Chapter 8: Problem 45
$$ \text { Change each equation to rectangular coordinates and then graph. } $$ $$ r(2 \cos \theta+3 \sin \theta)=6 $$
Short Answer
Expert verified
Convert to rectangular coordinates: \( 2x + 3y = 6 \), then graph this line.
Step by step solution
01
Understand the Relationship
The given equation is a polar equation, and we need to convert it to rectangular coordinates. In polar coordinates, a point is represented by \( (r, \theta) \), where \( r \) is the radius and \( \theta \) is the angle. In rectangular coordinates, a point is represented by \( (x, y) \). To convert, we use the relationships: \( x = r \cos \theta \) and \( y = r \sin \theta \).
02
Expand Multiplication
Start with the given equation: \[ r(2 \cos \theta + 3 \sin \theta) = 6 \]Distribute \( r \) to both terms inside the parenthesis: \[ 2r \cos \theta + 3r \sin \theta = 6 \]
03
Substitute Rectangular Coordinates
Replace \( r \cos \theta \) with \( x \) and \( r \sin \theta \) with \( y \) in the expanded equation:\[ 2x + 3y = 6 \]We have now expressed the equation in rectangular coordinates.
04
Rearrange for Graphing
To make graphing easier, rearrange the equation for the slope-intercept form \( y = mx + b \):\[ 3y = -2x + 6 \]Divide every term by 3:\[ y = -\frac{2}{3}x + 2 \]This is the linear equation in slope-intercept form, where the slope \( m = -\frac{2}{3} \) and the y-intercept \( b = 2 \).
05
Graph the Equation
To graph the line \( y = -\frac{2}{3}x + 2 \), start at the y-intercept \( (0, 2) \). From this point, use the slope; for each step of 3 units in the positive x-direction, go 2 units down, because the slope is negative. Continue plotting points and draw the line.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
Polar coordinates are a way of representing points on a plane using a radius and an angle. This system is defined by the pair \((r, \theta)\), where:
- \(r\) is the radial distance from the origin (center of the graph) to the point.
- \(\theta\) is the angle formed with the positive x-axis.
Rectangular Coordinates
Rectangular coordinates, or Cartesian coordinates, are used to identify a point on a plane with an ordered pair (x, y). Here,
- \(x\) represents the horizontal position from the origin.
- \(y\) represents the vertical position from the origin.
- \(x = r \cos \theta\)
- \(y = r \sin \theta\)
Graphing Linear Equations
Graphing linear equations involves plotting straight lines on a coordinate plane. A linear equation in two variables can be expressed in the standard form \(ax + by = c\), which can be easily rearranged into other useful forms for graphing, such as the slope-intercept form.To graph a linear equation, you typically:
- Identify the slope (m) and y-intercept (b) if the equation is in the slope-intercept form.
- Plot the y-intercept on the graph.
- Use the slope to determine the direction and steepness of the line. The slope indicates how many units you move vertically for a given horizontal movement.
Slope-Intercept Form
The slope-intercept form of a linear equation is: \(y = mx + b\). In this format:
- \(m\) is the slope, which measures the steepness and direction of the line.
- \(b\) is the y-intercept, the point where the line crosses the y-axis.
- The slope, \(-\frac{2}{3}\), means for every 3 units moved right along the x-axis, the line drops 2 units vertically.
- The y-intercept, \(2\), means the line crosses the y-axis at \(y = 2\).