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You roll two fair dice, a green one and a red one. (a) Are the outcomes on the dice independent? (b) Find \(P(1\) on green die and 2 on red die). (c) Find \(P(2\) on green die and 1 on red die). (d) Find \(P((1)\) on green die and 2 on red die) or \((2\) on green die and 1 on red die)).

Short Answer

Expert verified
(a) Yes, the outcomes are independent. (b) \( \frac{1}{36} \) (c) \( \frac{1}{36} \) (d) \( \frac{1}{18} \)

Step by step solution

01

Define Independence

Two events are independent if the occurrence of one event does not affect the occurrence of the other event. In the context of dice, each die roll is independent of the other, thus the outcomes on the green die and the red die are independent.
02

Calculate P(1 on green die and 2 on red die)

To find the probability of rolling a 1 on the green die and a 2 on the red die, we multiply the probabilities of each event occurring, since they are independent. The probability of rolling a 1 on one die is \( \frac{1}{6} \) and the probability of rolling a 2 on the other die is also \( \frac{1}{6} \). So, the combined probability is \( \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} \).
03

Calculate P(2 on green die and 1 on red die)

Similar to the previous step, the probability of rolling a 2 on the green die and a 1 on the red die involves multiplying the probabilities of each individual event: \( \frac{1}{6} \) for rolling a 2 on the green die and \( \frac{1}{6} \) for rolling a 1 on the red die. The combined probability is also \( \frac{1}{36} \).
04

Calculate P((1 on green die and 2 on red die) or (2 on green die and 1 on red die))

To determine the probability of either of these outcomes occurring, we add the probabilities of each individual outcome because they are mutually exclusive. Thus, \( \frac{1}{36} + \frac{1}{36} = \frac{2}{36} = \frac{1}{18} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
Independent events in probability refer to scenarios where the occurrence of one event does not impact the occurrence of another. In simpler terms, the result of one event will not tell us anything about the result of another. For example, rolling a die is an independent event because each roll is separate from the others.

In the context of the exercise, when rolling two dice, the result of the green die does not affect what will happen with the red die. Each die is rolled independently, meaning the fact that you rolled a 1 on the green die and a 2 on the red die happened without influencing each other. This independence makes the calculation of probabilities simpler, as you can simply multiply the probabilities of each event.
Mutually Exclusive Events
Mutually exclusive events are events that cannot happen at the same time. If one event occurs, the other cannot possibly occur. In the example of rolling dice, getting a 1 on the green die and getting a 2 on the green die are mutually exclusive because both can't happen in one roll.

When calculating probabilities, if events are mutually exclusive, you determine the probability of either event happening by adding their individual probabilities. This straightforward addition is possible because mutually exclusive events do not overlap. In our exercise, getting (1 on green and 2 on red) and (2 on green and 1 on red) can't both occur simultaneously with one roll of two dice; hence, these are mutually exclusive.
Outcome Probability
Outcome probability is about calculating the likelihood of a particular event occurring. When asked for the probability of achieving a specific outcome with dice rolls, you calculate it by considering all possible outcomes.

In dice rolls, any side has an equal chance of landing up. The probability of rolling any specific number on a six-sided die is \( \frac{1}{6} \). To determine the probability of two independent events occurring concurrently, such as rolling a 1 on the green die and a 2 on the red die, you multiply their probabilities because they are independent. Thus, the outcome probability for this specific scenario is \( \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} \).

This outcome probability explains how likely it is to see a specific combination when both dice are rolled.
Probability Calculation
Using probability theory, calculating probabilities often involves considering the nature of the events involved. If events are independent, such as dice rolls, the probability of both events occurring is a product of their individual probabilities. For example, calculating the probability for the combination of 1 on green and 2 on red involves multiplying \( \frac{1}{6} \times \frac{1}{6} \) to get \( \frac{1}{36} \).

When you then want to determine the probability of either one event or another occurs, if those events are mutually exclusive, you simply add their probabilities. So, finding the probability of either (1 on green and 2 on red) or (2 on green and 1 on red) involves adding their individual probabilities since they cannot occur together. Thus, you add \( \frac{1}{36} + \frac{1}{36} \) to get \( \frac{2}{36} = \frac{1}{18} \).

This logical process ensures clear understanding when calculating combined probabilities.

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Most popular questions from this chapter

If two events are mutually exclusive, can they occur concurrently? Explain.

You draw two cards from a standard deck of 52 cards without replacing the first one before drawing the second. (a) Are the outcomes on the two cards independent? Why? (b) Find \(P(3\) on 1 st card and 10 on 2 nd). (c) Find \(P(10\) on 1 st card and 3 on 2 nd \()\). (d) Find the probability of drawing a 10 and a 3 in either order.

For each of the following situations, explain why the combinations rule or the permutations rule should be used. (a) Determine the number of different groups of 5 items that can be selected from 12 distinct items. (b) Determine the number of different arrangements of 5 items that can be selected from 12 distinct items.

(a) Make a tree diagram to show all the possible sequences of answers for three multiple-choice questions, each with four possible responses. (b) Probability extension: Assuming that you are guessing the answers so that all outcomes listed in the tree are equally likely, what is the probability that you will guess the one sequence that contains all three correct answers?

Four wires (red, green, blue, and yellow) need to be attached to a circuit board. A robotic device will attach the wires. The wires can be attached in any order, and the production manager wishes to determine which order would be fastest for the robot to use. Use the multiplication rule of counting to determine the number of possible sequences of assembly that must be tested. (Hint: There are four choices for the first wire, three for the second, two for the third, and only one for the fourth.)

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