/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 \(f(x)=\sqrt{x+8}+2\) (a) \(f(... [FREE SOLUTION] | 91Ó°ÊÓ

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\(f(x)=\sqrt{x+8}+2\) (a) \(f(-8)\) (b) \(f(1)\) (c) \(f(x-8)\)

Short Answer

Expert verified
\(f(-8) = 2\), \(f(1) = 5\), and \(f(x-8) = \sqrt{x} + 2\)

Step by step solution

01

Evaluate \(f(-8)\)

The expression under the square root should be non-negative, so it's safe to substitute \(-8\) for \(x\). So, \(f(-8) = \sqrt{-8+8} + 2 = \sqrt{0} + 2 = 0 + 2 = 2\).
02

Evaluate \(f(1)\)

Substitute \(x = 1\) in \(f(x)\). So, \(f(1) = \sqrt{1+8}+2 = \sqrt{9} + 2 = 3 + 2 = 5\).
03

Evaluate \(f(x-8)\)

Substitute \(x = x - 8\) in \(f(x)\). So, \(f(x-8) = \sqrt{x-8+8}+2 = \sqrt{x} + 2\). Note that here, the function will only be defined where \(x - 8 \geq 0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Square Root Function
A square root function is an expression involving the square root of a variable. In the function \(f(x) = \sqrt{x+8} + 2\), the square root component is \(\sqrt{x+8}\). Square root functions are important in mathematics because they are used to determine a value that, when multiplied by itself, yields the original number.
  • The expression inside the square root, in this case \(x+8\), is called the radicand.
  • Square roots can only be performed on non-negative numbers within the realm of real numbers, making the expression inside always greater than or equal to zero.
In practical terms, square root functions often result in a graph that forms a gentle upward curve. When evaluating square root functions, calculating the actual operation is crucial in deriving the value of \(f(x)\), which in our example, also includes adding 2 to the square root calculation.
Domain of a Function
The domain of a function refers to all the possible input values (typically \(x\) values) that are acceptable and make the function work without any mathematical errors. For the function \(f(x) = \sqrt{x+8} + 2\), it's essential for the radicand \(x+8\) to be greater than or equal to zero so that \(\sqrt{x+8}\) is real.
  • We set the inequality \(x+8 \geq 0\).
  • Simplifying, we find that \(x \geq -8\).
This means the domain of the function \(f(x)\) is all real numbers \(x\) such that \(x \geq -8\). Restricting the domain ensures that we only consider inputs where the function produces valid and real-number outputs. Always take care when performing operations on functions such as substitution, which can affect the function's overall domain.
Function Substitution
Function substitution involves replacing the variable in a function with another expression or specific number to evaluate or transform the function. In our examples, we see substitutions like \(f(-8)\), \(f(1)\), and \(f(x-8)\).
  • For \(f(-8)\), substitute \(x = -8\) into \(f(x)\) to get \(f(-8) = \sqrt{-8+8} + 2 = 2\).
  • For \(f(1)\), substitute \(x = 1\) yielding \(f(1) = \sqrt{1+8} + 2 = 5\).
  • In \(f(x-8)\), substitute \(x = x-8\): \(f(x-8) = \sqrt{x-8+8} + 2 = \sqrt{x} + 2\).
Function substitution is a powerful tool as it lets you explore how different inputs or transformations affect the function. When substituting, always pay attention to how it affects the domain of the function, especially if the substitution introduces new terms that require additional consideration.

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