Chapter 6: Problem 10
Graph each pair of parametric equations in the rectangular coordinate system. $$x=t-3, y=1 / t,\( for \)t\( in \)(-\infty, \infty)$$
Short Answer
Expert verified
Plot points such as (-5, -0.5), (-4, -1), and others to draw a hyperbolic curve.
Step by step solution
01
Understand the Parametric Equations
The given equations are parametric, where both x and y are expressed in terms of a parameter t. These are: \[ x = t - 3 \] and \[ y = \frac{1}{t} \]
02
Create a Table of Values
Choose various values for t to see how x and y change. For example, let t be -2, -1, -0.5, 0.5, 1, and 2.
03
Calculate Coordinates
Substitute the chosen values of t into both equations to get corresponding x and y values. Here are some calculations: For t = -2: \[ x = -2 - 3 = -5 \] \[ y = \frac{1}{-2} = -0.5 \] For t = -1: \[ x = -1 - 3 = -4 \] \[ y = \frac{1}{-1} = -1 \] For t = -0.5: \[ x = -0.5 - 3 = -3.5 \] \[ y = \frac{1}{-0.5} = -2 \] For t = 0.5: \[ x = 0.5 - 3 = -2.5 \] \[ y = \frac{1}{0.5} = 2 \] For t = 1: \[ x = 1 - 3 = -2 \] \[ y = \frac{1}{1} = 1 \] For t = 2: \[ x = 2 - 3 = -1 \] \[ y = \frac{1}{2} = 0.5 \]
04
Plot the Points
Use the calculated coordinates to plot each point on the rectangular coordinate system: \[ (-5, -0.5), (-4, -1), (-3.5, -2), (-2.5, 2), (-2, 1), (-1, 0.5) \]
05
Draw the Curve
Connect the plotted points smoothly, keeping in mind that as t approaches 0, the values of y will become very large or very small. The graph will show a hyperbola-like curve on the coordinate system.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Parametric Equations
Parametric equations express the coordinates of points on a curve as functions of a parameter, usually denoted as t. This means, instead of directly relating x and y, we have separate equations for each:
\[ x = t - 3 \] and \[ y = \frac{1}{t} \]
To graph these, we substitute various values of t into both equations to generate points (x, y). These points are then plotted on a graph and connected smoothly. It's crucial to choose a range of t values that reveal the curve's behavior accurately. In this exercise, t was chosen from the set: \(-\text{infinity}, \text{infinity}\). This range ensures we capture the entire behavior of the graph.
Building a table of values helps to systematically organize this process. Here's a simplified approach:
\[ x = t - 3 \] and \[ y = \frac{1}{t} \]
To graph these, we substitute various values of t into both equations to generate points (x, y). These points are then plotted on a graph and connected smoothly. It's crucial to choose a range of t values that reveal the curve's behavior accurately. In this exercise, t was chosen from the set: \(-\text{infinity}, \text{infinity}\). This range ensures we capture the entire behavior of the graph.
Building a table of values helps to systematically organize this process. Here's a simplified approach:
- Select different t values: -2, -1, -0.5, 0.5, 1, and 2.
- Calculate corresponding x and y values using the parametric equations.
- Plot the calculated points on a graph.
Rectangular Coordinate System
The rectangular coordinate system, also known as the Cartesian plane, is a two-dimensional plane formed by the intersection of two perpendicular lines: the horizontal x-axis and the vertical y-axis. Each point on this plane is described by a pair of numerical coordinates \((x, y)\), determining its exact position.
In this plane:
In this plane:
- The x-coordinate indicates horizontal position: positive values to the right of the origin and negative values to the left.
- The y-coordinate indicates vertical position: positive values above the origin and negative values below.
- Calculate the x and y values by substituting chosen t values.
- Mark each point corresponding to \((x, y)\) values on this plane.
- Pay attention to the overall shape and behavior of the curve as points are plotted.
Hyperbola
A hyperbola is a type of conic section that emerged from slicing a double-cone with a plane. Hyperbolas have two symmetrical curves, each reflecting the shape of the other. These curves are displayed in a mirror-image structure on the coordinate system.
In the context of our parametric equations, \(x = t - 3\) and \(y = \frac{1}{t}\), the resulting graph does show a hyperbola-like structure. Here's why:
In the context of our parametric equations, \(x = t - 3\) and \(y = \frac{1}{t}\), the resulting graph does show a hyperbola-like structure. Here's why:
- As t approaches 0, \(y\) tends to infinity, causing the curves to shoot outwards.
- The symmetry in \(1/t\) throughout positive and negative values of \(t\) creates mirroring curves.
- The asymptotes - lines which the curves approach but never actually reach - help guide the curve's shape.
- For large absolute values of \(t\), the \(x\) and \(y\) values settle into predictable patterns, aiding in sketching the entire curve smoothly.