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91Ó°ÊÓ

When drawing a scatter diagram, along which axis is the explanatory variable placed? Along which axis is the response variable placed?

Short Answer

Expert verified
Explanatory variable is on the x-axis; response variable is on the y-axis.

Step by step solution

01

Understanding Variables in a Scatter Diagram

In a scatter diagram, we have two types of variables: the explanatory variable and the response variable. The explanatory variable is the one that is controlled or changed to see how it affects the response variable.
02

Explanatory Variable Placement

The explanatory variable is typically represented along the horizontal axis, also known as the x-axis. This axis is used to represent the variable that is expected to influence or predict changes in the other variable.
03

Response Variable Placement

The response variable is placed along the vertical axis, also known as the y-axis. The y-axis is used to show how this variable changes in response to the changes in the explanatory variable.
04

Summary of Axes Placement

In summary, in a scatter diagram, the explanatory variable is placed along the x-axis, and the response variable is placed along the y-axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Explanatory Variable
In the world of data analysis and statistical graphing, understanding the explanatory variable is fundamental. This type of variable, often referred to as the independent variable, is the one that you select to manipulate or control in an experiment or study. By changing the explanatory variable, you hope to observe changes in another variable, known as the response variable. For instance, if you are studying the effect of study time on test scores, 'study time' would be your explanatory variable. You adjust 'study time' to see how it influences test scores. Remember, without the correct identification and manipulation of the explanatory variable, analyzing relationships in data would be near impossible.
Response Variable
The response variable, sometimes called the dependent variable, is what you measure in an experiment. It responds or changes as the explanatory variable is controlled or altered. Continuing with our example, if your explanatory variable is 'study time', the response variable would be 'test scores', as it's expected to change in response to how much time is spent studying. Understanding the interplay between a response variable and an explanatory variable is crucial for testing hypotheses and evaluating outcomes in any statistical study. This variable is what you're observing outcomes for, providing key insights into the patterns and trends in your data.
Axes Placement
Axes placement is a critical aspect of constructing a scatter plot, ensuring clarity and correctness in the representation of data. The horizontal axis, or x-axis, is where you place the explanatory variable. This is because it serves as the baseline for the changes and manipulations you are testing. Meanwhile, the vertical axis, known as the y-axis, is reserved for the response variable. This axis displays how the response variable behaves in relation to changes in the explanatory variable.
By consistently placing these variables on their respective axes, it allows for a standardized representation in scatter plots, making them easier to read and understand. Consistent axis labeling helps to immediately orient the viewer to what is being tested and measured in the graph.
Statistical Graphing
Statistical graphing like creating scatter plots is a powerful tool for visualizing data relationships. A scatter plot places each data point on the graph using two dimensions – with the explanatory variable on the x-axis and the response variable on the y-axis. This allows you to quickly see if there is a relationship or trend between the two.
Some benefits of scatter plots include:
  • Detecting patterns or trends in data that might be difficult to see otherwise.
  • Identifying potential correlations between variables.
  • Helping to spot outliers that deviate from the expected pattern.
When creating a scatter plot, it’s important to ensure your data is accurate and your axes are labeled correctly. This will help in clearly communicating the insights that can be drawn from your data, ultimately aiding in the decision-making process.

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Most popular questions from this chapter

Over the past 50 years, there has been a strong negative correlation between average annual income and the record time to run 1 mile. In other words, average annual incomes have been rising while the record time to run 1 mile has been decreasing. (a) Do you think increasing incomes cause decreasing times to run the mile? Explain. (b) What lurking variables might be causing the increase in one or both of the variables? Explain.

What is the symbol used for the population correlation coefficient?

When we take measurements of the same general type, a power law of the form \(y=\alpha x^{\beta}\) often gives an excellent fit to the data. A lot of research has been conducted as to why power laws work so well in business, economics, biology, ecology, medicine, engineering, social science, and so on. Let us just say that if you do not have a good straight-line fit to data pairs \((x, y)\), and the scatter plot does not rise dramatically (as in exponential growth), then a power law is often a good choice. College algebra can be used to show that power law models become linear when we apply logarithmic transformations to both variables. To see how this is done, please read on. Note: For power law models, we assume all \(x>0\) and all \(y>0\). Suppose we have data pairs \((x, y)\) and we want to find constants \(\alpha\) and \(\beta\) such that \(y=\alpha x^{\beta}\) is a good fit to the data. First, make the logarithmic transformations \(x^{\prime}=\log x\) and \(y^{\prime}=\log y .\) Next, use the \(\left(x^{\prime}, y^{\prime}\right)\) data pairs and a calculator with linear regression keys to obtain the least-squares equation \(y^{\prime}=a+b x^{\prime} .\) Note that the equation \(y^{\prime}=a+b x^{\prime}\) is the same as \(\log y=a+b(\log x)\). If we raise both sides of this equation to the power 10 and use some college algebra, we get \(y=10^{a}(x)^{b} .\) In other words, for the power law model \(y=\alpha x^{\beta}\), we have \(\alpha \approx 10^{a}\) and \(\beta \approx b\). In the electronic design of a cell phone circuit, the buildup of electric current (Amps) is an important function of time (microseconds). Let \(x=\) time in microseconds and let \(y=\) Amps built up in the circuit at time \(x\). $$ \begin{array}{c|ccccc} \hline x & 2 & 4 & 6 & 8 & 10 \\ \hline y & 1.81 & 2.90 & 3.20 & 3.68 & 4.11 \\ \hline \end{array} $$ (a) Make the logarithmic transformations \(x^{\prime}=\log x\) and \(y^{\prime}=\log y .\) Then make a scatter plot of the \(\left(x^{\prime}, y^{\prime}\right)\) values. Does a linear equation seem to be a good fit to this plot? (b) Use the \(\left(x^{\prime}, y^{\prime}\right)\) data points and a calculator with regression keys to find the least-squares equation \(y^{\prime}=a+b x^{\prime} .\) What is the correlation coefficient? (c) Use the results of part (b) to find estimates for \(\alpha\) and \(\beta\) in the power law \(y=\) \(\alpha x^{\beta .}\) Write the power law giving the relationship between time and Amp buildup. Note: The TI-84Plus calculator fully supports the power law model. Place the original \(x\) data in list \(\mathrm{L} 1\) and the corresponding \(y\) data in list \(\mathrm{L} 2 .\) Then press STAT, followed by CALC, and scroll down to option A: PwrReg. The output gives values for \(\alpha, \beta\), and the correlation coefficient \(r\).

Given the linear regression equation $$ x_{1}=1.6+3.5 x_{2}-7.9 x_{3}+2.0 x_{4} $$ (a) Which variable is the response variable? Which variables are the explanatory variables? (b) Which number is the constant term? List the coefficients with their corresponding explanatory variables. (c) If \(x_{2}=2, x_{3}=1\), and \(x_{4}=5\), what is the predicted value for \(x_{1}\) ? (d) Explain how each coefficient can be thought of as a "slope" under certain conditions. Suppose \(x_{3}\) and \(x_{4}\) were held at fixed but arbitrary values and \(x_{2}\) increased by 1 unit. What would be the corresponding change in \(x_{1} ?\) Suppose \(x_{2}\) increased by 2 units. What would be the expected change in \(x_{1}\) ? Suppose \(x_{2}\) decreased by 4 units. What would be the expected change in \(x_{1} ?\) (e) Suppose that \(n=12\) data points were used to construct the given regression equation and that the standard error for the coefficient of \(x_{2}\) is \(0.419\). Construct a \(90 \%\) confidence interval for the coefficient of \(x_{2}\). (f) Using the information of part (e) and level of significance \(5 \%\), test the claim that the coefficient of \(x_{2}\) is different from zero. Explain how the conclusion of this test would affect the regression equation.

In Section \(5.1\), we studied linear combinations of independent random variables. What happens if the variables are not independent? A lot of mathematics can be used to prove the following: Let \(x\) and \(y\) be random variables with means \(\mu_{x}\) and \(\mu_{y}\), variances \(\sigma_{x}^{2}\) and \(\sigma_{y}^{2}\) and population correlation coefficient \(\rho\) (the Greek letter rho). Let \(a\) and \(b\) be any constants and let \(w=a x+b y .\) Then $$ \begin{aligned} &\mu_{w}=a \mu_{x}+b \mu_{y} \\ &\sigma_{w}^{2}=a^{2} \sigma_{x}^{2}+b^{2} \sigma_{y}^{2}+2 a b \sigma_{x} \sigma_{y} \rho \end{aligned} $$ In this formula, \(\rho\) is the population correlation coefficient, theoretically computed using the population of all \((x, y)\) data pairs. The expression \(\sigma_{x} \sigma_{y} \rho\) is called the covariance of \(x\) and \(y\). If \(x\) and \(y\) are independent, then \(\rho=0\) and the formula for \(\sigma_{w}^{2}\) reduces to the appropriate formula for independent variables (see Section 5.1). In most real-world applications the population parameters are not known, so we use sample estimates with the understanding that our conclusions are also estimates. Do you have to be rich to invest in bonds and real estate? No, mutual fund shares are available to you even if you aren't rich. Let \(x\) represent annual percentage return (after expenses) on the Vanguard Total Bond Index Fund, and let \(y\) represent annual percentage return on the Fidelity Real Estate Investment Fund. Over a long period of time, we have the following population estimates (based on Morningstar Mutual Fund Report). $$ \mu_{x} \approx 7.32 \quad \sigma_{x} \approx 6.59 \quad \mu_{y} \approx 13.19 \quad \sigma_{y} \approx 18.56 \quad \rho \approx 0.424 $$ (a) Do you think the variables \(x\) and \(y\) are independent? Explain. (b) Suppose you decide to put \(60 \%\) of your investment in bonds and \(40 \%\) in real estate. This means you will use a weighted average \(w=0.6 x+0.4 y\). Estimate your expected percentage return \(\mu_{w}\) and risk \(\sigma_{w}\). (c) Repeat part (b) if \(w=0.4 x+0.6 y\). (d) Compare your results in parts (b) and (c). Which investment has the higher expected return? Which has the greater risk as measured by \(\sigma_{w} ?\)

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