Chapter 8: Problem 60
Find the following products. $$(4+7 i)^{2}$$
Short Answer
Expert verified
\((-33 + 56i)\)
Step by step solution
01
Expand the Square
To find \((4 + 7i)^2\), we need to first expand the expression using the formula for squaring a binomial: \((a + b)^2 = a^2 + 2ab + b^2\). Let \(a = 4\) and \(b = 7i\).
02
Calculate Individual Squares
Calculate each term separately: For \(a^2\): \(4^2 = 16\).For \(b^2\): \((7i)^2 = (7^2)(i^2) = 49i^2\). Since \(i^2 = -1\), \(49i^2 = -49\).
03
Compute 2ab
Calculate the middle term \(2ab\): \(2 \times 4 \times 7i = 56i\).
04
Combine the Terms
Combine all the calculated values: \(16 + 56i - 49\). Simplify by combining the real parts: \(16 - 49 = -33\).The complete expression is \(-33 + 56i\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Number Multiplication
Multiplying complex numbers can be a fun and interesting task once you get the hang of it. When working with complex numbers, we generally deal with numbers of the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit with the property \(i^2 = -1\). To multiply two complex numbers, we use the distributive property just like multiplying binomials. It involves:
- Multiplying the real parts together
- Multiplying the imaginary parts together
- Taking care of the cross terms
Binomial Expansion
Expanding binomials is a concept you're probably familiar with, and this becomes handy when working with expressions like \((a + b)^2\). In our case, we focused on expanding \((4 + 7i)^2\). Here's how it goes:
- Recall the formula: \((a + b)^2 = a^2 + 2ab + b^2\).
- Identify \(a\) and \(b\); here, \(a = 4\) and \(b = 7i\).
- Apply the formula, calculating each component separately.
Imaginary Unit Properties
The imaginary unit \(i\) can sometimes twist our brains. It’s a special number that satisfies \(i^2 = -1\). This little equation is the key to handling expressions involving complex numbers. Here's why it's important:
- When squaring \(i\), you switch signs from positive to negative.
- This property ensures the imaginary parts are properly translated back into real numbers during calculations.