Chapter 8: Problem 20
Find the three cube roots for each of the following complex numbers. Leave your answers in trigonometric form. $$ 27\left(\cos 303^{\circ}+i \sin 303^{\circ}\right) $$
Short Answer
Expert verified
The cube roots are \( 3(\cos 101^{\circ} + i \sin 101^{\circ}), 3(\cos 221^{\circ} + i \sin 221^{\circ}), \) and \( 3(\cos 341^{\circ} + i \sin 341^{\circ}) \).
Step by step solution
01
Understanding the Problem
We need to find the cube roots of the complex number given in trigonometric form: \( 27(\cos 303^{\circ} + i \sin 303^{\circ}) \). The formula for finding the \( n^{th} \) roots of a complex number \( r(\cos \theta + i \sin \theta) \) is \( \sqrt[n]{r}(\cos(\frac{\theta + 360k}{n}) + i \sin(\frac{\theta + 360k}{n})) \), where \( n \) is the root degree and \( k = 0, 1, 2, \ldots, n-1 \).
02
Applying the Cube Root Formula
In our case, we want to find the cube roots, so \( n = 3 \), \( r = 27 \), and \( \theta = 303^{\circ} \). The cube roots will be calculated by evaluating the expression \( 3\sqrt{27}(\cos(\frac{303^{\circ} + 360^{\circ}k}{3}) + i \sin(\frac{303^{\circ} + 360^{\circ}k}{3})) \) for \( k = 0, 1, \) and \( 2 \).
03
Calculate Magnitude of the Roots
First, calculate the magnitude: \( \sqrt[3]{27} = 3 \). So the magnitude of each root is 3.
04
Calculate the Angles for each Root
For \( k = 0 \):\[\theta_0 = \frac{303^{\circ} + 360^{\circ} \cdot 0}{3} = 101^{\circ}\]For \( k = 1 \):\[\theta_1 = \frac{303^{\circ} + 360^{\circ} \cdot 1}{3} = 221^{\circ}\]For \( k = 2 \):\[\theta_2 = \frac{303^{\circ} + 360^{\circ} \cdot 2}{3} = 341^{\circ}\]
05
Presenting the Roots in Trigonometric Form
The three cube roots are:1. \( 3(\cos 101^{\circ} + i \sin 101^{\circ}) \)2. \( 3(\cos 221^{\circ} + i \sin 221^{\circ}) \)3. \( 3(\cos 341^{\circ} + i \sin 341^{\circ}) \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trigonometric Form of Complex Numbers
Complex numbers can be a bit tricky because they have a real part and an imaginary part. To make them easier to work with, we often use their trigonometric form. This form uses a radial distance from the origin and an angle from the positive x-axis, making it ideal for calculating roots and powers. A complex number in trigonometric form is written as \( r(\cos \theta + i \sin \theta) \), where:
- \( r \) is the magnitude, or modulus of the complex number, representing how far away it is from the origin.
- \( \theta \) is the angle, or argument, representing the direction of the complex number from the positive x-axis.
Nth Roots of Complex Numbers
Finding the \( n \)th roots of a complex number can sound daunting, but with the right formula, it becomes straightforward. The roots are based on a formula where you take the magnitude and divide the angle by the root's degree. For a complex number in the form \( r(\cos \theta + i \sin \theta) \), the formula for its \( n \)th roots is:
- \( \sqrt[n]{r}(\cos(\frac{\theta + 360^\circ k}{n}) + i \sin(\frac{\theta + 360^\circ k}{n})) \)
- Where \( k = 0, 1, 2, \ldots, n-1 \)
Complex Number Calculations
Performing calculations with complex numbers involves both their magnitude and angle, especially in trigonometric form. Here's how to handle a few operations neatly:**Calculating Magnitude:** For a complex number \( z = a + bi \), its magnitude is \( |z| = \sqrt{a^2 + b^2} \). In trigonometric form, for any \( z = r(\cos \theta + i \sin \theta) \), \( r \) is the magnitude.**Angle Calculations:** The angle is typically found with \( \theta = \text{atan2}(b, a) \), producing a value in degrees or radians that places the complex number on the complex plane.For operations such as multiplication, division, and finding powers or roots, work in trigonometric form:
- **Multiplication and Division:** Add or subtract angles when multiplying or dividing complex numbers, and multiply or divide their magnitudes, respectively.
- **Powers and Roots:** For powers, multiply the angle, and for roots, divide it, following the rules provided by De Moivre’s Theorem.