/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 In Exercises 69-74, use the func... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercises 69-74, use the functions given by \(f(x)=\frac{1}{8} x-3\) and \(g(x)=x^{3}\) to find the indicated value or function. $$ \left(g^{-1} \circ f^{-1}\right)(-3) $$

Short Answer

Expert verified
So, the value of \(\left(g^{-1} \circ f^{-1}\right)(-3)\) is 0.

Step by step solution

01

Find the inverse functions

Firstly, let's find the inverse function of \(f\) and \(g\). For \(f(x)=\frac{1}{8}x - 3\) to find \(f^{-1}(x)\), we replace \(f(x)=y\), swap \(y\) and \(x\), and solve for \(y\):So, we get \(x = \frac{1}{8}y - 3\).Solving for \(y\), we obtain \(f^{-1}(x) = 8x + 24\).Similarly, for \(g(x) = x^3\), to find \(g^{-1}(x)\) we replace \(g(x)=y\), swap \(y\) and \(x\), and solve for \(y\):So, we get \(x = y^3\). Solving for \(y\), we obtain \(g^{-1}(x) = \sqrt[3]{x}\).
02

Find the inverse function of f(-3)

Next, we find the value of \(f^{-1}(-3)\) by substituting -3 into the inverse function of \(f\) which we found in the previous step. So, \(f^{-1}(-3) = 8(-3) + 24 = -24 + 24 = 0\).
03

Find the inverse function of g(f(-3))

Finally, we plug in the result of step 2 into the inverse function of \(g(x)\). So, \(\left(g^{-1} \circ f^{-1}\right)(-3) = g^{-1}(0) = \sqrt[3]{0} = 0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Composition of Functions
The concept of the composition of functions involves taking one function and applying it to the results of another function. This is typically notated as \(f \circ g\)(x), where function \(g\) is applied first, and then function \(f\) is applied to the result of \(g\). In simpler terms, it's like feeding the output of one function directly into another.
In math, understanding function composition helps us see how changes or transformations stack upon each other. For instance, if you first multiply a number by 3 and then add 2, you're applying two different transformations in sequence.
  • The sequence matters: \(f \circ g\) is generally not the same as \(g \circ f\).
  • When dealing with inverse functions, the composition \(f^{-1} \circ f\) should return the starting value.
In our example, the composition \(g^{-1} \circ f^{-1}(-3)\) meant finding the output of \(f^{-1}\) first and then applying \(g^{-1}\) to that result.
Cubic Functions
Cubic functions are polynomial functions where the highest power of the variable, usually denoted as \(x\), is 3. For example, the function \(g(x) = x^3\) is a cubic function. These functions often exhibit interesting behaviors, especially when it comes to graphs.
The shape of a cubic graph has a distinctive 'S' curve and can pass through the x-axis in up to three points. Cubic functions can also have one real root or three real roots, depending on the coefficients found in the equation.
  • They tend to have at least one inflection point, where the graph changes its concavity.
  • They are symmetric around their inflection points, which can help in sketching or understanding their behavior.
The inverse of a cubic function is useful because it 'undoes' whatever the cubic function did. For \(g(x) = x^3\), the inverse is \(g^{-1}(x) = \sqrt[3]{x}\), allowing retrieval of the original value before the cubic transformation.
Linear Functions
Linear functions are perhaps the simplest type of function you will encounter in algebra. They have the form \(f(x) = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.
One of the key characteristics of linear functions is that their graphs are straight lines. This simplicity makes them easy to manipulate and understand compared to more complex functions like quadratic or cubic ones.
  • The slope, \(m\), shows the rate of change, or how steep the line is.
  • The y-intercept, \(b\), tells you where the line crosses the y-axis.
In our example, \(f(x)=\frac{1}{8}x-3\) is a linear function, meaning it has a constant slope and creates a straight line on a graph. The inverse of this function, \(f^{-1}(x) = 8x + 24\), reverses the effect of the original function. This reverse operation gives the x-value back when you have a particular output, like when we find \(f^{-1}(-3)=0\).

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Most popular questions from this chapter

Transportation For groups of 80 or more people, a charter bus company determines the rate per person according to the formula Rate \(=8-0.05(n-80), \quad n \geq 80\) where the rate is given in dollars and \(n\) is the number of people. (a) Write the revenue \(R\) for the bus company as a function of \(n\). (b) Use the function in part (a) to complete the table. What can you conclude? \begin{tabular}{|l|l|l|l|l|l|l|l|} \hline\(n\) & 90 & 100 & 110 & 120 & 130 & 140 & 150 \\ \hline\(R(n)\) & & & & & & & \\ \hline \end{tabular}

In Exercises 55-68, determine whether the function has an inverse function. If it does, find the inverse function. $$ h(x)=-\frac{4}{x^{2}} $$

The number of lumens (time rate of flow of light) \(L\) from a fluorescent lamp can be approximated by the model $$ L=-0.294 x^{2}+97.744 x-664.875, \quad 20 \leq x \leq 90 $$ where \(x\) is the wattage of the lamp. (a) Use a graphing utility to graph the function. (b) Use the graph from part (a) to estimate the wattage necessary to obtain 2000 lumens.

True or False? In Exercises 85 and 86, determine whether the statement is true or false. Justify your answer. Proof Prove that if \(f\) is a one-to-one odd function, then \(f^{-1}\) is an odd function.

Maximum Profit The cost per unit in the production of a portable CD player is \(\$ 60\). The manufacturer charges \(\$ 90\) per unit for orders of 100 or less. To encourage large orders, the manufacturer reduces the charge by \(\$ 0.15\) per CD player for each unit ordered in excess of 100 (for example, there would be a charge of \(\$ 87\) per CD player for an order size of 120 ). (a) The table shows the profit \(P\) (in dollars) for various numbers of units ordered, \(x\). Use the table to estimate the maximum profit. \begin{tabular}{|l|c|c|c|c|} \hline Units, \(x\) & 110 & 120 & 130 & 140 \\ \hline Profit, \(P\) & 3135 & 3240 & 3315 & 3360 \\ \hline \end{tabular} \begin{tabular}{|l|c|c|c|} \hline Units, \(x\) & 150 & 160 & 170 \\ \hline Profit, \(P\) & 3375 & 3360 & 3315 \\ \hline \end{tabular} (b) Plot the points \((x, P)\) from the table in part (a). Does the relation defined by the ordered pairs represent \(P\) as a function of \(x\) ? (c) If \(P\) is a function of \(x\), write the function and determine its domain.

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