/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Graph each of the following from... [FREE SOLUTION] | 91Ó°ÊÓ

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Graph each of the following from \(x=0\) to \(x=4 \pi\). \(y=2 \cos ^{2} \frac{x}{2}\)

Short Answer

Expert verified
The graph of \( y = 2 \cos^2 \frac{x}{2} \) oscillates between 2 and 0 over \( x = 0 \) to \( x = 4\pi \), making a complete wave with peaks at even multiples of \( \pi \).

Step by step solution

01

Understanding the Equation

The given equation is \( y = 2 \cos^2 \frac{x}{2} \). We need to graph this as \( x \) varies from 0 to \( 4\pi \). Recognize that this is a transformation of the cosine function, involving squared terms and multiplication.
02

Finding the Period

The function involves \( \cos \frac{x}{2} \), which affects the period. The standard period of \( \cos(x) \) is \( 2\pi \), but with \( \cos \frac{x}{2} \), the period will be \( 4\pi \). Thus, we need to graph over its entire period which happens to align perfectly with the given range \([0, 4\pi ]\).
03

Amplitude Calculation

The function \( 2\cos^2(\frac{x}{2}) \) represents a transformation that scales the amplitude. Normally, \( \cos(x) \) ranges between -1 and 1, and \( \cos^2(\frac{x}{2}) \) ranges from 0 to 1. Therefore, \( y = 2 \cos^2(\frac{x}{2}) \) will range from 0 to 2. So the amplitude is 2.
04

Determining Key Points

To plot the function accurately, calculate \( y \) at key values of \( x \):\[ \begin{align*} x = 0, & \quad y = 2 \cos^2(0) = 2, \ x = \pi, & \quad y = 2 \cos^2\left(\frac{\pi}{2}\right) = 0, \ x = 2\pi, & \quad y = 2 \cos^2(\pi) = 2, \ x = 3\pi, & \quad y = 2 \cos^2\left(\frac{3\pi}{2}\right) = 0, \ x = 4\pi, & \quad y = 2 \cos^2(2\pi) = 2. \end{align*} \]
05

Sketching the Graph

Using the calculated key points and understanding that the function is periodic, sketch the curve. The graph will oscillate between 2 and 0, making a complete cycle from 0 to \(4\pi\). Mark these key points and ensure the smooth, wave-like transition between them as cosine functions suggest.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Period of a Function
The period of a function is essentially the length of the smallest interval over which the function repeats itself. For the standard cosine function, the period is
  • \(2\pi\)
This means that every \(2\pi\) units along the x-axis, the cosine wave completes one full cycle before starting over again. However, transforming the argument inside the cosine function affects the period. In our exercise, the function is \( \cos\left(\frac{x}{2}\right) \).
This transformation will stretch the period by a factor of 2 because the coefficient \(\frac{1}{2}\) in the argument of the cosine function doubles the length of the x-values needed to complete one full cycle.
Hence, the new period of \( \cos\left(\frac{x}{2}\right) \) is \( 4\pi \). This means from \( x=0 \) to \( x=4\pi \), the function completes exactly one cycle, which fits perfectly into the range specified for graphing in the exercise.
Amplitude Calculation
The amplitude of a trigonometric function is a measure of its highest vertical displacement from the horizontal axis. For the basic cosine and sine functions, their amplitudes are typically 1, since they oscillate consistently between -1 and 1. However, transformations such as multiplication change the amplitude.
In our function \( y = 2 \cos^2\left(\frac{x}{2}\right) \), the coefficient 2 affects the range of the function.
  • Since \( \cos^2\) term ensures the values are squared, the range prior to scaling is between 0 and 1.
  • Multiplying by 2 scales this up to between 0 and 2.
Thus, the amplitude is 2, meaning the highest point of the graph reaches up to 2 from the x-axis, while the lowest point stays at 0 due to squaring preventing negative values.
Key Points in Graphing
To accurately sketch a trigonometric graph, identifying key points is crucial. These points offer a framework that the rest of the graph can be drawn through. In our problem, carrying out computations at strategic values of x helps reveal the behavior and structure of the graph:
  • At \( x = 0 \), \( y = 2 \cos^2 (0) = 2 \).
  • At \( x = \pi \), \( y = 2 \cos^2\left(\frac{\pi}{2}\right) = 0 \).
  • At \( x = 2\pi \), \( y = 2 \cos^2 (\pi) = 2 \).
  • At \( x = 3\pi \), \( y = 2 \cos^2\left(\frac{3\pi}{2}\right) = 0 \).
  • At \( x = 4\pi \), \( y = 2 \cos^2(2\pi) = 2 \).
Plotting these points on a graph provides markers of where the curve reaches its peaks (amplitude), dips (midpoints), and ends one complete cycle (period). Connecting them in a smooth, periodic wave immerses the core nature of the cosine function, completing the graph from 0 to \( 4\pi \).
Trigonometric Graph Transformations
Trigonometric functions are versatile and can be manipulated to produce a variety of waves by applying transformations. These transformations can involve changes to the amplitude, period, horizontal and vertical shifts, as well as reflections.
In the case of our equation \( y = 2 \cos^2\left(\frac{x}{2}\right) \), several transformations occur:
  • The presence of \( \left(\frac{x}{2}\right) \) arguments doubles the period as discussed.
  • The coefficient of 2 in front of the function scales up the amplitude by a factor of 2.
Combining these transformations, the graph of \( y = 2 \cos^2\left(\frac{x}{2}\right) \) will oscillate smoothly between 0 and 2, over the expanded duration of \( 4\pi \). The function undergoes its full set of transformations resulting in a taller, horizontally stretched graph compared to the standard cosine wave.

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