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Let \(z\) be a random variable with a standard normal distribution. Find the indicated probability, and shade the corresponding area under the standard normal curve. $$ P(-2.20 \leq z \leq 1.04) $$

Short Answer

Expert verified
The probability is approximately 0.849. Shade the area between the z-scores -2.20 and 1.04 on the standard normal curve.

Step by step solution

01

Understand the Standard Normal Distribution

A standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. The random variable \(z\) represents standard scores, which tell us how many standard deviations the data point is from the mean.
02

Locate the Z-Scores

Identify the z-scores from the problem statement. In this case, we are looking at the range between \(z = -2.20\) and \(z = 1.04\).
03

Use Z-Table to Find Probabilities

Use a z-table to find the cumulative probabilities associated with the z-scores. For \(z = -2.20\), find \(P(z \leq -2.20)\) and for \(z = 1.04\), find \(P(z \leq 1.04)\).
04

Calculate Probability for the Range

Subtract the probability at \(z = -2.20\) from the probability at \(z = 1.04\) to find the probability within the range: \[ P(-2.20 \leq z \leq 1.04) = P(z \leq 1.04) - P(z \leq -2.20) \]
05

Shade the Area Under the Curve

To visualize, shade the region under the standard normal curve between z-scores \(-2.20\) and \(1.04\). This represents the likelihood of a z-value being within this interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Scores
Z-scores are a way to describe the position of a data point within a distribution, helping us understand how far and in what direction the point lies from the mean. They are standardized scores, meaning each score indicates the number of standard deviations a point is away from the mean. In the case of a standard normal distribution, the mean is 0 and the standard deviation is 1. Therefore, a z-score tells us directly how far a value is from the mean in terms of standard deviations.

For instance, a z-score of 1.04 means the data point is 1.04 standard deviations above the mean. Similarly, a z-score of -2.20 indicates the point is 2.20 standard deviations below the mean.

Calculating and understanding z-scores is fundamental when working with standard normal distributions as they transform data to a comparable standardized form, integrated into further statistical analysis.
Probability Calculation
Probability calculation in the context of z-scores involves determining the likelihood of a particular range of values occurring within a standard normal distribution. The process of finding probabilities for specific z-ranges helps us answer the question: "What is the chance that a randomly selected score falls within a particular interval?"

To calculate probabilities between two z-scores, we follow a few simple steps:
  • First, obtain the cumulative probability for the higher z-score.
  • Next, find the cumulative probability for the lower z-score.
  • Finally, subtract the cumulative probability of the lower z-score from the higher one. This resulting value represents the probability of a randomly picked z-value falling within that interval.
In our example, we want to find the probability between z = -2.20 and z = 1.04. We subtract the cumulative probability at z = -2.20 from that at z = 1.04. This probability can be visualized as the shaded area under the curve between these two points.
Z-Table
A Z-table, also known as the standard normal distribution table, is a mathematical table used to determine the percentage of values below a given z-score in a standard normal distribution. The table is a powerful tool that assists in converting z-scores into probabilities and vice versa.

The Z-table lists z-scores in its first column and provides the cumulative probabilities up to those z-scores in the adjacent columns. It is divided into two sections based on positive and negative z-scores due to the symmetrical property of the standard normal distribution.

When using a Z-table:
  • Identify the correct z-score from your data.
  • Locate this z-score in the Z-table.
  • Read across to find the cumulative probability.
For example, if you need to find the probability for z = 1.04, locate 1.0 in the row and use 0.04 in the column, then find the intersection point for the cumulative probability.

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Most popular questions from this chapter

A relay microchip in a telecommunications satellite has a life expectancy that follows a normal distribution with a mean of 90 months and a standard deviation of \(3.7\) months. When this computer-relay microchip malfunctions, the entire satellite is useless. A large London insurance company is going to insure the satellite for 50 million dollars. Assume that the only part of the satellite in question is the microchip. All other components will work indefinitely. (a) Inverse Normal Distribution For how many months should the satellite be insured to be \(99 \%\) confident that it will last beyond the insurance date? (b) If the satellite is insured for 84 months, what is the probability that it will malfunction before the insurance coverage ends? (c) If the satellite is insured for 84 months, what is the expected loss to the insurance company? (d) If the insurance company charges \(\$ 3\) million for 84 months of insurance, how much profit does the company expect to make?

Assume that \(x\) has a normal distribution with the specified mean and standard deviation. Find the indicated probabilities. $$ P(50 \leq x \leq 70) ; \mu=40 ; \sigma=15 $$

Sketch the areas under the standard normal curve over the indicated intervals, and find the specified areas. $$ \text { Between } z=-2.18 \text { and } z=1.34 $$

What is the value of the standard score for the mean of a distribution?

Assume that \(x\) has a normal distribution with the specified mean and standard deviation. Find the indicated probabilities. $$ P(7 \leq x \leq 9) ; \mu=5 ; \sigma=1.2 $$

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