Chapter 6: Problem 66
\(9 x^{2}+4 y^{2}=36\)
Short Answer
Expert verified
The center of the ellipse is at (0,0), the length of the semi-major axis is 2 and the semi-minor axis is 3.
Step by step solution
01
Normalizing the equation
Divide every term by 36 to normalize the equation as \(\frac{x^{2}}{4}+\frac{y^{2}}{9}=1\)
02
Identifying the values of a and b
Now, identify the values of \(a^{2}\) and \(b^{2}\). In the normalized equation, \(a^{2}\) (the denominator of \(x^{2}\)) is 4 and \(b^{2}\) (the denominator of \(y^{2}\)) is 9.
03
Identify the center of the ellipse
The center of the ellipse is given by (h,k), where h and k are the values of x and y that make the equation zero. Since there are no added or subtracted constants in the x and y terms, the center of this ellipse is at (0,0).
04
Find the lengths of the semi-major and semi-minor axes
The length of the semi-major axis is the square root of \(a^{2}\), which is \(\sqrt{4} = 2\). The length of the semi-minor axis is the square root of \(b^{2}\), which is \(\sqrt{9} = 3\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Normalization
Normalization is a crucial step in simplifying the equation of an ellipse. It helps in representing the ellipse in a standard form that is easier to analyze. To normalize an ellipse equation, you divide each term by a constant to make the equation equal to 1. In the given problem, the original equation is
- \(9x^{2} + 4y^{2} = 36\)
- \(\frac{x^{2}}{4} + \frac{y^{2}}{9} = 1\)
Semi-major and Semi-minor Axes
In the context of ellipses, the semi-major axis and the semi-minor axis are key components defining the ellipse's shape and orientation. Once the ellipse equation is normalized as
- \(\frac{x^{2}}{4} + \frac{y^{2}}{9} = 1\)
Equation of an Ellipse
The general equation of an ellipse, when centered at the origin (0,0), takes a specific form in its normalized state:
- \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\)
- \(\frac{x^2}{4} + \frac{y^2}{9} = 1\)