/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Determine whether each point lie... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether each point lies on the graph of the equation. \(y=\frac{1}{3} x^3-2 x^2\) (a) \(\left(2,-\frac{16}{3}\right)\) (b) \((-3,9)\)

Short Answer

Expert verified
Point (a) \(\left(2,-\frac{16}{3}\right)\) lies on the graph of the equation. Point (b) \((-3,9)\) does not lie on the graph of the equation.

Step by step solution

01

Substitute Point (a) into the Equation

Start with the first point (a) \(\left(2,-\frac{16}{3}\right)\). Substitute \(x = 2\) into the equation \(y=\frac{1}{3} x^3-2 x^2\). Calculate the value of y.
02

Compare Resultant Y-Coordinate for Point (a)

Compare the resultant y-coordinate from the equation to the y-coordinate of point (a). If they match, then the point lies on the graph of the equation, otherwise not.
03

Substitute Point (b) into the Equation

Now consider the second point (b) \((-3,9)\). Substitute \(x = -3\) into the equation \(y=\frac{1}{3} x^3-2 x^2\). Calculate the value of y.
04

Compare Resultant Y-Coordinate for Point (b)

Compare the resultant y-coordinate from the equation to the y-coordinate of point (b). If they match, then the point lies on the graph of the equation, otherwise not.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Equations
To solve equations involving polynomial functions, students must understand how to manipulate variables and apply operations. When we have a specific point, like \(a\) in \( (2,-\frac{16}{3}) \), to verify if it lies on the graph of the equation, we substitute the x-coordinate, 2, into the equation \( y=\frac{1}{3} x^3-2 x^2 \).

After performing the necessary arithmetic operations, we calculate the y-coordinate. In this step, exponentiation and multiplication by fractions are key processes that require precision. Once we get our y-coordinate, we compare it with the one given in the point. If they match, it confirms the point's presence on the curve of the polynomial function. This process is repeated for as many points as needed, here exemplified again with point \(b\) \( (-3,9) \).

Understanding how to substitute values and simplify polynomial expressions are essential skills for solving equations in algebra. It is this foundational skill that allows students to bridge the gap between algebraic expressions and geometric representations of functions.
Polynomial Functions
Polynomial functions are expressions consisting of variables and coefficients, involving only the operations of addition, subtraction, multiplication, and positive integer exponents. It's crucial to recognize the shape and features of these functions when graphed.

For example, the given polynomial function \( y=\frac{1}{3} x^3-2 x^2 \) is a cubic function, which means its graph has a characteristic 'S' shape curve with possible turning points. In analyzing these functions, we note that the coefficient of the highest degree term influences the end behavior of the graph, while the other terms affect the shape and location of the turning points.

When we work through an exercise like this, we are dealing with the graphical behavior of polynomial functions. It's also important to grasp the concept of roots, or zeros, which are the x-values where the function crosses or touches the x-axis. These points play a significant role when sketching the graphs of polynomial functions.
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, involves the study of geometry using a coordinate system. This field enables us to describe geometric figures algebraically and solve geometric problems by algebraic methods.

When we discuss whether a point lies on the graph of a given polynomial equation, we are intersecting the concepts of algebra and geometry. By taking the algebraic expression \( y=\frac{1}{3} x^3-2 x^2 \) and evaluating given points, we are using coordinate geometry to determine the position of these points relative to the curve represented by the equation.

In coordinate geometry, each point is defined by an ordered pair \( (x, y) \) on the Cartesian plane. Understanding how to plot these points and how to interpret the significance of their position enables students to visualize and solve more complex geometric problems. Exercises like these not only reinforce the student's algebraic skills but also strengthen their spatial understanding of mathematical concepts.

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Most popular questions from this chapter

True or False? In Exercises 85 and 86, determine whether the statement is true or false. Justify your answer. Proof Prove that if \(f\) is a one-to-one odd function, then \(f^{-1}\) is an odd function.

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