/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Trevor is interested in purchasi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Trevor is interested in purchasing the local hardware/sporting goods store in the small town of Dove Creek, Montana. After examining accounting records for the past several years, he found that the store has been grossing over \(\$ 850\) per day about \(60 \%\) of the business days it is open. Estimate the probability that the store will gross over \(\$ 850\) (a) at least 3 out of 5 business days. (b) at least 6 out of 10 business days. (c) fewer than 5 out of 10 business days. (d) fewer than 6 out of the next 20 business days. If this actually happened, might it shake your confidence in the statement \(p=0.60\) ? Might it make you suspect that \(p\) is less than \(0.60 ?\) Explain. (e) more than 17 out of the next 20 business days. If this actually happened, might you suspect that \(p\) is greater than \(0.60\) ? Explain.

Short Answer

Expert verified
Apply the binomial distribution with p = 0.6 for calculations. Unlikely results for parts (d) and (e) might suggest a different p value.

Step by step solution

01

Understanding the Problem

We need to determine the probability that the store grosses over $850 considering it does so 60% of the business days. We will use the binomial probability formula since we have a fixed number of trials (business days), two possible outcomes (gross over $850 or not), and consistent probability (p = 0.6).
02

Identify Variables for Binomial Distribution

Let the random variable X denote the number of business days where the store grosses over $850. In this context, the probability of success (gross over $850) p = 0.6, and the probability of failure q = 1 - p = 0.4. For the various scenarios, n will be the number of business days considered.
03

Calculate Probability for (a) At least 3 out of 5 days

For this case, n = 5. We need P(X \geq 3). We can calculate using the binomial formula:\[ P(X \geq 3) = 1 - P(X < 3) = 1 - (P(X = 0) + P(X = 1) + P(X = 2)) \]Compute each probability using:\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]Calculate P(X = 0), P(X = 1), and P(X = 2), then subtract their sum from 1.
04

Compute for (b) At least 6 out of 10 days

For this scenario, n = 10. Calculate P(X \geq 6):\[ P(X \geq 6) = 1 - P(X < 6) = 1 - (P(X = 0) + P(X = 1) + ... + P(X = 5)) \]Compute the probabilities for each X value from 0 to 5 using the binomial formula, and subtract the sum from 1.
05

Evaluate Probability for (c) Fewer than 5 out of 10 days

Here, n = 10. We need P(X < 5):\[ P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) \]Calculate each using the binomial formula and add them together.
06

Assess Probability for (d) Fewer than 6 out of 20 days

For this, n = 20. We need P(X < 6):\[ P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) \]Compute each probability using the binomial formula. If this probability is very low, it might indicate the actual success rate is less than 0.6.
07

Analyze Probability for (e) More than 17 out of 20 days

Here, n = 20. We need P(X > 17):\[ P(X > 17) = P(X = 18) + P(X = 19) + P(X = 20) \]Calculate each using the binomial formula. A very low probability might suggest p is greater than 0.6 if it occurs.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistics
Statistics is all about collecting, analyzing, interpreting, and presenting data. In this problem, we are dealing with data from a local hardware store. To make sense of this data, Trevor uses statistics to determine how often the store's daily gross surpasses $850.
By examining past accounting records, he finds that 60% of the time, the store meets this threshold on business days. This figure - 60% - is a statistical estimation of probability derived from historical data.
Here's the beauty of statistics: it turns raw data into meaningful information to help make informed decisions. The % figure helps Trevor gauge the store's performance trends. Then, using statistical tools, he can estimate probabilities for different business day scenarios.
Probability Estimation
Probability estimation involves predicting how likely an event is to happen based on given information. In Trevor's case, he wants to estimate the probability of the store grossing over $850 on certain numbers of business days.
Based on previous data, the probability of a "success" (grossing over $850) on a single day is 0.6, or 60%. This is the key probability estimate Trevor uses in his calculations.
When we talk about probability in this context, we're essentially assigning numerical values between 0 and 1 to possible outcomes to express their likelihood. Events with higher probabilities are more likely to occur than those with lower probabilities. For Trevor, an accurate probability estimation will aid in understanding how reliably the store performs financially.
Binomial Distribution
A binomial distribution is a probability distribution that summarizes the number of successes in a fixed number of independent trials, each with the same probability of success. In our exercise, each business day is considered a trial, and each day the store grosses over \(850 is a success.
Trevor applies the binomial distribution because:
  • There are a set number of trials (e.g., 5 or 10 days).
  • There's a consistent probability of success (0.6 for each day).
  • Trials are independent so one day's outcome doesn't affect another's.
Trevor uses the binomial formula, \[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k},\] to calculate probabilities for different scenarios, such as grossing over \)850 for at least a certain number of days.
The binomial distribution provides a model to predict likelihoods of various outcomes based on known success rates, fitting Trevor's estimations perfectly.
Statistical Inference
Statistical inference allows us to make conclusions about a population based on sample data. Here, Trevor uses statistical inference to draw conclusions about future business successes based on the store's past performance data.
He takes his historical data (the 60% success rate on business days) and applies it to predict future outcomes. When Trevor calculates probabilities for different scenarios using the binomial distribution, he's essentially making inferences.
If the probabilities of observed outcomes significantly deviate from expected trends (like fewer than 6 out of 20 days exceeding $850), Trevor might question the initial assumption that the performance rate is 60%. Conversely, if in 17 out of 20 days, the store does better, he might think the real success rate is higher.
Statistical inference, thus, supports decision-making by bridging the gap between observed data and broader generalizations about business expectations.

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Most popular questions from this chapter

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