Chapter 6: Problem 5
Find all solutions if \(0^{\circ} \leq \theta<360^{\circ}\). Verify your answer graphically. $$ \sin 2 \theta=\frac{\sqrt{3}}{2} $$
Short Answer
Expert verified
The solutions are \( \theta = 30^{\circ}, 60^{\circ}, 210^{\circ}, 240^{\circ} \).
Step by step solution
01
Identify key trigonometric equation
Our goal is to solve the equation \( \sin 2\theta = \frac{\sqrt{3}}{2} \). This suggests that we need to find angles where the sine function equals \( \frac{\sqrt{3}}{2} \).
02
Determine reference angles for sine
The sine of \( \frac{\sqrt{3}}{2} \) corresponds to the angles \( 60^{\circ} \) and \( 120^{\circ} \) within the interval \( 0^{\circ} \leq x < 360^{\circ} \).
03
Solve for \( 2\theta \)
Since \( \sin 2\theta = \frac{\sqrt{3}}{2} \), we find the values for \( 2\theta \) as \( 2\theta = 60^{\circ}, 120^{\circ}, 60^{\circ} + 360^{\circ}k, 120^{\circ} + 360^{\circ}k \), where \( k \) is an integer.
04
Solve for \( \theta \)
Solve for \( \theta \) in \( \theta = \frac{60^{\circ}}{2}, \frac{120^{\circ}}{2}, \frac{420^{\circ}}{2}, \frac{480^{\circ}}{2}, \ldots \). Each of these gives \( \theta = 30^{\circ}, 60^{\circ}, 210^{\circ}, 240^{\circ} \).
05
Verify solutions graphically
Graph \( y = \sin 2\theta \) and \( y = \frac{\sqrt{3}}{2} \) within the range \( 0^{\circ} \leq \theta < 360^{\circ} \). The intersections of these graphs should occur at the \( \theta \) values solved above, which are \( 30^{\circ}, 60^{\circ}, 210^{\circ}, 240^{\circ} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sine Function
The sine function is a fundamental concept in trigonometry. It measures the y-coordinate of a point on a unit circle, which is a circle with a radius of 1 unit, as it rotates around its center. For any angle \( \theta \), the sine value ranges from -1 to 1.
The sine of an angle is periodic with a period of \( 360^{\circ} \), meaning it repeats its values every \( 360^{\circ} \). This function is useful for modeling various oscillatory phenomena like sound waves or tides. Understanding the sine function helps in solving equations like \( \sin 2\theta = \frac{\sqrt{3}}{2} \), where we seek specific angles within a defined range for which the sine value matches a given number.
Some properties to remember about the sine function:
The sine of an angle is periodic with a period of \( 360^{\circ} \), meaning it repeats its values every \( 360^{\circ} \). This function is useful for modeling various oscillatory phenomena like sound waves or tides. Understanding the sine function helps in solving equations like \( \sin 2\theta = \frac{\sqrt{3}}{2} \), where we seek specific angles within a defined range for which the sine value matches a given number.
Some properties to remember about the sine function:
- It is an odd function, implying \( \sin(-\theta) = -\sin(\theta) \).
- The graph of the sine function is a smooth wave that extends indefinitely in both directions.
Angle Solutions
When tasked with solving for angles corresponding to a specific sine value, it is essential to leverage known reference angles and the periodic nature of trigonometric functions. With \( \sin 2\theta = \frac{\sqrt{3}}{2} \), we recognize this sine value from common angles such as \( 60^{\circ} \) and \( 120^{\circ} \).
Since we are solving for \( 2\theta \), we calculate the possible values as multiples of these reference angles:
This periodic adjustment ensures no solutions are missed. Dividing each result by 2 gives the solutions for \( \theta \), leading us to angles \( 30^{\circ}, 60^{\circ}, 210^{\circ} \), and \( 240^{\circ} \). These solutions fall within the initial \( 0^{\circ} \leq \theta < 360^{\circ} \) range.
Since we are solving for \( 2\theta \), we calculate the possible values as multiples of these reference angles:
- \( 2\theta = 60^{\circ} \) and \( 2\theta = 120^{\circ} \)
- Accounting for periodicity, \( 2\theta = 60^{\circ} + 360^{\circ}k \) and \( 2\theta = 120^{\circ} + 360^{\circ}k \) where \( k \) is an integer.
This periodic adjustment ensures no solutions are missed. Dividing each result by 2 gives the solutions for \( \theta \), leading us to angles \( 30^{\circ}, 60^{\circ}, 210^{\circ} \), and \( 240^{\circ} \). These solutions fall within the initial \( 0^{\circ} \leq \theta < 360^{\circ} \) range.
Graphical Verification
Graphical verification is a powerful method for confirming analytical solutions in trigonometry. By plotting the functions \( y = \sin 2\theta \) and \( y = \frac{\sqrt{3}}{2} \) on the same graph and observing their intersections, we can visually check our calculated angle solutions.
The graph of \( \sin 2\theta \) will show a wave that repeats every \( 180^{\circ} \), due to the doubled angle inside the sine function. It results in two full oscillations between 0 and \( 360^{\circ} \). The line \( y = \frac{\sqrt{3}}{2} \) is a horizontal line intersecting the sine wave at specific points corresponding to the solutions we found analytically.
By marking the intersections, we confirm that they occur at \( \theta = 30^{\circ}, 60^{\circ}, 210^{\circ}, \) and \( 240^{\circ} \). This graphical approach not only verifies our work but also provides a visual understanding of how the trigonometric functions interact within the given domain.
The graph of \( \sin 2\theta \) will show a wave that repeats every \( 180^{\circ} \), due to the doubled angle inside the sine function. It results in two full oscillations between 0 and \( 360^{\circ} \). The line \( y = \frac{\sqrt{3}}{2} \) is a horizontal line intersecting the sine wave at specific points corresponding to the solutions we found analytically.
By marking the intersections, we confirm that they occur at \( \theta = 30^{\circ}, 60^{\circ}, 210^{\circ}, \) and \( 240^{\circ} \). This graphical approach not only verifies our work but also provides a visual understanding of how the trigonometric functions interact within the given domain.