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In Exercises 79-88, sketch the graph of the equation. $$ y=-4 x-1 $$

Short Answer

Expert verified
The graph of the equation \(y = -4x -1\) is a straight line passing through the points (0, -1) and (1, -5).

Step by step solution

01

Identify the slope and y-intercept

In the given equation \(y = -4x - 1\), the coefficient of \(x\) corresponds to the slope \(m\) and the constant term is the y-intercept \(b\). Therefore, the slope of the line \(m\) is -4 and the y-intercept \(b\) is -1.
02

Plot the y-intercept

Begin the graph by plotting the y-intercept, which is the point (0, -1). The y-intercept is the point where the line crosses the y-axis.
03

Use the slope to find another point

The slope of the line is -4, which can be thought of as the fraction \(-4/1\). This indicates a reduction of 4 in \(y\) for each increment of 1 in \(x\). Starting from the y-intercept (0, -1), one could go down 4 units and right 1 unit to find another point on line. This gives us the point (1, -5).
04

Plot the line

Now that we have two points, (0, -1) and (1, -5), we can draw a straight line through these points. This line represents the graph of the equation \(y = -4x - 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope and Y-intercept
The slope and y-intercept are essential components of linear equations. In the equation of a line in slope-intercept form, which is written as y = mx + b, the slope is represented by m, and the y-intercept by b.

The slope measures the steepness of the line, indicating how much the value of y changes for a unit change in x. A positive slope means the line ascends as it moves from left to right, while a negative slope means it descends, which is evident in our exercise equation y = -4x - 1 where the slope is -4. This tells us the line falls 4 units for every 1 unit it moves to the right.

The y-intercept is the point where the graph of the equation crosses the y-axis. In our equation, the y-intercept is -1, which translates to the point (0, -1) on a graph. This is the starting point for plotting the line on the coordinate system, and from there, the slope is used to determine the direction and steepness.
Plotting Points
To visualize a linear equation, one can create its graph by plotting points. First, one must locate the y-intercept on the graph. As in our problem, with the y-intercept at (0, -1), you would place a point on the graph where x is 0 and y is -1.

After marking the y-intercept, the next step is to use the slope to find another point. The slope -4 can be interpreted as a ratio: -4/1. This means for each step rightward along the x-axis (an increase in x), y decreases by 4 units. From the y-intercept, you move 1 unit to the right (for x) and 4 units down (for y), landing at the point (1, -5), which is then plotted.

With two points plotted, a straight line drawn through them represents the graph of the given linear equation. Remember, any two distinct points are enough to define a line, but you may plot more points to ensure accuracy, especially when working by hand or if the slope is a fraction.
Linear Equation Representation
The way we write a linear equation can greatly impact how easily we can graph it. Our standard form is the slope-intercept form, y = mx + b, because it readily provides the slope and y-intercept, vital for graphing. With the slope-intercept form, the correlation between the algebraic equation and the graphical representation becomes clear.

In a linear equation representation, every combination of x and y that satisfies the equation can be shown as a point on the line when graphed. This aligns with the principle that the graph of a linear equation in two variables is a straight line. The slope shows the direction and tilt of this line, while the y-intercept provides the specific location where the line intersects the y-axis.

In the education example y = -4x - 1, by simply looking at the equation, we can understand that we're working with a decreasing line that crosses the y-axis just below the origin. Knowing the forms and how to interpret them builds a bridge from numerical expressions to visual graphing, a key skill in understanding linear relationships in algebra.

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