Chapter 8: Problem 33
Find the five fifth roots of \(z=10^{5}\) cis \(15^{\circ}\). Write each root in trigonometric form and then give a decimal approximation, accurate to the nearest hundredth, for each one.
Short Answer
Expert verified
The five fifth roots are: \( 9.98 + 0.52i \), \( 2.59 + 9.66i \), \( -8.47 + 5.39i \), \( -8.89 - 4.54i \), \( 2.59 - 9.66i \).
Step by step solution
01
Identify Equation
We start with a complex number given in polar form. The problem states \( z = 10^5 \text{ cis } 15^\circ \). In polar form, this is \( z = r \text{ cis } \theta \), where \( r = 10^5 \) and \( \theta = 15^\circ \).
02
Apply De Moivre's Theorem
De Moivre's Theorem tells us how to find the roots of a complex number. For the \( n \)-th roots, we use \[ z_k = r^{1/n} \text{ cis } \left( \frac{\theta}{n} + \frac{k360^\circ}{n} \right) \] for \( k = 0, 1, 2, 3, 4 \). Here, \( n = 5 \).
03
Calculate Magnitude of Roots
Determine the magnitude of the roots, which will be \( r^{1/5} = (10^5)^{1/5} = 10 \).
04
Calculate Each Root Angle
For each value of \( k \), compute the angle: \( \frac{15^\circ}{5} + \frac{k \times 360^\circ}{5} \). Calculate for each \( k \) from 0 to 4:- \( k=0 \): \( 3^\circ \)- \( k=1 \): \( 75^\circ \)- \( k=2 \): \( 147^\circ \)- \( k=3 \): \( 219^\circ \)- \( k=4 \): \( 291^\circ \).
05
Express Each Root in Trigonometric Form
Now, use the magnitude and each angle to express the roots in trigonometric form:- \( z_0 = 10 \text{ cis } 3^\circ \)- \( z_1 = 10 \text{ cis } 75^\circ \)- \( z_2 = 10 \text{ cis } 147^\circ \)- \( z_3 = 10 \text{ cis } 219^\circ \)- \( z_4 = 10 \text{ cis } 291^\circ \).
06
Convert to Decimal Approximation
Convert each root to decimal form using the trigonometric identities: \( z_k = 10 \cdot (\cos(a) + i\sin(a)) \), where \( a \) is the angle in degrees:- \( z_0 = 9.98 + 0.52i \)- \( z_1 = 2.59 + 9.66i \)- \( z_2 = -8.47 + 5.39i \)- \( z_3 = -8.89 - 4.54i \)- \( z_4 = 2.59 - 9.66i \). Round each component to the closest hundredth.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
De Moivre's Theorem
De Moivre's Theorem is a powerful tool in complex number theory that simplifies working with powers and roots of complex numbers. It states that for any complex number in polar form, \[ z = r (\cos \theta + i \sin \theta) \]where \( n \) is a positive integer, then the \( n \)-th power of \( z \) is given by:\[ z^n = r^n (\cos(n \theta) + i \sin(n \theta)) \]This theorem also extends to roots, allowing us to easily find the \( n \)-th roots of a complex number. Here's how to apply it:
- Write the complex number in polar form.
- Calculate the magnitude of each root by taking the \( n \)-th root of the original magnitude.
- Determine each root's angle by dividing the original angle by \( n \) then adding \( \frac{2\pi k}{n} \) (or \( \frac{360^\circ k}{n} \) in degrees) for each integer \( k \) from 0 to \( n-1 \).
Polar Form of Complex Numbers
The polar form of complex numbers is a way to express complex numbers using polar coordinates instead of rectangular coordinates. A complex number \( z \) is usually written as \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part. In polar form, the same number is represented as:\[ z = r (\cos \theta + i \sin \theta) \text{ or } z = r \text{ cis } \theta \]Here, \( r \) is the magnitude (or modulus) of the complex number, and \( \theta \) is the argument (or angle). To convert a complex number from rectangular form to polar form, use:
- The magnitude \( r = \sqrt{a^2 + b^2} \).
- The angle \( \theta = \arctan\left(\frac{b}{a}\right) \) measured from the positive x-axis.
Roots of Complex Numbers
Finding roots of complex numbers involves calculating values that, when raised to a specific power, give the original complex number. To find the \( n \)-th roots of a complex number in polar form, leverage both the magnitude and angle:
- Determine the root magnitude as \( r^{1/n} \), being the \( n \)-th root of the original magnitude.
- Calculate the angles \( \theta_k \) for each root using: \( \theta_k = \frac{\theta}{n} + \frac{k360^\circ}{n} \) for each integer \( k \) from 0 to \( n-1 \).
- Discover the magnitude of each root, which is simply: \( 10^5 \) raised to the power of \( \frac{1}{5} \), yielding 10.
- Calculate different angles for \( k = 0, 1, 2, 3, 4 \) to find each unique root's angle.