Chapter 8: Problem 19
Use de Moivre's Theorem to find each of the following. Write your answer in standard form. $$ \left[2\left(\cos 10^{\circ}+i \sin 10^{\circ}\right)\right]^{6} $$
Short Answer
Expert verified
The expression is \( 32 + 32\sqrt{3}i \).
Step by step solution
01
Express in Polar Form
Start by recognizing the given expression in polar form: \[ z = 2(\cos 10^{\circ} + i\sin 10^{\circ}) \]This can be written as \( z = 2\text{cis}10^{\circ} \), where "cis" denotes \( \cos + i\sin \).
02
Apply de Moivre's Theorem
According to de Moivre’s Theorem, for a complex number in polar form \( r(\cos \theta + i \sin \theta) \), its nth power is:\[ z^n = r^n \left(\cos(n\theta) + i\sin(n\theta)\right) \]Apply it to \( z^6 \), where \( z = 2\text{cis}10^{\circ} \).
03
Calculate Magnitude
The magnitude \( r^6 \) is:\[ 2^6 = 64 \]Thus, the expression becomes:\[ 64\text{cis}(60^{\circ}) \]
04
Convert to Standard Form
Convert back to standard form:\[ 64\left( \cos 60^{\circ} + i \sin 60^{\circ} \right) \]Substitute the trigonometric values:\[ 64\left( \frac{1}{2} + i\frac{\sqrt{3}}{2} \right) \]
05
Simplify
Multiply through by 64:\[ 32 + 32\sqrt{3}i \]This is the expression in standard form.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers form a fundamental concept in mathematics and can be quite intriguing. They combine a real part and an imaginary part into a single number, typically expressed as:
- For example, a complex number is written as \( z = a + bi \), where \( a \) is the real part and \( bi \) is the imaginary part.
- The imaginary unit \( i \) satisfies the equation \( i^2 = -1 \).
Polar Form
Polar form provides a unique and beneficial way to express complex numbers. In this form, a complex number is represented based on its distance from the origin (magnitude) and the angle it makes with the positive x-axis (argument).
- The polar form of a complex number \( z = r(\cos \theta + i \sin \theta) \) can also be written as \( z = r\text{cis}\theta \), where "cis" stands for "cosine plus i sine."
- The magnitude \( r \) is defined as \( \sqrt{a^2 + b^2} \) and represents the modulus of the complex number.
- The argument \( \theta \) represents the angle, which can be found using trigonometric functions such as the arctan function.
Standard Form Conversion
Converting a complex number back into its standard form involves calculating its real and imaginary components from the polar form. The process typically involves using trigonometric identities to find each part:
- Start with a complex number in polar form: \( z = r(\cos \theta + i \sin \theta) \).
- Convert it by distributing the magnitude \( r \) to both the cosine and sine components.
- For example, \( r(\cos \theta) = a \) becomes the real part, and \( r(i \sin \theta) = bi \) becomes the imaginary part.
Trigonometric Functions
Trigonometric functions like sine and cosine are key components in both the polar form and the standard form conversion of complex numbers.
- The cosine function, \( \cos \theta \), gives the horizontal (or x-axis) component of the distance from the origin.
- The sine function, \( \sin \theta \), provides the vertical (or y-axis) component.
- Trigonometric functions are periodic, repeating their values in cycles, which is crucial for simplifying expressions involving repeated angles.