Chapter 8: Problem 5
Sketch the graph of each equation by making a table using values of \(\theta\) that are multiples of \(45^{\circ}\).\(r=6 \cos \theta\)
Short Answer
Expert verified
Plot points for \( r = 6 \cos \theta \) using \( \theta \) multiples of \( 45^{\circ} \), then connect them to form a limacon.
Step by step solution
01
Understanding the Equation
The equation given is in polar form, which relates the radius \( r \) with the angle \( \theta \). It indicates how the distance from the origin varies with \( \theta \). This is a polar equation of a limacon.
02
Select \( \theta \) Values
Choose values for \( \theta \) that are multiples of \( 45^{\circ} \). These will be: \( 0^{\circ}, 45^{\circ}, 90^{\circ}, 135^{\circ}, 180^{\circ}, 225^{\circ}, 270^{\circ}, 315^{\circ}, 360^{\circ} \).
03
Calculate \( r \) for Each \( \theta \) Value
For each angle, calculate \( r = 6 \cos \theta \). Make sure to convert any angle measurements into radians if using a calculator (e.g., \( 45^{\circ} = \frac{\pi}{4} \)).
04
Compile the Table
Create a table with two columns: one for \( \theta \) and the other for \( r \). Fill in the values of \( r \) corresponding to each \( \theta \). For example: \( \theta = 0^{\circ} \), \( r = 6 \); \( \theta = 90^{\circ} \), \( r = 0 \); etc.
05
Plot the Points on Polar Graph
Plot each pair of values (\( \theta, r \)) on a polar coordinate graph. Each point's location is determined by \( \theta \) (the direction angle) and \( r \) (the distance from the origin along that angle).
06
Sketch the Graph
Connect the plotted points to sketch the curve. This graph should show the symmetry and shape typical of a limacon with a loop, extending from \( 6 \) units out at \( \theta = 0^{\circ} \) to forming a smaller loop around the pole.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Polar Equations
Polar coordinates allow us to describe points on a plane using a combination of radius and angle, rather than Cartesian coordinates which use x and y. In the polar system:
- Each point is defined by a distance from the origin, called the radius (\( r \)), and an angle (\( \theta \)) from the positive x-axis.
- This system is particularly useful for equations describing circular and spiral-like shapes, which we call polar equations.
- Choose angles \( \theta \) often in multiples of \( 45^{\circ} \); these are easy to compute in trigonometric terms and translate well into radians.
- For each angle, compute the radius (\( r \)), allowing you to plot points on a polar graph paper.
Limacon
The graph of \( r = 6 \cos \theta \) illustrates a unique type of curve known as a limacon. Limacons are special because they can take on different forms based on certain parameters in their equations. Here are some characteristics:
- When the cosine function is involved, like in our equation, the limacon is oriented horizontally.
- Limacons may have inner loops, a dimple, or they may appear to be just a cardioid shape, depending largely on the coefficients in the equation.
- For the equation \( r = 6 \cos \theta \), the graph forms a limacon with an inner loop. The loop is visible because the radius (\( r \)) can become negative, pulling the loop inside and crossing the pole.
Trigonometric Functions
Trigonometric functions, like sine and cosine, play a crucial role in polar equations. They are periodic and oscillate between a maximum and minimum value, which influences the radius (\( r \)) in polar graphs.Consider \( r = 6 \cos \theta \):
- The cosine function varies between -1 and 1, meaning \( r \) will range from \(-6\) to \(6\) as \( \theta \) changes.
- At \( \theta = 0^{\circ} \) and \( \theta = 360^{\circ} \), \( \cos \theta \) is 1, giving the maximum radius of 6.
- Meanwhile, at \( \theta = 90^{\circ} \) and \( \theta = 270^{\circ} \), \( \cos \theta \) is 0, providing no radius, or zero distance from the origin.