Chapter 5: Problem 10
Factor each expression completely.a. \(x^{4}-y^{4}\) b. \(\sin ^{4} \theta-\cos ^{4} \theta\)
Short Answer
Expert verified
a. \((x-y)(x+y)(x^2+y^2)\); b. \(\sin^2\theta - \cos^2\theta\).
Step by step solution
01
Identify the Difference of Squares
Notice that both expressions, part a and part b, have terms raised to the fourth power. They can be rewritten as the difference of squares since \[ a^4 - b^4 = (a^2)^2 - (b^2)^2. \] This allows us to use the difference of squares formula, \( a^2 - b^2 = (a - b)(a + b). \)
02
Factor Part a: Initial Application
Apply the difference of squares formula to factor the expression \( x^4 - y^4 \):\[ x^4 - y^4 = (x^2)^2 - (y^2)^2 = (x^2 - y^2)(x^2 + y^2). \]
03
Factor Part a: Recursive Factorization
Notice that \( x^2 - y^2 \) is itself a difference of squares, and it can be further factored:\[ x^2 - y^2 = (x-y)(x+y). \]Thus, the complete factorization for part a is:\[ x^4 - y^4 = (x-y)(x+y)(x^2 + y^2). \]
04
Factor Part b: Initial Application
Apply the difference of squares formula to factor the expression \( \sin^4 \theta - \cos^4 \theta \):\[ \sin^4 \theta - \cos^4 \theta = (\sin^2 \theta)^2 - (\cos^2 \theta)^2 = (\sin^2 \theta - \cos^2 \theta)(\sin^2 \theta + \cos^2 \theta). \]
05
Factor Part b: Simplification Using Trigonometric Identity
Recall the Pythagorean identity \sin^2 \theta + \cos^2 \theta = 1. Using this identity simplifies the expression further:\[ \sin^2 \theta + \cos^2 \theta = 1, \]thus\[ \sin^4 \theta - \cos^4 \theta = (\sin^2 \theta - \cos^2 \theta)(1). \]This leaves us with the factorization:\[ \sin^4 \theta - \cos^4 \theta = \sin^2 \theta - \cos^2 \theta. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference of Squares
The difference of squares is a special algebraic formula used for simplifying expressions where two square terms are subtracted. The formula is given by:
For example, given any expression like \(x^4 - y^4\), it can also be seen as \( (x^2)^2 - (y^2)^2 \). This is a direct application of the difference of squares formula, which then simplifies to:
- \(a^2 - b^2 = (a - b)(a + b)\).
For example, given any expression like \(x^4 - y^4\), it can also be seen as \( (x^2)^2 - (y^2)^2 \). This is a direct application of the difference of squares formula, which then simplifies to:
- \((x^2 - y^2)(x^2 + y^2)\).
Factorization
Factorization is the process of breaking down a complex expression into simpler multiplicative components. This is akin to finding what numbers multiply together to give the original expression.
When it comes to trigonometric expressions, such as \(\sin^4 \theta - \cos^4 \theta\), similar factorization steps can be applied. Initially, you rewrite it using the difference of squares formula, but simplification may also involve other identities.
- For instance, factoring \(x^4 - y^4\) starts with recognizing that it's a difference of squares. So it becomes \((x^2 - y^2)(x^2 + y^2)\).
- Upon further observation, \(x^2 - y^2\) is again a difference of squares, which gives \((x-y)(x+y)\) when factored fully.
When it comes to trigonometric expressions, such as \(\sin^4 \theta - \cos^4 \theta\), similar factorization steps can be applied. Initially, you rewrite it using the difference of squares formula, but simplification may also involve other identities.
Pythagorean Identity
The Pythagorean identity is a fundamental trigonometric identity. It stems from the Pythagorean theorem in geometry but applies to trigonometric functions. The most common form of the Pythagorean identity is:
This simplification transforms the factored expression \((\sin^2 \theta - \cos^2 \theta)(\sin^2 \theta + \cos^2 \theta)\) into \((\sin^2 \theta - \cos^2 \theta)\cdot1\), effectively leaving us with:
- \(\sin^2 \theta + \cos^2 \theta = 1\).
This simplification transforms the factored expression \((\sin^2 \theta - \cos^2 \theta)(\sin^2 \theta + \cos^2 \theta)\) into \((\sin^2 \theta - \cos^2 \theta)\cdot1\), effectively leaving us with:
- \(\sin^2 \theta - \cos^2 \theta\).