidence interval, use the same formula: \( \bar{x} \pm t_{\alpha/2} \frac{s}{\sqrt{n}} \). Here, \( \alpha = 0.01 \), so refer to the t-distribution table for \( df = 42 \) to find \( t_{0.005} \approx 2.423 \). Again, calculate the new margin of error and determine the confidence interval.
04

Analyze Player Home Run Percentages

Compare the calculated confidence intervals with the home run percentages of Tim Huelett (2.5), Herb Hunter (2.0), and Jackie Jensen (3.8). Determine whether these values fall within the intervals and discuss any insights regarding their performance relative to the population mean.
05

Discuss Normality Assumption

Review the need for the normal distribution assumption. Given our sample size is 43, the Central Limit Theorem suggests that the sample mean distribution will be approximately normal, even if the original data distribution is not. Therefore, normality of the data is not a strict requirement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range of values used to estimate the true value of a population parameter. When we calculate a confidence interval, we're looking to determine where the true population mean might lie, based on our sample data. For instance, in our baseball players example, we want to estimate the mean home run percentage of all professional baseball players using our sample.
  • To compute a confidence interval, we use the sample mean (\(\bar{x}\)) and the sample standard deviation (\(s\)), along with a critical value determined from the t-distribution.
  • The confidence level we choose (e.g., 90% or 99%) indicates how sure we are that the interval contains the true mean. The higher the confidence level, the wider the interval.
The formula used is \(\bar{x} \pm t_{\alpha/2} \frac{s}{\sqrt{n}}\), where \(t_{\alpha/2}\) is the t-score from the t-distribution table. This margin of error adjusts our sample mean to better reflect the population mean. By computing both the 90% and 99% intervals in the exercise, you see how changing the confidence level affects the interval's width.
Central Limit Theorem
The Central Limit Theorem (CLT) is a fundamental principle in statistics that makes working with sample means feasible, even when the original data set may not be normally distributed. This theorem states that, for a sufficiently large sample size, the distribution of the sample means will be approximately normal (bell-shaped), regardless of the shape of the population distribution.
  • In our exercise context, the home run percentages might not be normally distributed on their own.
  • However, our sample size of 43 is large enough for the CLT to take effect.
This allows us to use normal approximation methods for our calculations. Essentially, the CLT lets us say, "Even if the data isn't perfectly normal, our methods for estimating the population mean are still valid." The CLT is why we didn't stress about the normality of the data distribution when we calculated confidence intervals for the mean.
t-distribution
The t-distribution is a probability distribution that's especially useful for small sample sizes or when the population standard deviation is unknown. Unlike the normal distribution, which is applicable for large samples, the t-distribution has heavier tails, meaning it is more spread out.
  • When constructing confidence intervals with smaller samples, the t-distribution provides a more accurate critical value, making sure our intervals are reliable.
  • In our baseball exercise, even with a moderate sample size of 43, we utilize the t-distribution as a precaution and to improve accuracy.
The t-distribution varies with degrees of freedom (df), which are determined by the sample size minus one (\(n - 1\)). For a sample of size 43, we have 42 degrees of freedom. As the sample size grows, the t-distribution begins to resemble the normal distribution more closely, but for smaller samples, sticking with the t-distribution is best for precision.
Population Mean
The population mean (\(\mu\)) is a measure that tells us the average value of an entire population. However, calculating it directly is typically impractical or impossible. That's why we use a sample mean as our best estimate.
  • In statistics exercises like our baseball player example, our goal is to make inferences about this population mean using the sample we've gathered.
  • We use the sample mean of 2.29 as an estimate but the confidence interval process helps us to gauge how close this estimate is likely to be to the actual population mean.
The confidence interval provides a range that, with a certain level of confidence, contains the population mean. Therefore, even though we cannot always measure the population mean exactly, statistical methods allow us to estimate it effectively and understand its potential variability. Based on our 90% and 99% confidence intervals, we can assess how home run percentages for specific players compare to the average, aiding in performance analysis.

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Most popular questions from this chapter

Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below \(6 \mathrm{mg} / \mathrm{dl}(\) Reference: Manual of Laboratory and Diagnostic Tests, F. Fischbach). Recently, the patient's total calcium tests gave the following readings (in \(\mathrm{mg} / \mathrm{dl}\) ). \(9.3\) \(\begin{array}{llllll}8.8 & 10.1 & 8.9 & 9.4 & 9.8 & 10.0\end{array}\) \(\begin{array}{lll}9.9 & 11.2 & 12.1\end{array}\) (a) Use a calculator to verify that \(\bar{x}=9.95\) and \(s \approx 1.02\). (b) Find a \(99.9 \%\) confidence interval for the population mean of total calcium in this patient's blood. (c) Based on your results in part (b), do you think this patient still has a calcium deficiency? Explain.

How hot is the air in the top (crown) of a hot air balloon? Information from Ballooning: The Complete Guide to Riding the Winds, by Wirth and Young (Random House), claims that the air in the crown should be an average of \(100^{\circ} \mathrm{C}\) for a balloon to be in a state of equilibrium. However, the temperature does not need to be exactly \(100^{\circ} \mathrm{C}\). What is a reasonable and safe range of temperatures? This range may vary with the size and (decorative) shape of the balloon. All balloons have a temperature gauge in the crown. Suppose that 56 readings (for a balloon in equilibrium) gave a mean temperature of \(\bar{x}=97^{\circ} \mathrm{C}\). For this balloon, \(\sigma \approx 17^{\circ} \mathrm{C}\). (a) Compute a \(95 \%\) confidence interval for the average temperature at which this balloon will be in a steady-state equilibrium. (b) If the average temperature in the crown of the balloon goes above the high end of your confidence interval, do you expect that the balloon will go up or down? Explain.

(a) Suppose a \(95 \%\) confidence interval for the difference of means contains both positive and negative numbers. Will a \(99 \%\) confidence interval based on the same data necessarily contain both positive and negative numbers? Explain. What about a \(90 \%\) confidence interval? Explain. (b) Suppose a \(95 \%\) confidence interval for the difference of proportions contains all positive numbers. Will a \(99 \%\) confidence interval based on the same data necessarily contain all positive numbers as well? Explain. What about a \(90 \%\) confidence interval? Explain.

A random sample of medical files is used to estimate the proportion \(p\) of all people who have blood type \(B\). (a) If you have no preliminary estimate for \(p\), how many medical files should you include in a random sample in order to be \(85 \%\) sure that the point estimate \(\hat{p}\) will be within a distance of \(0.05\) from \(p ?\) (b) Answer part (a) if you use the preliminary estimate that about 8 out of 90 people have blood type B. (Reference: Manual of Laboratory and Diagnostic Tests, F. Fischbach.)

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