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Let \(z_{1}=2+3 i, z_{2}=2-3 i\), and \(z_{3}=4+5 i\), and find $$z_{1} z_{2}$$

Short Answer

Expert verified
The product \( z_{1}z_{2} \) is 13.

Step by step solution

01

Write down the expression for multiplication

We need to find the product of two complex numbers: \( z_{1} = 2 + 3i \) and \( z_{2} = 2 - 3i \). This expression can be written as \( z_{1}z_{2} = (2 + 3i)(2 - 3i) \).
02

Apply the distributive property (FOIL Method)

When multiplying two complex numbers, use the distributive property: \[(2 + 3i)(2 - 3i) = 2(2) + 2(-3i) + 3i(2) + 3i(-3i)\]This simplifies to:\[= 4 - 6i + 6i - 9i^2\]
03

Simplify the expression

Notice that the \(-6i\) and \(+6i\) terms cancel each other out. We then have:\[= 4 - 9i^2\]Recall that \(i^2 = -1\), substitute this into the equation:\[= 4 - 9(-1)\]\(= 4 + 9\)
04

Final simplification

Now, we add the real numbers:\(= 4 + 9 = 13\)Hence, the product \( z_{1} z_{2} \) simplifies to 13.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

FOIL Method
When multiplying two binomials, such as complex numbers, the FOIL method is a handy technique. FOIL stands for First, Outer, Inner, and Last – these are the pairs of terms we multiply together to get all parts of the product.
In the case of complex numbers, like
  • \( (a + bi) \) and \( (c + di) \)
the process looks like this:
  • First: multiply the first terms of each binomial (\( a \times c \)).
  • Outer: multiply the outer terms (\( a \times di \)).
  • Inner: multiply the inner terms (\( bi \times c \)).
  • Last: multiply the last terms of each binomial (\( bi \times di \)).
For the example of \( (2+3i)(2-3i) \), we apply the FOIL process to multiply:
  • First: \( 2 \times 2 = 4 \)
  • Outer: \( 2 \times (-3i) = -6i \)
  • Inner: \( 3i \times 2 = 6i \)
  • Last: \( 3i \times (-3i) = -9i^2 \)
The FOIL method helps in ensuring no term is missed when expanding the product.
Distributive Property
The distributive property is a key mathematical principle, especially in algebra, and it's vital for multiplying expressions like complex numbers. The property states:
  • \( a(b+c) = ab + ac \)
When it comes to complex numbers, this property helps organize and distribute the multiplication across each term.
In the problem of multiplying
  • \( (2 + 3i) \times (2 - 3i) \)
we break it down:
  • First, multiply each term in the first complex number by each term in the second, then add the results together.
By following the structured distribution:
  • \( (2 \times 2) + (2 \times -3i) + (3i \times 2) + (3i \times -3i) \)
All terms are integrated into one finished result:
  • \( 4 - 6i + 6i - 9i^2 \)
This method ensures that no part is left out in the multiplication.
Imaginary Unit i
The imaginary unit \( i \) is an essential concept in complex numbers. It represents the square root of \( -1 \) and is written as:
  • \( i^2 = -1 \)
In expressions involving complex numbers, \( i \) functions like a regular variable, but follows different rules due to its definition.
For example, when dealing with the expression
  • \( 3i \times -3i = -9i^2 \)
we simplify it using the rule for \( i^2 \). Since \( i^2 = -1 \), substitute it to get:
  • \( -9 \times -1 = 9 \)
By understanding and correctly applying the properties of \( i \), it makes simplifying and working with complex numbers possible. So, in operations like multiplication, always recall \( i^2 = -1 \) and use it to transform the expression.

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