Chapter 6: Problem 74
Let \(P(x)=x^{2}+4 x+5, T(x)=2 x^{2}+1,\) and \(W(x)=\) \(x^{2}-6 x+14 .\) Find each of the following. $$ T\left(\frac{i \sqrt{2}}{2}\right) $$
Short Answer
Expert verified
0
Step by step solution
01
Identify the function
The function to be evaluated is given as \( T(x) = 2x^2 + 1. \).
02
Substitute the given value
Substitute \( x = \frac{i \sqrt{2}}{2} \) into the function \( T(x) \). This gives \( T \left ( \frac{i \sqrt{2}}{2} \right ) = 2 \left ( \frac{i \sqrt{2}}{2} \right )^2 + 1 \).
03
Simplify the square
Calculate \( \left ( \frac{i \sqrt{2}}{2} \right )^2 = \left ( \frac{i^2 \sqrt{2}^2}{2^2} \right ) = \left ( \frac{-1 \cdot 2}{4} \right ) = -\frac{1}{2} \).
04
Multiply by coefficient
Multiply the result by 2, giving \( 2 \cdot \left( -\frac{1}{2} \right) = -1 \).
05
Add constant term
Add the constant term 1 to get the final result \( -1 + 1 = 0 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers in Trigonometry
Complex numbers are numbers that have both a real part and an imaginary part. In trigonometry, they are often represented as \(a + bi\), where \(i\) is the imaginary unit satisfying \(i^2 = -1\). The imaginary unit allows for the extension of the real number system into the complex plane. Evaluating trigonometric functions with complex numbers can be a bit tricky, so let's delve into this important concept.
Example: In the exercise, we were given the function \(T(x) = 2x^2 + 1\) and asked to find \(T \left( \frac{i \sqrt{2}}{2} \right)\). Here, \(\frac{i \sqrt{2}}{2}\) is a complex number because it has a real part of 0 and an imaginary part of \(\frac{ \sqrt{2}}{2}i\).
Example: In the exercise, we were given the function \(T(x) = 2x^2 + 1\) and asked to find \(T \left( \frac{i \sqrt{2}}{2} \right)\). Here, \(\frac{i \sqrt{2}}{2}\) is a complex number because it has a real part of 0 and an imaginary part of \(\frac{ \sqrt{2}}{2}i\).
- When substituting \(x = \frac{i \sqrt{2}}{2}\) into \(T(x)\), we must handle the imaginary unit \(i\) according to its unique properties.
- After expanding and simplifying, consider that \(i^2 = -1\) to get the correct results.
Polynomial Evaluation
Polynomials are expressions involving variables raised to powers and represented as \ a_nx^n + a_{n-1}x^{n-1} + ... + a_1x + a_0 \. Evaluating a polynomial means finding the value of the polynomial for a given value of the variable.
Let's break down polynomial evaluation with an example from the exercise:
Let's break down polynomial evaluation with an example from the exercise:
- The polynomial given is \(T(x) = 2x^2 + 1\).
- To evaluate \(T \left( \frac{i \sqrt{2}}{2} \right)\), substitute the given value into the polynomial.
- This step involves basic arithmetic operations and handling any special values, such as \(i\).
Step-by-Step Problem Solving
Solving mathematical problems step-by-step ensures that each part of the process is correct and helps to understand every aspect of the problem. Let's see how this approach is applied in the exercise:
- First, identify the function to be evaluated. Here, it is \( T(x) = 2x^2 + 1 \).
- Next, substitute the given value \( x = \frac{i \sqrt{2}}{2} \) into the function.
- Then, simplify the square \( \left( \frac{i \sqrt{2}}{2} \right)^2 \).
- Multiply by the coefficient to get the intermediate result.
- Finally, add any constant terms to get the final answer.