Chapter 6: Problem 27
\(\cos 2 x \cos x-\sin 2 x \sin x=-\frac{\sqrt{3}}{2}\)
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Chapter 6: Problem 27
\(\cos 2 x \cos x-\sin 2 x \sin x=-\frac{\sqrt{3}}{2}\)
These are the key concepts you need to understand to accurately answer the question.
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\(\sin ^{3} 5 x=-1\)
\(\cot ^{2} 3 \theta=1\)
Use the quadratic formula to find (a) all degree solutions and (b) \(\theta\) if \(0^{\circ} \leq \theta<360^{\circ}\). Use a calculator to approximate all answers to the nearest tenth of a degree. $$ 1-4 \cos \theta=-2 \cos ^{2} \theta $$
\(\cos 8 \theta=\frac{1}{2}\)
For each of the following equations, solve for (a) all radian solutions and (b) \(x\) if \(0 \leq x<2 \pi\). Give all answers as exact values in radians. Do not use a calculator. $$ \tan x(\tan x-1)=0 $$
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