Chapter 6: Problem 1
If \(\sin \theta+\sin \phi=a\) and \(\cos \theta+\sin \phi=b\) then tan \(\frac{\theta-\phi}{2}\) is equal to (a) \(\sqrt{\frac{a^{2}+b^{2}}{4-a^{2}-b^{2}}}\) (b) \(\sqrt{\frac{4-a^{2}-b^{2}}{a^{2}+b^{2}}}\) (c) \(\sqrt{\frac{a^{2}+b^{2}}{4+a^{2}+b^{2}}}\) (d) \(\sqrt{\frac{4+a^{2}+b^{2}}{a^{2}+b^{2}}}\)
Short Answer
Step by step solution
Rewrite the given expressions
Express trigonometric identities
Apply the tangent half-angle formula
Calculate \( \sin^2(\theta - \phi) \) and \( \cos(\theta - \phi) \) from given equations
Compare the derived expression to possible answers
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Tangent Half-Angle
Trigonometric Identities
- \(\sin^2 \theta + \cos^2 \theta = 1\)
- \(\sin(\theta - \phi) = \sin \theta \cos \phi - \cos \theta \sin \phi\)
Algebraic Manipulation
Trigonometric Functions
- \(\sin(\theta)\) is the ratio of the opposite side to the hypotenuse.
- \(\cos(\theta)\) is the ratio of the adjacent side to the hypotenuse.
- \(\tan(\theta)\) is the ratio of the sine of the angle to the cosine, \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\).