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One indicator of an outlier is that an observation is more than \(2.5\) standard deviations from the mean. Consider the data value 80 . (a) If a data set has mean 70 and standard deviation 5 , is 80 a suspect outlier? (b) If a data set has mean 70 and standard deviation 3, is 80 a suspect outlier?

Short Answer

Expert verified
(a) 80 is not a suspect outlier; (b) 80 is a suspect outlier.

Step by step solution

01

Understanding Outliers

An outlier is often considered as a data point that lies significantly outside the range of the rest of the data. In this exercise, a data value is considered a suspect outlier if it is more than 2.5 standard deviations away from the mean.
02

Calculating for Part (a)

For the first data set with mean 70 and standard deviation 5, calculate the range beyond which a value would be considered a suspect outlier using the formula: \[ \text{Outlier Range} = (\text{Mean} \pm 2.5 \times \text{Standard Deviation}) \] Substitute the given values: \[ 70 \pm 2.5 \times 5 = 70 \pm 12.5 \] This gives a range of 57.5 to 82.5.
03

Checking Observation for Part (a)

Check if the value 80 falls outside the calculated range of 57.5 to 82.5. Since 80 is within this range, it is not a suspect outlier in this context.
04

Calculating for Part (b)

For the second data set with mean 70 and standard deviation 3, compute the suspect outlier range using the same formula: \[ 70 \pm 2.5 \times 3 = 70 \pm 7.5 \] This gives a new range of 62.5 to 77.5.
05

Checking Observation for Part (b)

Determine if the value 80 lies outside the calculated range of 62.5 to 77.5. Since 80 is greater than the upper limit of 77.5, it is considered a suspect outlier in this situation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
The standard deviation is a measurement that indicates how much data values in a set differ from the mean.
It essentially tells us how "spread out" the values are around the average. A small standard deviation means that most of the numbers are close to the mean.
Conversely, a large standard deviation indicates that the values are more spread out, showing greater variation. Let's break it down with an example.
  • If a class of students scores fairly similarly on a test, the standard deviation of their scores would be low. This is because most students scored close to the average.
  • On the other hand, if the scores vary significantly—with some students doing very well and others poorly—the standard deviation will be higher.
This measure is crucial in determining whether a point, such as a test score, could be considered an outlier, based on its distance from the mean.
Mean
The mean, often referred to as the average, is the sum of all the data points divided by the number of points.
It’s a central value of a data set and provides a quick snapshot of the typical data point. Understanding the mean is essential for analyzing data as it sets the baseline from which we measure deviations. For example, suppose we have test scores: 70, 68, 72, 74, and 66. The mean score would be calculated as:
\[\text{Mean} = \frac{70 + 68 + 72 + 74 + 66}{5} = 70\]By setting the central tendency at 70, we can analyze how individual scores deviate, identify trends, and potentially spot outliers.
Statistical Analysis
Statistical analysis is the process by which data is gathered, reviewed, and interpreted. It’s crucial for making informed decisions based on data rather than assumptions.
In our context, statistical analysis helps determine if a data point, like a test score, is typical or if it stands out significantly from the rest. There are several methods of statistical analysis, but here are a few relevant to our discussion:
  • Descriptive Statistics: These provide a summary about the sample and measures. This includes the mean, median, mode, and standard deviation, providing a quick overview of the data.
  • Inferential Statistics: This involves drawing conclusions from data that are subject to random variation, like observational errors or sampling variability.
By employing statistical analysis, we can deduce insights about data, making it a powerful tool for understanding numbers comprehensively and spotting outliers by measuring deviations from the mean.
Suspect Outlier Criteria
When identifying suspect outliers, a common criterion is to check how far a data point is from the mean using standard deviation. A typical rule is that if a value lies more than 2.5 standard deviations away from the mean, it may be considered an outlier. Let's fixate on this concept with clarity:
  • The basic calculation is: \[\text{Outlier Range} = (\text{Mean} \pm 2.5 \times \text{Standard Deviation})\]
  • If a number falls outside this range, it is labeled a suspect outlier, signaling it could be unusual or worth further investigation.
For instance, if the mean is 70 with a standard deviation of 3, a value of 80 would exceed the outlier range, thus marking it as an outlier. On the contrary, if the standard deviation increased to 5, 80 lands within the range and is not tagged an outlier. Applying suspect outlier criteria helps to highlight data points that require additional attention, offering insights or identifying potential errors in data collection or entry.

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Most popular questions from this chapter

In this problem, we explore the effect on the standard deviation of multiplying each data value in a data set by the same constant. Consider the data set \(5,9,10,11,15 .\) (a) Use the defining formula, the computation formula, or a calculator to com- pute \(s .\) (b) Multiply each data value by 5 to obtain the new data set \(25,45,50,55,75\). Compute s. (c) Compare the results of parts (a) and (b). In general, how does the standard deviation change if each data value is multiplied by a constant \(c\) ? (d) You recorded the weekly distances you bicycled in miles and computed the standard deviation to be \(s=3.1\) miles. Your friend wants to know the standard deviation in kilometers. Do you need to redo all the calculations? Given 1 mile \(=1.6\) kilometers, what is the standard deviation in kilometers?

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Consider the numbers \(\begin{array}{lllll}2 & 3 & 4 & 5 & 5\end{array}\) (a) Compute the mode, median, and mean. (b) If the numbers represented codes for the colors of \(\mathrm{T}\) -shirts ordered from a catalog, which average(s) would make sense? (c) If the numbers represented one-way mileages for trails to different lakes, which average(s) would make sense? (d) Suppose the numbers represent survey responses from 1 to 5, with \(1=\) disagree strongly, \(2=\) disagree, \(3=\) agree, \(4=\) agree strongly, and \(5=\) agree very strongly. Which averages make sense?

Consider the mode, median, and mean. Which average represents the middle value of a data distribution? Which average represents the most frequent value of a distribution? Which average takes all the specific values into account?

What are the big corporations doing with their wealth? One way to answer this question is to examine profits as percentage of assets. A random sample of 50 Fortune 500 companies gave the following information. (Source: Based on information from Fortune 500 , Vol. 135 , No. 8.) \begin{tabular}{l|rrrrr} \hline Profit as percentage of assets & \(8.6-12.5\) & \(12.6-16.5\) & \(16.6-20.5\) & \(20.6-24.5\) & \(24.6-28.5\) \\ \hline Number of companies & 15 & 20 & 5 & 7 & 3 \\ \hline \end{tabular} Estimate the sample mean, sample variance, and sample standard deviation for profit as percentage of assets.

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