Chapter 8: Problem 68
Change each equation to rectangular coordinates and then graph.Graph \(r_{1}=2+2 \cos \theta\) and \(r_{2}=2-2 \cos \theta\) and name three points they have in common.
Short Answer
Expert verified
The circles intersect at points \((0, 2)\), \((0, -2)\), and \((0, 0)\).
Step by step solution
01
Understanding the Polar Coordinates
The given equations are in polar coordinates: \(r_1 = 2 + 2\cos\theta\) and \(r_2 = 2 - 2\cos\theta\). These are known as polar curves. To convert them into rectangular coordinates (\(x,y\)), we need to use the relations \(x = r\cos\theta\) and \(y = r\sin\theta\).
02
Conversion of the Equation \(r_1 = 2 + 2\cos\theta\) to Rectangular Coordinates
For the first equation, we use the identity \(r = \sqrt{x^2 + y^2}\) and \(x = r\cos\theta\), so \(r_1 = 2 + 2\frac{x}{r_1}\). This becomes \(r_1^2 = (2 + \frac{2x}{r_1})^2\). By multiplying through by \(r_1^2\) and simplifying, we get \((x - 2)^2 + y^2 = 4\), which represents a circle centered at \((2, 0)\) with radius 2.
03
Conversion of the Equation \(r_2 = 2 - 2\cos\theta\) to Rectangular Coordinates
Similarly, using the same approach, \(r_2 = 2 - 2\frac{x}{r_2}\) becomes \((x + 2)^2 + y^2 = 4\) after simplification. This represents a circle centered at \((-2, 0)\) with radius 2.
04
Finding Intersection Points
Both equations represent circles, and to find their intersection points, set \((x - 2)^2 + y^2 = (x + 2)^2 + y^2\). Simplify to find \(x = 0\). Substitute \(x = 0\) back into either circle's equation, \(y^2 = 4 - 0\). Thus, \(y = \pm 2\). The common points are \((0, 2)\) and \((0, -2)\). The polar curves also intersect at \(\theta = \pi/2\), giving the point \((0, 0)\) as another intersection due to their symmetry.
05
Graphing and Finalizing the Solution
Graph the circles centered at \((2, 0)\) and \((-2, 0)\) each with radius 2. The intersection points \((0, 2)\), \((0, -2)\), and \((0, 0)\) are visible where the circles intersect. These are the three points the circles have in common.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
Polar coordinates are a way of expressing the position of a point in a plane using a distance from a reference point and an angle from a reference direction. This system is different from the more familiar rectangular coordinate system, which measures a point's position using horizontal and vertical distances (x and y).
- Polar coordinates use two values:
- \( r \): the distance from the origin (the center point, often represented as the pole)
- \( \theta \): the angle measured from the positive x-axis (typically in radians)
- The conversion between polar and rectangular coordinates relates through the equations:
- \( x = r\cos\theta \)
- \( y = r\sin\theta \)
- \( r = \sqrt{x^2 + y^2} \)
- \( \theta = \tan^{-1}\left(\frac{y}{x}\right) \)
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, are a system where each point in a plane is determined by an ordered pair of numbers, typically referred to as \( (x, y) \). This system is based on a grid formed by perpendicular horizontal and vertical lines.
- The x-coordinate measures how far a point is to the left or right of the origin (zero point), while the y-coordinate measures how far a point is above or below the origin.
- Rectangular equations can represent a variety of shapes including lines, circles, ellipses, parabolas, and hyperbolas.
- \( x = r\cos\theta \)
- \( y = r\sin\theta \)
Graphing Circles
Graphing circles in the coordinate plane involves understanding the standard form of a circle's equation, which is \[(x - h)^2 + (y - k)^2 = r^2,\]where \((h, k)\) is the circle's center, and \(r\) is its radius.
- This equation shows that all points on the circle are equidistant from the center, a key property defining a circle.
- Graphically, this means moving \(r\) units away from the center in all directions to form a perfect circle.
- \((x - 2)^2 + y^2 = 4\) for the first circle, translating to a circle centered at \((2, 0)\) with radius 2.
- \((x + 2)^2 + y^2 = 4\) for the second circle, meaning a circle centered at \((-2, 0)\) with a radius of 2.