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Graph one complete cycle of each of the following equations. Be sure to label the \(x\) - and \(y\)-axes so that the amplitude, period, and horizontal shift for each graph are easy to see. $$y=\sin \left(x+\frac{\pi}{6}\right)$$

Short Answer

Expert verified
One cycle of \( y = \sin\left(x + \frac{\pi}{6}\right) \) shifts left by \( \frac{\pi}{6} \), with amplitude 1 and period \( 2\pi \).

Step by step solution

01

Understanding the Sine Function

The general form of the sine function is given by: \[ y = a \sin(bx + c) + d \] where: - Amplitude = \( |a| \) - Period = \( \frac{2\pi}{|b|} \)- Phase shift (horizontal shift) = \(-\frac{c}{b}\) - Vertical shift = \(d\)
02

Identify Parameters in the Given Function

The given function is \( y = \sin\left(x + \frac{\pi}{6}\right) \). Identify the parameters:- \(a = 1\) (Amplitude is 1)- \(b = 1\) (Period is \( 2\pi \))- \(c = \frac{\pi}{6}\) (Horizontal shift is \(-\frac{\pi}{6}\))- \(d = 0\) (No vertical shift)
03

Determine the Amplitude and Period

For the function \( y = \sin\left(x + \frac{\pi}{6}\right) \):- Amplitude = \( |a| = 1 \)- Period = \( \frac{2\pi}{1} = 2\pi \)
04

Calculate the Phase Shift

The phase shift is the horizontal shift of the graph. For \( y = \sin\left(x + \frac{\pi}{6}\right) \): - Phase shift = \(-\frac{\pi}{6}\) This means the graph is shifted left by \( \frac{\pi}{6} \).
05

Graphing the Function

Start by graphing the standard sine function \( y = \sin(x) \) with an amplitude of 1 and period \( 2\pi \). Then, shift the graph left by \( \frac{\pi}{6} \).- Mark the x-axis from \(-\frac{\pi}{6} \) to \( \frac{11\pi}{6} \) for one cycle of \( 2\pi \). - Label the critical points: starting point at \(-\frac{\pi}{6} \), maximum at \( \frac{\pi}{3} \), zero at \( \frac{5\pi}{6} \), minimum at \( \frac{7\pi}{6} \), and ending back at zero at \( \frac{11\pi}{6} \).- Amplitude is marked from -1 to 1 on the y-axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amplitude
The amplitude in a sine function refers to the height of the wave from its middle point to its peak. It shows how far up or down the wave stretches from the center line, which runs horizontally through the middle of the wave. If the wave were music, the amplitude would be the volume level. The higher the amplitude, the louder the sound.

In the function given by the equation \( y = \sin(x + \frac{\pi}{6}) \), the amplitude is determined by the coefficient "a" in front of the sine. As there is no visible coefficient (other than 1), the amplitude is 1. This means that from the sine wave's central axis (often the x-axis), it reaches 1 unit up to its peak and 1 unit down to its lowest point. Here's why it matters: when you graph the sine wave, the highest point of your curve (the crest) is at \( y = 1 \), and the lowest point (the trough) is at \( y = -1 \).

Understanding amplitude helps us visualize how intense or mild the variations in the sine wave will appear. It's particularly important as it remains consistent throughout one cycle of the wave, making it easier to predict the shape of the graph.
Period
The period of a sine function tells us how long it takes for the wave to complete one full cycle. It's like a repeating pattern. Once the function completes a cycle, it starts over. You can think of it like a looped track—once each complete loop of the track is done, another begins right after.

In the equation for a sine function, the period is derived from the expression \( \frac{2\pi}{|b|} \). In the function \( y = \sin(x + \frac{\pi}{6}) \), the value of "b" is 1. So, substituting into the formula, we find that our period is \( \frac{2\pi}{1} = 2\pi \).

This means that one full cycle of the sine wave spans a horizontal distance of \( 2\pi \) units. Along this distance, the wave starts at a middle position, climbs to a peak, descends through the middle, reaches its lowest dip, and returns back to the starting level—this entire sequence repeats every \( 2\pi \) units along the x-axis. A consistent period helps anticipate where the wave will be at any point, crucial for plotting the graph accurately.
Phase Shift
Phase shift in a sine function is all about horizontal movement. It indicates how the entire wave shifts left or right along the x-axis. This shift is like moving the starting point of the wave without changing its shape.

The formula for determining phase shift is \( -\frac{c}{b} \). In our function \( y = \sin(x + \frac{\pi}{6}) \), we identify "c" as \( \frac{\pi}{6} \) and "b" as 1. Plugging these into the phase shift formula, we get:
  • Phase Shift = \(-\frac{\pi}{6}\)
This negative sign indicates the wave shifts to the left along the x-axis by \( \frac{\pi}{6} \) units. In other words, the graph of the sine wave starts its cycle \( \frac{\pi}{6} \) units earlier than if there were no phase shift.

By understanding the phase shift of a sine function, you can accurately position your graph. This is essential as it significantly affects where the "starting" and "ending" of each cycle appear on the graph, emphasizing the importance of labeling when plotting.

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Most popular questions from this chapter

Graph one complete cycle of each of the following. In each case, label the axes accurately and identify the amplitude for each graph. $$ y=-4 \sin x $$

A pendulum swings back and forth. The angular displacement \(\theta\) of the pendulum from its rest position after \(t\) seconds is given by the function \(\theta=20 \cos (3 \pi t)\), where \(\theta\) is measured in degrees (Figure 14). a. Sketch the graph of this function for \(0 \leq t \leq 6\). b. What is the maximum angular displacement? c. How long does it take for the pendulum to complete one oscillation?

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