/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 Use the properties of logarithms... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the properties of logarithms to expand the expression as a sum, difference, and/or constant multiple of logarithms. (Assume all variables are positive.) $$ \ln \frac{6}{\sqrt{x^{2}+1}} $$

Short Answer

Expert verified
The expanded form of the given expression is \(\ln(6) -0.5 * \ln(x^{2}+1)\).

Step by step solution

01

Identify the logarithmic properties

To solve this problem, we need to use the properties of logarithms which are quotient rule, \(\ln(a/b) = \ln(a) - \ln(b)\) and square root rule, \(\ln(\sqrt{x} ) = 0.5 * \ln(x)\).
02

Apply the quotient rule

Applying the quotient rule to this expression, we get: \(\ln(6) - \ln(\sqrt{x^{2}+1})\)
03

Apply the root rule

Now we can apply the root rule to \(\ln(\sqrt{x^{2}+1})\). This gives us the following equation: \(\ln(6) -0.5 * \ln(x^{2}+1)\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule
One of the key properties of logarithms is the Quotient Rule. This rule helps us break down the logarithm of a division into a simpler form. It states that the logarithm of a quotient is the difference between the logarithms of the numerator and the denominator.

The rule can be expressed as follows:
\[\ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b)\]

This means that when you have the logarithm of a fraction, you can split it into separate logarithms for the top (numerator) and bottom (denominator), with a minus sign in between. This transformation helps simplify complex logarithmic expressions into more manageable pieces.

For example, in our given expression \(\ln\left(\frac{6}{\sqrt{x^2 + 1}}\right)\), applying the Quotient Rule allows us to separate it into \(\ln(6) - \ln(\sqrt{x^2 + 1})\). This step is crucial for further simplifying the expression by using additional logarithmic properties.
Logarithmic Expansion
Logarithmic Expansion refers to the process of breaking down a complex logarithmic expression into simpler terms. This allows easier manipulation and understanding of the components involved.

There are several properties and rules utilized in logarithmic expansion, such as the Quotient Rule, Product Rule, and Power Rule. Each of these rules helps in rewriting the logarithms in the form of sums, differences, or constants.

Utilizing these rules:
  • The Quotient Rule allows decomposition of a division into subtraction.
  • The Product Rule lets you turn multiplication within a logarithmic argument into an addition.
  • The Power Rule allows coefficients to be moved outside the logarithm as multiples.
In our exercise, once we applied the Quotient Rule and wrote \(\ln(6) - \ln(\sqrt{x^2 + 1})\), the expression is ready for further breakdown using another logarithmic property: the Square Root Rule. This process exemplifies logarithmic expansion: converting a complex expression into a form that shows individual components clearly and distinctly.
Square Root Rule
The Square Root Rule is a helpful property when dealing with logarithms of square roots. It allows us to transform the expression into a simpler form that is easier to work with.

This rule states:
\[\ln(\sqrt{x}) = 0.5 \cdot \ln(x)\]

Essentially, when you encounter a logarithm of a square root, you can express it as one-half of the logarithm of the radicand (the number inside the square root).

Applying this rule to our solution, we take \(\ln(\sqrt{x^2 + 1})\) and rewrite it as \(0.5 \cdot \ln(x^2 + 1)\).

This transformation illustrates the power of the Square Root Rule in simplifying complex expressions and making them more tractable. It turns a nested operation—taking the logarithm of a square root—into a simpler multiplication operation, often paving the way for easier computations or further manipulation in algebraic or calculus contexts.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

\(e^{-4.1}=0.0165 \ldots\)

A $$\$ 120,000$$ home mortgage for 35 years at \(7 \frac{1}{2} \%\) has a monthly payment of $$\$ 809.39$$. Part of the monthly payment is paid toward the interest charge on the unpaid balance, and the remainder of the payment is used to reduce the principal. The amount that is paid toward the interest is $$ u=M-\left(M-\frac{P r}{12}\right)\left(1+\frac{r}{12}\right)^{12 t} $$ and the amount that is paid toward the reduction of the principal is $$ v=\left(M-\frac{P r}{12}\right)\left(1+\frac{r}{12}\right)^{12 t} $$ In these formulas, \(P\) is the size of the mortgage, \(r\) is the interest rate, \(M\) is the monthly payment, and \(t\) is the time in years. (a) Use a graphing utility to graph each function in the same viewing window. (The viewing window should show all 35 years of mortgage payments.) (b) In the early years of the mortgage, is the larger part of the monthly payment paid toward the interest or the principal? Approximate the time when the monthly payment is evenly divided between interest and principal reduction. (c) Repeat parts (a) and (b) for a repayment period of 20 years \((M=\$ 966.71)\). What can you conclude?

The population \(P\) (in millions) of Russia from 1996 to 2004 can be approximated by the model \(P=152.26 e^{-0.0039 t}\), where \(t\) represents the year, with \(t=6\) corresponding to 1996 . (Source: Census Bureau, International Data Base) (a) According to the model, is the population of Russia increasing or decreasing? Explain. (b) Find the population of Russia in 1998 and \(2000 .\) (c) Use the model to predict the population of Russia in \(2010 .\)

Use the properties of logarithms to rewrite and simplify the logarithmic expression. \(\log _{2}\left(4^{2} \cdot 3^{4}\right)\)

Compound Interest In Exercises 57-60, complete the table to determine the balance \(A\) for $$\$ 12,000$$ invested at rate \(r\) for \(t\) years, compounded continuously. \(\begin{array}{|l|l|l|l|l|l|} \hline t & 10 & 20 & 30 & 40 & 50 \\ \hline A & & & & & \\ \hline \end{array}\) $$ r=6 \% $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.