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91Ó°ÊÓ

Work each of the following problems on your calculator. Do not write down or round off any intermediate answers. $$ \cos ^{2} 58^{\circ}+\sin ^{2} 58^{\circ} $$

Short Answer

Expert verified
The expression equals 1, using the Pythagorean identity.

Step by step solution

01

Understand the Identity

We need to solve the expression \(\cos^2 58^{\circ} + \sin^2 58^{\circ}\). Notice that this is a well-known trigonometric identity, which states that for any angle \(\theta\), \( \cos^2 \theta + \sin^2 \theta = 1 \).
02

Apply the Trigonometric Identity

Given the identity \( \cos^2 \theta + \sin^2 \theta = 1 \), we can directly apply this to our given angle, which is \(58^{\circ}\). So, \( \cos^2 58^{\circ} + \sin^2 58^{\circ} = 1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean identity
The Pythagorean identity is one of the fundamental identities in trigonometry. It expresses a simple, yet powerful concept that applies to every angle: the sum of the squares of the cosine function and sine function of any angle is equal to one. Mathematically, it is given by:
  • \(\cos^2 \theta + \sin^2 \theta = 1\)
This identity is crucial because it holds true for any angle \(\theta\), whether in degrees or radians. It essentially captures the core relationship between the sine and cosine functions as they relate to the unit circle.
In the context of the unit circle, the coordinates of any point on the circle can be represented as \((\cos \theta, \sin \theta)\). The Pythagorean identity follows from the equation of the unit circle \(x^2 + y^2 = 1\), where \(x\) is \(\cos \theta\) and \(y\) is \(\sin \theta\).
Understanding and being able to apply the Pythagorean identity allows students to simplify trigonometric expressions and solve trigonometric equations efficiently.
cosine function
The cosine function is a fundamental trigonometric function that deals with the ratio of the adjacent side to the hypotenuse in a right triangle. It is usually denoted by \(\cos\) and is closely linked with the unit circle and wave phenomena.
  • The value of \(\cos \theta\) is the \(x\)-coordinate of the point on the unit circle obtained by rotating the point \((1, 0)\) counterclockwise by an angle \(\theta\) from the positive \(x\)-axis.
  • \(\cos \theta\) ranges from -1 to 1 as \(\theta\) varies from 0 to \(360^{\circ}\) or from \(0\) to \(2\pi\) radians.

The cosine function is periodic with a period of \(360^{\circ}\) or \(2\pi\). This means that the function repeats its values every complete rotation.
Graphically, the cosine function resembles a wave, starting at its maximum value of 1 at \(\theta = 0\), descending through 0 at \(\theta = 90^{\circ}\) or \(\pi/2\), reaching its minimum at -1 at \(\theta = 180^{\circ}\) or \(\pi\), and then returning back to 1.
sine function
The sine function represents another fundamental trigonometric function. It is intimately associated with angles in both right triangles and the unit circle.
  • The sine function is symbolized by \(\sin\) and represents the ratio of the opposite side to the hypotenuse of a right triangle.
  • On the unit circle, \(\sin \theta\) corresponds to the \(y\)-coordinate of a point formed by rotating the radius at an angle \(\theta\) from the origin.

Just like the cosine function, the sine function also has a range of values between -1 and 1. Its graph starts at 0 when \(\theta = 0\), rises to 1 at \(\theta = 90^{\circ}\) or \(\pi/2\), descends back to 0 at \(\theta = 180^{\circ}\) or \(\pi\), and continues down to -1 at \(\theta = 270^{\circ}\) or \(3\pi/2\) before returning to 0 at \(\theta = 360^{\circ}\) or \(2\pi\).
The sine function also exhibits periodicity with a period of \(360^{\circ}\) or \(2\pi\), repeating its pattern consistently as the angle \(\theta\) increases. Understanding the sine function is important for solving various mathematical and real-world trigonometric problems.

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Most popular questions from this chapter

Pat and Tim position themselves \(2.5\) miles apart to watch a missile launch from Vandenberg Air Force Base. When the missile is launched, Pat estimates its bearing from him to be \(\mathrm{S} 75^{\circ} \mathrm{W}\), while Tim estimates the bearing of the missile from his position to be \(\mathrm{N} 65^{\circ} \mathrm{W}\). If Tim is due south of Pat, how far is Tim from the missile when it is launched?

A ship is anchored off a long straight shoreline that runs north and south. From two observation points \(4.5\) miles apart on shore, the bearings of the ship are \(\mathrm{S} 73^{\circ} \mathrm{W}\) and \(\mathrm{N} \mathrm{} 17^{\circ} \mathrm{W}\). What is the distance from the ship to the northernmost observation point? a. \(4.3 \mathrm{mi}\) b. \(14.7 \mathrm{mi}\) c. \(4.7 \mathrm{mi}\) d. \(1.3 \mathrm{mi}\)

From here on, each Problem Set will end with a series of review problems. In mathematics, it is very important to review. The more you review, the better you will understand the topics we cover and the longer you will remember them. Also, there will be times when material that seemed confusing earlier will be less confusing the second time around. The problems that follow review material we covered in Section 1.2. Find \(x\) so that the distance between \((x, 2)\) and \((1,5)\) is \(\sqrt{13}\).

Find \(x\) if the point \((x,-8)\) is on the terminal side of \(\theta\) and \(\sin \theta=-\frac{4}{5}\).

Find exact values for each of the following, if possible. \(\cot 45^{\circ}\)

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