/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Let \(x\) be per capita income i... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(x\) be per capita income in thousands of dollars. Let \(y\) be the number of medical doctors per 10,000 residents. Six small cities in Oregon gave the following information about \(x\) and \(y\) (based on information from Life in America's Small Cities, by G. S. Thomas, Prometheus Books). $$ \begin{array}{c|cccccc} \hline x & 8.6 & 9.3 & 10.1 & 8.0 & 8.3 & 8.7 \\ \hline y & 9.6 & 18.5 & 20.9 & 10.2 & 11.4 & 13.1 \\ \hline \end{array} $$ Complete parts (a) through (e), given \(\Sigma x=53, \Sigma y=83.7, \Sigma x^{2}=471.04\), \(\Sigma y^{2}=1276.83, \Sigma x y=755.89\), and \(r \approx 0.934 .\) (f) Suppose a small city in Oregon has a per capita income of 10 thousand dollars. What is the predicted number of M.D.s per 10,000 residents?

Short Answer

Expert verified
The predicted number of doctors is about 20.67 per 10,000 residents.

Step by step solution

01

Understand the Problem

We need to predict the number of medical doctors per 10,000 residents based on a given per capita income for a city using a linear regression model. We are given data of per capita incomes and doctor numbers for six cities, along with certain statistical sums.
02

Recall the Regression Equation

The regression equation is of the form \[y = a + bx\]where \(a\) is the y-intercept and \(b\) is the slope of the line.
03

Calculate the Slope (b)

The slope \(b\) can be calculated using the formula:\[b = \frac{n(\Sigma xy) - (\Sigma x)(\Sigma y)}{n(\Sigma x^2) - (\Sigma x)^2}\]where \(n\) is the number of data points. Here, \(n = 6\). Substituting the known values:\[b = \frac{6(755.89) - (53)(83.7)}{6(471.04) - (53)^2}\]
04

Calculate the Slope (b) Continued

Continue the calculation:\[b = \frac{4535.34 - 4436.1}{2826.24 - 2809} = \frac{99.24}{17.24} \approx 5.756\]
05

Calculate the Y-intercept (a)

The y-intercept \(a\) is calculated using:\[a = \frac{(\Sigma y) - b(\Sigma x)}{n}\]Substitute the known values:\[a = \frac{83.7 - (5.756)(53)}{6}\]
06

Calculate the Y-intercept (a) Continued

Continue the calculation:\[a = \frac{83.7 - 305.068}{6} = \frac{-221.368}{6} = -36.8947\]
07

Write the Regression Line Equation

Substitute \(a\) and \(b\) into the regression equation:\[y = -36.8947 + 5.756x\]
08

Predict for x = 10

Substitute \(x = 10\) (the given income) into the regression equation to find \(y\):\[y = -36.8947 + 5.756(10)\]
09

Calculate the Predicted y

Calculate the result:\[y = -36.8947 + 57.56= 20.6653\]Thus, the predicted number of M.D.s per 10,000 residents for a city with per capita income of 10 thousand dollars is approximately 20.67.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Regression
Linear regression is a statistical method that models the relationship between a dependent variable and one or more independent variables. In our exercise, the dependent variable is the number of medical doctors per 10,000 residents, denoted as \( y \), and the independent variable is the per capita income in thousands of dollars, denoted as \( x \). The primary goal of linear regression is to find the line that best fits the observed data. This line is expressed through the regression equation \( y = a + bx \), where \( a \) is the y-intercept, and \( b \) is the slope.
  • Simplifies complex data relationships into a straight line.
  • Helps make predictions about the dependent variable when given new values of the independent variable.
  • Commonly used in various fields like economics, biology, and social sciences.

Understanding this basic concept helps you analyze and predict outcomes by drawing conclusions from data patterns.
Slope Calculation
The slope \( b \) of the regression line indicates how much \( y \) changes for a one-unit change in \( x \). It quantifies the relationship between the variables. To calculate the slope \( b \), use the formula:\[b = \frac{n(\Sigma xy) - (\Sigma x)(\Sigma y)}{n(\Sigma x^2) - (\Sigma x)^2}\]where \( n \) is the number of data points. For our specific data set:
  • \( \Sigma xy \) is the sum of the product of each \( x \) and \( y \) value.
  • \( \Sigma x \) is the sum of all \( x \) observations.
  • \( \Sigma y \) is the sum of all \( y \) observations.
  • \( \Sigma x^2 \) is the sum of the squares of all \( x \) observations.

By plugging in these values, as shown in the exercise, we calculated \( b \approx 5.756 \). This means for every increase of 1 (thousand dollars) in per capita income, the number of medical doctors per 10,000 residents increases by approximately 5.756. Understanding how to calculate the slope helps interpret the direction and strength of a relationship between variables.
Y-intercept Calculation
The y-intercept \( a \) of a linear regression line represents the value of \( y \) when \( x \) is zero. It is the point where the line crosses the y-axis. To find \( a \), use the formula:\[a = \frac{(\Sigma y) - b(\Sigma x)}{n}\]Substitute the calculated slope \( b \) and other known values from the data:
  • This value helps to understand the baseline level of \( y \) when there is no contribution from the independent variable.
  • The calculated y-intercept \( a = -36.8947 \) suggests a theoretical scenario.
  • In real-world scenarios, the y-intercept often provides a hypothetical rather than a practical interpretation.

Even if \( x = 0 \) in our dataset doesn't make sense practically (as zero income isn’t realistic), the intercept is vital for constructing the regression line and predicting \( y \) for any \( x \). Knowing how to calculate the y-intercept ensures that you can accurately construct and apply the regression equation.

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Most popular questions from this chapter

Do larger universities tend to have more property crime? University crime statistics are affected by a variety of factors. The surrounding community, accessibility given to outside visitors, and many other factors influence crime rate. Let \(x\) be a variable that represents student enrollment (in thousands) on a university campus, and let \(y\) be a variable that represents the number of burglaries in a year on the university campus. A random sample of \(n=8\) universities in California gave the following information about enrollments and annual burglary incidents. (Reference: Crime in the United States, Federal Bureau of Investigation.) $$ \begin{array}{c|clllllll} \hline x & 12.5 & 30.0 & 24.5 & 14.3 & 7.5 & 27.7 & 16.2 & 20.1 \\ \hline y & 26 & 73 & 39 & 23 & 15 & 30 & 15 & 25 \\ \hline \end{array} $$ (a) Make a scatter diagram and draw the line you think best fits the data. (b) Would you say the correlation is low, moderate, or high? positive or negative? (c) Using a calculator, verify that \(\Sigma x=152.8, \Sigma x^{2}=3350.98, \Sigma y=246\), \(\Sigma y^{2}=10,030\), and \(\Sigma x y=5488.4\). Compute \(r\). As \(x\) increases, does the value of \(r\) imply that \(y\) should tend to increase or decrease? Explain.

Over the past 30 years in the United States, there has been a strong negative correlation between the number of infant deaths at birth and the number of people over age \(65 .\) (a) Is the fact that people are living longer causing a decrease in infant mortalities at birth? (b) What lurking variables might be causing the increase in one or both of the variables? Explain.

Please do the following. (a) Draw a scatter diagram displaying the data. (b) Verify the given sums \(\Sigma x, \Sigma y, \Sigma x^{2}, \Sigma y^{2}\), and \(\sum x y\) and the value of the sample correlation coefficient \(\underline{r}\) (c) Find \(\bar{x}, \bar{y}, a\), and \(b .\) Then find the equation of the least- squares line \(\hat{y}=a+b x\) (d) Graph the least-squares line on your scatter diagram. Be sure to use the point \((\bar{x}, \bar{y})\) as one of the points on the line. (e) Find the value of the coefficient of determination \(r^{2} .\) What percentage of the variation in \(y\) can be explained by the corresponding variation in \(x\) and the least-squares line? What percentage is unexplained? Answers may vary slightly due to rounding. You are the foreman of the Bar-S cattle ranch in Colorado. A neighboring ranch has calves for sale, and you are going to buy some calves to add to the Bar-S herd. How much should a healthy calf weigh? Let \(x\) be the age of the calf (in weeks), and let \(y\) be the weight of the calf (in kilograms). The following information is based on data taken from The Merck Veterinary Manual (a reference used by many ranchers). $$ \begin{array}{r|rrrrrr} \hline x & 1 & 3 & 10 & 16 & 26 & 36 \\ \hline y & 42 & 50 & 75 & 100 & 150 & 200 \\ \hline \end{array} $$ Complete parts (a) through (e), given \(\Sigma x=92, \Sigma y=617, \Sigma x^{2}=2338, \Sigma y^{2}=\) \(82,389, \Sigma x y=13,642\), and \(r \approx 0.998 .\) (f) The calves you want to buy are 12 weeks old. What does the least- squares line predict for a healthy weight?

Given the linear regression equation $$ x_{1}=1.6+3.5 x_{2}-7.9 x_{3}+2.0 x_{4} $$ (a) Which variable is the response variable? Which variables are the explanatory variables? (b) Which number is the constant term? List the coefficients with their corresponding explanatory variables. (c) If \(x_{2}=2, x_{3}=1\), and \(x_{4}=5\), what is the predicted value for \(x_{1}\) ? (d) Explain how each coefficient can be thought of as a "slope" under certain conditions. Suppose \(x_{3}\) and \(x_{4}\) were held at fixed but arbitrary values and \(x_{2}\) increased by 1 unit. What would be the corresponding change in \(x_{1} ?\) Suppose \(x_{2}\) increased by 2 units. What would be the expected change in \(x_{1}\) ? Suppose \(x_{2}\) decreased by 4 units. What would be the expected change in \(x_{1} ?\) (e) Suppose that \(n=12\) data points were used to construct the given regression equation and that the standard error for the coefficient of \(x_{2}\) is \(0.419\). Construct a \(90 \%\) confidence interval for the coefficient of \(x_{2}\). (f) Using the information of part (e) and level of significance \(5 \%\), test the claim that the coefficient of \(x_{2}\) is different from zero. Explain how the conclusion of this test would affect the regression equation.

Given the linear regression equation \(x_{3}=-16.5+4.0 x_{1}+9.2 x_{4}-1.1 x_{7}\) (a) Which variable is the response variable? Which variables are the explanatory variables? (b) Which number is the constant term? List the coefficients with their corresponding explanatory variables. (c) If \(x_{1}=10, x_{4}=-1\), and \(x_{7}=2\), what is the predicted value for \(x_{3}\) ? (d) Explain how each coefficient can be thought of as a "slope." Suppose \(x_{1}\) and \(x_{7}\) were held as fixed but arbitrary values. If \(x_{4}\) increased by 1 unit, what would we expect the corresponding change in \(x_{3}\) to be? If \(x_{4}\) increased by 3 units, what would be the corresponding expected change in \(x_{3} ?\) If \(x_{4}\) decreased by 2 units, what would we expect for the corresponding change in \(x_{3}\) ? (e) Suppose that \(n=15\) data points were used to construct the given regression equation and that the standard error for the coefficient of \(x_{4}\) is \(0.921\). Construct a \(90 \%\) confidence interval for the coefficient of \(x_{4}\). (f) Using the information of part (e) and level of significance \(1 \%\), test the claim that the coefficient of \(x_{4}\) is different from zero. Explain how the conclusion has a bearing on the regression equation.

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