Chapter 5: Problem 4
Find exact values for each of the following: $$\tan 75^{\circ}$$
Short Answer
Expert verified
The exact value of \( \tan 75^{\circ} \) is \( 2 + \sqrt{3} \).
Step by step solution
01
Use the Angle Addition Formula for Tangent
To find \( \tan 75^{\circ} \), notice that \( 75^{\circ} = 45^{\circ} + 30^{\circ} \). We can use the tangent addition formula: \( \tan(a + b) = \frac{\tan a + \tan b}{1 - \tan a \tan b} \) where \( a = 45^{\circ} \) and \( b = 30^{\circ} \).
02
Substitute Known Values for Tangent
From trigonometric values, we know \( \tan 45^{\circ} = 1 \) and \( \tan 30^{\circ} = \frac{1}{\sqrt{3}} \). Substitute these into the angle addition formula: \[ \tan 75^{\circ} = \frac{1 + \frac{1}{\sqrt{3}}}{1 - 1 \cdot \frac{1}{\sqrt{3}}} \]
03
Simplify the Expression
Simplify the fraction step by step: - The numerator becomes \( 1 + \frac{1}{\sqrt{3}} = \frac{\sqrt{3} + 1}{\sqrt{3}} \).- The denominator becomes \( 1 - \frac{1}{\sqrt{3}} = \frac{\sqrt{3} - 1}{\sqrt{3}} \).Now, substitute these into the fraction: \[ \tan 75^{\circ} = \frac{\frac{\sqrt{3} + 1}{\sqrt{3}}}{\frac{\sqrt{3} - 1}{\sqrt{3}}} = \frac{\sqrt{3} + 1}{\sqrt{3} - 1} \].
04
Rationalize the Denominator
To simplify \( \frac{\sqrt{3} + 1}{\sqrt{3} - 1} \), multiply the numerator and the denominator by the conjugate of the denominator, \( \sqrt{3} + 1 \): \[ \frac{(\sqrt{3} + 1)(\sqrt{3} + 1)}{(\sqrt{3} - 1)(\sqrt{3} + 1)} = \frac{(\sqrt{3} + 1)^2}{(\sqrt{3})^2 - 1^2} \].
05
Calculate and Simplify Further
Compute the squared terms and simplify: - The numerator is \((\sqrt{3} + 1)^2 = 3 + 2\sqrt{3} + 1 = 4 + 2\sqrt{3}\).- The denominator becomes \(3 - 1 = 2\).Thus, we get: \[ \frac{4 + 2\sqrt{3}}{2} = 2 + \sqrt{3} \].
06
Conclude with the Exact Value
Therefore, the exact value of \( \tan 75^{\circ} \) is \( 2 + \sqrt{3} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Angle Addition Formula
The angle addition formula for the tangent function is a useful tool in trigonometry.It helps us find the tangent of an angle that can be expressed as a sum of two smaller, known angles.The formula states that for two angles, \( a \) and \( b \), the tangent of their sum is given by:
- \( \tan(a + b) = \frac{\tan a + \tan b}{1 - \tan a \tan b} \)
Tangent Function
The tangent function is a fundamental trigonometric function.It is defined as the ratio of the opposite side to the adjacent side in a right triangle for a given angle.Alternatively, it can also be expressed as the ratio of sine to cosine.Mathematically, \( \tan x = \frac{\sin x}{\cos x} \).When working with tangent, some common angles have easily recalled tangent values:
- \( \tan 45^{\circ} = 1 \)
- \( \tan 30^{\circ} = \frac{1}{\sqrt{3}} \)
- \( \tan 60^{\circ} = \sqrt{3} \)
Rationalizing the Denominator
Rationalizing the denominator is an important mathematical operation used to simplify expressions.When an expression has a radical or irrational number in the denominator, it can be made simpler by converting it into a rational number.This usually involves multiplying by a form of one, which in many cases is the conjugate of the denominator.For example, if the denominator is \( \sqrt{3} - 1 \), we multiply both the numerator and the denominator by \( \sqrt{3} + 1 \).This process exploits the difference of squares, leading to:
- \[ (\sqrt{3} - 1)(\sqrt{3} + 1) = (\sqrt{3})^2 - 1^2 = 3 - 1 = 2 \]