/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 In Exercises 1-8, find the dot p... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises 1-8, find the dot product of \(\mathbf{u}\) and \(\mathbf{v}\). $$ \begin{aligned} &\mathbf{u}=\langle 5,12\rangle \\ &\mathbf{v}=\langle-3,2\rangle \end{aligned} $$

Short Answer

Expert verified
The dot product of \(\mathbf{u}\) and \(\mathbf{v}\) is 9.

Step by step solution

01

Identify the vectors

The vectors given in the exercise are \(\mathbf{u}=\langle 5,12\rangle\) and \(\mathbf{v}=\langle-3,2\rangle\).
02

Apply the dot product formula

The formula to find the dot product of two vectors \(\mathbf{u}=\langle u1,u2\rangle\) and \(\mathbf{v}=\langle v1,v2\rangle\) is \(u1*v1 + u2*v2\). Therefore, the dot product of \(\mathbf{u}\) and \(\mathbf{v}\) can be found by applying the formula :(5*(-3)) + (12*2).
03

Calculate the result

Upon applying the formula in the previous step we get: -15 +24 = 9. So, the dot product of \(\mathbf{u}\) and \(\mathbf{v}\) is 9.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Vectors
Vectors are fundamental elements in mathematics and physics, symbolizing quantities with both direction and magnitude. A vector is often represented as an arrow, where the length of the arrow denotes the vector's magnitude, and the direction of the arrow indicates the vector's direction. In two-dimensional space, vectors can be expressed in a component form as \(\mathbf{u} = \langle u_1, u_2 \rangle\).
Here, - \(u_1\) represents the horizontal component - \(u_2\) signifies the vertical component
Vectors are essential in various fields such as physics, engineering, and computer science because they help to model and analyze forces, velocities, and displacements. In the problem, the vectors \(\mathbf{u} = \langle 5, 12 \rangle\) and \(\mathbf{v} = \langle -3, 2 \rangle\) can be visualized as arrows in a plane, pointing in their respective directions.
Trigonometry Exercises and Their Role
Trigonometry exercises often involve vectors, as trigonometry provides the tools to analyze angles and distances in a plane. When dealing with vectors, trigonometric concepts like sine, cosine, and tangent help determine angles between vectors or their projections.
These exercises enhance problem-solving skills by combining vector algebra with trigonometric relationships.
  • They help in computing angles between vectors using the dot product.
  • They assist in projecting one vector onto another.
Developing proficiency in trigonometry alongside vectors aids students in comprehending more complex scenarios where vector magnitudes and directions must be calculated relative to specific angles. While the original exercise primarily dealt with the dot product, a strong foundation in trigonometry is crucial for fully understanding vector applications.
Basics of Vector Multiplication
Vector multiplication can happen in several ways, with one common method being the dot product, also known as the scalar product. The dot product is quite straightforward for vectors in two dimensions: \(\mathbf{u} \cdot \mathbf{v} = u_1 \cdot v_1 + u_2 \cdot v_2\).
The result is a scalar (a single number), not another vector. This operation is important because it represents a projection of one vector onto another and calculates the "amount" one vector moves in the direction of another.
Here, the calculation for \(\mathbf{u} = \langle 5, 12 \rangle\) and \(\mathbf{v} = \langle -3, 2 \rangle\) becomes:
  • Multiply the horizontal components: \(5 \cdot (-3) = -15\)
  • Multiply the vertical components: \(12 \cdot 2 = 24\)
  • Add them: \(-15 + 24 = 9\)
Thus, the dot product is 9, providing useful insights into the relationship and alignment of vectors in space.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Circumscribed and Inscribed Circles Let \(R\) and \(r\) be the radii of the circumscribed and inscribed circles of a triangle \(A B C\), respectively (see figure), and let $$ s=\frac{a+b+c}{2} $$ (a) Prove that \(2 R=\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}\). (b) Prove that \(r=\sqrt{\frac{(s-a)(s-b)(s-c)}{s}}\).

In Exercises 39-42, use vectors to find the interior angles of the triangle with the given vertices. $$ (-3,0),(2,2),(0,6) $$

The Leaning Tower of Pisa in Italy is characterized by its tilt. The tower leans because it was built on a layer of unstable soil-clay, sand, and water. The tower is approximately \(58.36\) meters tall from its foundation (see figure). The top of the tower leans about \(5.45\) meters off center. (a) Find the angle of lean \(\alpha\) of the tower. (b) Write \(\beta\) as a function of \(d\) and \(\theta\), where \(\theta\) is the angle of elevation to the sun. (c) Use the Law of Sines to write an equation for the length \(d\) of the shadow cast by the tower. (d) Use a graphing utility to complete the table. $$ \begin{array}{|l|l|l|l|l|l|l|} \hline \theta & 10^{\circ} & 20^{\circ} & 30^{\circ} & 40^{\circ} & 50^{\circ} & 60^{\circ} \\ \hline d & & & & & & \\ \hline \end{array} $$

Velocity A ball is thrown with an initial velocity of 70 feet per second, at an angle of \(35^{\circ}\) with the horizontal (see figure). Find the vertical and horizontal components of the velocity.

In Exercises 29-34, find the area of the triangle having the indicated angle and sides.$$ C=120^{\circ}, \quad a=4, \quad b=6 $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.