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Solve the equation and check your solution. (If not possible, explain why.) $$ \frac{2}{(x-4)(x-2)}=\frac{1}{x-4}+\frac{2}{x-2} $$

Short Answer

Expert verified
The solution to the equation includes all real numbers except 4 and 2.

Step by step solution

01

Simplification

Simplify the equation by subtracting \(\frac{1}{x-4}\) and \(\frac{2}{x-2}\) from both sides, this renders the equation to 0 = 0 as the left side and the right side of equation are identical, the original equation is an identity.
02

Identify Domain Restrictions

Recognize that while the equation simplifies to being an identity, there are values which x cannot take. Given the denominators in our original equation, there are two evident restrictions: \(x ≠ 4\) and \(x ≠ 2\). These values would make the denominators of our original equation zero, leading to undefined results. Thus, since we subtracted those initial values, while the equation is an identity, these restrictions remain.
03

Concluding the Solution

Since the original equation simplifies to an identity (0=0), the solution will contain all real numbers except for the values identified as restrictions in our second step. That is: \(x ∈ R, x ≠ 4 \) and \(x ≠ 2\).

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