/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 137 Find all solutions of the equati... [FREE SOLUTION] | 91Ó°ÊÓ

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Find all solutions of the equation. Check your solutions in the original equation. $$ x^{4}-81=0 $$

Short Answer

Expert verified
The solutions of \(x^{4}-81=0\) are \(x=3\) and \(x=-3\).

Step by step solution

01

STEP 1: Rearrange the Original Equation

First, rearrange the original equation \(x^{4}-81=0\) to the form of \(a^2-b^2=0\). Here, \(a=x^2\) and \(b=9\). So it will be \((x^2)^2-(9)^2=0\).
02

STEP 2: Use The Formula for the Difference of Squares

Next, apply the difference of squares formula, \(a^2-b^2=(a-b)(a+b)\). Here, \(a=x^2\) and \(b=9\). This gives us \((x^2-9)(x^2+9)=0\).
03

STEP 3: Solve Each Factor for Zero

To find the roots of the equation, set each factor equal to zero: So we get \(x^2-9=0\) and \(x^2+9=0\). Solving for \(x\) in the first equation gives \(x=\pm3\), and in the second equation, there are no real roots as we would have to take the square root of a negative number.
04

STEP 4: Check The Solution

Finally, plug the solutions you found back into the original equation to check your answer. For \(x=\pm3\), \(x^{4}-81=0\) is a true statement. Thus, the solutions are correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference of Squares
The difference of squares is a common algebraic concept that refers to an expression of the form \(a^2 - b^2\), where \(a\) and \(b\) are terms in the equation. It is factored using the formula \(a^2 - b^2 = (a - b)(a + b)\). This pattern is particularly useful for simplifying equations and solving for variable roots.

For instance, when dealing with the equation \(x^4 - 81 = 0\), we recognize \(x^4\) and \(81\) as perfect squares of \(x^2\) and \(9\) respectively. Factoring this using the difference of squares formula gives us \((x^2 - 9)(x^2 + 9) = 0\). By setting each factor to zero and solving for \(x\), we can find potential solutions to the original equation. Remember, the difference of squares only works when both terms are perfect squares and subtraction is involved.
Factoring Polynomials
Factoring polynomials involves breaking down a polynomial equation into simpler parts (or factors) that, when multiplied together, will give the original polynomial. This process is crucial for solving polynomial equations.

For instance, in our example, the polynomial \(x^4 - 81\) is factored into \((x^2 - 9)(x^2 + 9)\). Each factor represents a potential solution to the equation when set to zero. In our case, one factor, \(x^2 - 9\), can be further factored into \((x + 3)(x - 3)\) using the difference of squares. It is important to explore all factors of the polynomial for possible solutions, and sometimes, a polynomial may be factored more than once or may require different factoring techniques based on its complexity.
Complex Roots
In algebra, complex roots arise when we are solving polynomial equations that result in taking the square root of a negative number. Since the square root of a negative number does not produce a real number, we get a type of number known as a complex number.

For instance, in our equation \(x^2 + 9 = 0\), solving for \(x\) requires taking the square root of \(-9\), which is not possible within the real number system. Instead, we use the concept of complex numbers, introducing the imaginary unit \(i\), where \(i^2 = -1\). Hence, the complex roots for the equation would be \(x = \pm 3i\). It's vital to recognize when an equation will lead to complex roots, as they are just as valid as real number solutions in the context of polynomial equations.
Verifying Solutions
After solving a polynomial equation, it's important to verify that the solutions are correct. This involves plugging the solutions back into the original equation to ensure that they satisfy the equation.

In our example, we have found real solutions \(x = \pm 3\) and complex solutions \(x = \pm 3i\). To verify, substitute these values for \(x\) in the original equation and check whether the equation holds true. For real solutions, when we plug \(3\) or \(-3\) into \(x^4 - 81\), it simplifies to \(81 - 81 = 0\), confirming they are correct. For complex solutions, plugging in \(3i\) or \(-3i\) will also result in \(0\), verifying their validity. Verification ensures that any overlooked mistakes during the solving process are caught and that the solutions provided are indeed solutions to the polynomial equation.

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Most popular questions from this chapter

In Exercises 33-38, use a graphing utility to graph the function, and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. $$ f(x)=-2 x \sqrt{16-x^{2}} $$

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Average Cost The inventor of a new game believes that the variable cost for producing the game is \(\$ 0.95\) per unit and the fixed costs are \(\$ 6000\). The inventor sells each game for \(\$ 1.69\). Let \(x\) be the number of games sold. (a) The total cost for a business is the sum of the variable cost and the fixed costs. Write the total cost \(C\) as a function of the number of games sold. (b) Write the average cost per unit \(\bar{C}=C / x\) as a function of \(x\).

The numbers of households \(f\) (in thousands) in the United States from 1995 to 2003 are shown in the table. The time (in years) is given by \(t\), with \(t=5\) corresponding to 1995 . (Source: U.S. Census Bureau) $$ \begin{array}{|c|c|} \hline \text { Year, } t & \text { Households, } f(t) \\ \hline 5 & 98,990 \\ 6 & 99,627 \\ 7 & 101,018 \\ 8 & 102,528 \\ 9 & 103,874 \\ 10 & 104,705 \\ 11 & 108,209 \\ 12 & 109,297 \\ 13 & 111,278 \\ \hline \end{array} $$ (a) Find \(f^{-1}(108,209)\). (b) What does \(f^{-1}\) mean in the context of the problem? (c) Use the regression feature of a graphing utility to find a linear model for the data, \(y=m x+b\). (Round \(m\) and \(b\) to two decimal places.) (d) Algebraically find the inverse function of the linear model in part (c). (e) Use the inverse function of the linear model you found in part (d) to approximate \(f^{-1}(117,022)\). (f) Use the inverse function of the linear model you found in part (d) to approximate \(f^{-1}(108,209)\). How does this value compare with the original data shown in the table?

In Exercises 39-54, (a) find the inverse function of \(f\), (b) graph both \(f\) and \(f^{-1}\) on the same set of coordinate axes, (c) describe the relationship between the graphs of \(f\) and \(f^{-1}\), and (d) state the domain and range of \(f\) and \(f^{-1}\). $$ f(x)=x^{5}-2 $$

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