Chapter 4: Problem 52
For each equation, identify the amplitude, period, horizontal shift, and phase. Then label the axes accordingly and sketch one complete cycle of the curve. $$ y=3 \cos \left(\frac{\pi}{3} x-\frac{\pi}{3}\right) $$
Short Answer
Expert verified
Amplitude is 3, period is 6, horizontal shift is 1 unit to the right.
Step by step solution
01
Identify the amplitude
The formula for a cosine function is given by \[y = a \cos(bx - c) + d\]In this equation, the amplitude is the absolute value of \(a\). Therefore, for the given function \[y = 3 \cos \left(\frac{\pi}{3} x - \frac{\pi}{3} \right),\] the amplitude is \(3\).
02
Determine the period
The period of a cosine function is determined by the formula \[\frac{2\pi}{|b|},\]where \(b\) is the coefficient of \(x\). For the given function, \(b = \frac{\pi}{3}\). So,\[\text{Period} = \frac{2\pi}{\frac{\pi}{3}} = 6.\]
03
Calculate the horizontal shift
The horizontal shift, also known as the phase shift, is determined by \(\frac{c}{b}\) from the cosine function\[y = a \cos(bx - c) + d.\]For the given function, \(c = \frac{\pi}{3}\) and \(b = \frac{\pi}{3}\). Thus,\[\text{Horizontal Shift} = \frac{\frac{\pi}{3}}{\frac{\pi}{3}} = 1.\]This shift is to the right since the expression is \(-\frac{\pi}{3}\).
04
Sketch the axes and graph one complete cycle
Now that we have all the transformations, we can sketch the function:- The amplitude is \(3\), meaning the graph will oscillate 3 units above and below the midline \(y = 0\).- The period is \(6\), so one full cycle from start to finish will span a horizontal length of 6 units.- There is a horizontal shift of \(1\) unit to the right.Label the x-axis from 0 to 6 appropriately to capture one cycle. The curve starts at \(x = 1\) and ends at \(x = 7\). Label the y-axis from -3 to 3 to represent the amplitude limits. Draw a cosine curve beginning from \(y = 3\) at \(x = 1\), reaching \(y = -3\) at \(x = 4\) (midpoint), and returning to \(y = 3\) at \(x = 7\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Amplitude
The amplitude of a trigonometric function indicates how much the function's values oscillate above and below its central axis, which is usually the x-axis.It is the maximum distance from the midline to the peak or trough of the curve. Amplitude is always a positive number and represents the "height" of the wave produced by the cosine expression.
In our given cosine function \[y = 3 \cos \left(\frac{\pi}{3} x - \frac{\pi}{3} \right),\] the amplitude is the absolute value of the number multiplying the cosine.
In our given cosine function \[y = 3 \cos \left(\frac{\pi}{3} x - \frac{\pi}{3} \right),\] the amplitude is the absolute value of the number multiplying the cosine.
- The formula for finding amplitude from a cosine function, \(y = a \cos(bx - c) + d\), is simply \(|a|\).
- So, the amplitude here is \(3\).
Period
The period of a trigonometric function is the horizontal length over which the function completes one full cycle.It's crucial for determining how frequently the wave pattern repeats over the x-axis.
The period for a cosine function \(y = a \cos(bx - c) + d\) is found using the formula \[\text{Period} = \frac{2\pi}{|b|},\] where \(b\) is the coefficient next to \(x\).
The period for a cosine function \(y = a \cos(bx - c) + d\) is found using the formula \[\text{Period} = \frac{2\pi}{|b|},\] where \(b\) is the coefficient next to \(x\).
- For our function, \(b = \frac{\pi}{3}\).
- This makes the period: \[\frac{2\pi}{\frac{\pi}{3}} = 6.\]
Phase Shift
The phase shift, often referred to as horizontal shift, reveals how far and in which direction the graph of a trigonometric function is shifted from the standard position.It determines where the cycle begins on the x-axis.
Using the standard cosine function \[y = a \cos(bx - c) + d,\] the phase shift can be calculated with the formula\[\frac{c}{b}.\] For the function in question:
Using the standard cosine function \[y = a \cos(bx - c) + d,\] the phase shift can be calculated with the formula\[\frac{c}{b}.\] For the function in question:
- We have \(c = \frac{\pi}{3}\) and \(b = \frac{\pi}{3}\).
- The phase shift becomes \[\frac{\frac{\pi}{3}}{\frac{\pi}{3}} = 1.\]
Cosine Function
The cosine function is one of the fundamental trigonometric functions.It is periodic and oscillates in a wave-like manner, commonly used to model real-world phenomena like sound waves and tides.
A typical cosine function is expressed as \[y = a \cos(bx - c) + d,\] where each parameter affects the graph:
A typical cosine function is expressed as \[y = a \cos(bx - c) + d,\] where each parameter affects the graph:
- \(a\): Determines the amplitude, impacting how tall and short the waves are.
- \(b\): Influences the period, affecting how quickly the waves repeat.
- \(c\): Controls the phase shift, moving the graph left or right.
- \(d\): Adjusts the vertical shift, raising or lowering the graph on the y-axis.