Chapter 1: Problem 33
\(f(x)=4 \sin \pi x\) \(g(x)=4 \sin \pi x-3\)
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Chapter 1: Problem 33
\(f(x)=4 \sin \pi x\) \(g(x)=4 \sin \pi x-3\)
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$$ \arcsin \frac{\sqrt{36-x^{2}}}{6}=\arccos (\quad), \quad 0 \leq x \leq 6 $$
When graphing the sine and cosine functions, determining the amplitude is part of the analysis. Explain why this is not true for the other four trigonometric functions.
Prove each identity. (a) \(\arcsin (-x)=-\arcsin x\) (b) \(\arctan (-x)=-\arctan x\) (c) \(\arctan x+\arctan \frac{1}{x}=\frac{\pi}{2}, \quad x>0\) (d) \(\arcsin x+\arccos x=\frac{\pi}{2}\) (e) \(\arcsin x=\arctan \frac{x}{\sqrt{1-x^{2}}}\)
$$ \text { In Exercises 49-58, find the exact value of the expression. } $$ $$ \sec \left[\arctan \left(-\frac{3}{5}\right)\right] $$
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