/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 A point is moving with a linear ... [FREE SOLUTION] | 91Ó°ÊÓ

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A point is moving with a linear velocity of 20 feet per second on the circumference of a circle. How far does the point move in 1 minute?

Short Answer

Expert verified
The point moves 1200 feet in 1 minute.

Step by step solution

01

Understand the Problem

The point moves along the circumference of a circle with a constant speed. We need to find the total distance the point travels in 1 minute.
02

Convert Time from Minutes to Seconds

Since the speed is given in feet per second, convert the time from minutes to seconds: 1 minute = 60 seconds.
03

Use Speed to Find Distance

The formula for distance traveled is given by \( \text{Distance} = \text{Speed} \times \text{Time} \). Substitute the values into the equation: \[ \text{Distance} = 20 \text{ ft/sec} \times 60 \text{ sec} \].
04

Calculate the Result

Perform the multiplication: \( 20 \times 60 = 1200 \text{ feet} \).
05

Interpret the Result

The point moves 1200 feet along the circumference in 1 minute.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Velocity
Linear velocity refers to the rate at which an object moves along a path in a straight line. In simpler terms, it describes how fast something is going in a particular direction. You can think of it as how far you go over a period of time. For example, if your car travels 60 miles in one hour, the linear velocity is 60 miles per hour.

Linear velocity is commonly expressed in units like meters per second (m/s) or feet per second (ft/s). Understanding linear velocity can help you solve problems involving motion, such as determining distance traveled or the time it takes to reach a destination. In this exercise, the linear velocity is provided as 20 feet per second, which tells us the speed at which the point is moving along the circumference of the circle.
Distance Calculation
To calculate the distance an object travels, especially in circular motion, you need its speed and the time for which it travels. The formula to find the distance is:
  • Distance = Speed x Time
This formula is straightforward and simply multiplies how fast you're going by how long you're going.

In the context of our problem, since we know the linear velocity is 20 feet per second and the time is 60 seconds (once converted from minutes), the distance can be calculated by substituting these values into the formula:
\[\text{Distance} = 20 \, \text{ft/s} \times 60 \, \text{s} = 1200 \, \text{ft}\]

This step shows that the point moves a total of 1200 feet along the circle's circumference in one minute.
Time Conversion
Converting units of time is an essential skill, especially when dealing with problems involving motion. Time conversion allows us to align the units given in a problem with the units required for calculations.

In this context, the problem involves linear velocity given in feet per second. Since we need to find the distance traveled in one minute, converting the minute to seconds is necessary. Knowing that 1 minute consists of 60 seconds means we can straightforwardly use the linear velocity to find how far the point travels in seconds, rather than minutes.

This conversion simplifies the calculation process immensely, making it possible to apply the distance formula without misalignment in units.

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Most popular questions from this chapter

In Chapters 2 and 3, we worked some problems involving the Ferris wheel called Colossus that was built in St. Louis in 1986. The diameter of the wheel is 165 feet, it rotates at \(1.5\) revolutions per minute, and the bottom of the wheel is 9 feet above the ground. Find an equation that gives a passenger's height above the ground at any time \(t\) during the ride. Assume the passenger starts the ride at the bottom of the wheel.

A mass attached to a spring is pulled downward and released. The displacement of the mass from its equilibrium position after \(t\) seconds is given by the function \(d=A \cos (\omega t)\), where \(d\) is measured in centimeters (Figure 11). The length of the spring when it is shortest is 11 centimeters, and 21 centimeters when it is longest. If the spring oscillates with a frequency of \(0.8\) Hertz, find \(d\) as a function of \(t\).

Alternating Current In North America, the voltage of the alternating current coming through an electrical outlet can be modeled by the function \(V=163 \sin (120 \pi t)\), where \(t\) is measured in seconds and \(V\) in volts. Sketch the graph of this function for \(0 \leq t \leq 0.1\).

Oscillating Spring A mass attached to a spring oscillates upward and downward. The displacement of the mass from its equilibrium position after \(t\) seconds is given by the function \(d=-3.5 \cos (2 \pi t)\), where \(d\) is measured in centimeters (Figure 13). a. Sketch the graph of this function for \(0 \leq t \leq 5\). b. What is the furthest distance of the mass from its equilibrium position? c. How long does it take for the mass to complete one oscillation?

Electric Current The current in an alternating circuit varies in intensity with time. If \(I\) represents the intensity of the current and \(t\) represents time, then the relationship between \(I\) and \(t\) is given by $$ I=20 \sin (120 \pi t) $$ where \(I\) is measured in amperes and \(t\) is measured in seconds. Find the maximum value of \(I\) and the time it takes for \(I\) to go through one complete cycle.

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