/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 Determine whether each pair of v... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine whether each pair of vectors is parallel, perpendicular, or neither. $$ \langle 2,3\rangle,\langle 8,12\rangle $$

Short Answer

Expert verified
The vectors \( \langle 2, 3 \rangle \) and \( \langle 8, 12 \rangle \) are parallel.

Step by step solution

01

- Understand the Vectors

The given vectors are \(\textbf{u} = \langle 2, 3 \rangle\) and \(\textbf{v} = \langle 8, 12 \rangle\). We need to determine if they are parallel, perpendicular, or neither.
02

- Check for Parallel Vectors

Vectors are parallel if one is a scalar multiple of the other. Check if \(\textbf{v} = k \textbf{u}\) for some scalar \(k\). Compare the components: \(8 = 4 \times 2\) and \(12 = 4 \times 3\). Since \(k = 4\), the vectors are parallel.
03

- Verify Perpendicular Condition

Vectors are perpendicular if their dot product is zero. Calculate the dot product: \( \textbf{u} \bullet \textbf{v} = 2 \times 8 + 3 \times 12 = 16 + 36 = 52 \). Since the dot product is not zero, the vectors are not perpendicular.
04

- Conclusion

Since the vectors are parallel based on the scalar multiple condition and not perpendicular based on the dot product, the vectors are identified as parallel.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parallel Vectors
In the context of vectors, 'parallel' means that one vector is a scaled version of the other. This implies that they point in the same or exactly opposite directions. To determine if vectors \( \textbf{u} = \langle 2, 3 \rangle \) and \( \textbf{v} = \langle 8, 12 \rangle \) are parallel, we check for a scalar multiple. If we find a scalar \( k \) such that \( \textbf{v} = k \textbf{u} \), the vectors are parallel.
By verifying the components, we see that \( 8 = 4 \times 2 \) and \( 12 = 4 \times 3 \). Here, \( k = 4 \). Hence, \( \textbf{v} \) is obtained by scaling \( \textbf{u} \) by 4. They are parallel because of this consistent scaling factor. Parallel vectors indicate alignment in the same direction or the exact opposite, depending on the sign of the scalar.
Perpendicular Vectors
Vectors are considered perpendicular (orthogonal) if the angle between them is 90 degrees. A key characteristic of perpendicular vectors is that their dot product equals zero. The dot product of two vectors \( \textbf{u} = \langle u_1, u_2 \rangle \) and \( \textbf{v} = \langle v_1, v_2 \rangle \) is calculated as: \[ \textbf{u} \cdot \textbf{v} = u_1 v_1 + u_2 v_2 \] Checking for the vectors \( \textbf{u} = \langle 2, 3 \rangle \) and \( \textbf{v} = \langle 8, 12 \rangle \), we find: \[ \textbf{u} \cdot \textbf{v} = 2 \times 8 + 3 \times 12 = 16 + 36 = 52 \] Since the dot product is \ not zero \, the vectors are not perpendicular. The zero value of the dot product signifies a perfect 90-degree angle between the vectors, which is not the case here.
Dot Product
The dot product (or scalar product) of two vectors quantifies the extent to which they point in the same direction. It can be calculated using the formula: \[ \textbf{u} \cdot \textbf{v} = u_1 v_1 + u_2 v_2 \] For vectors \( \textbf{u} = \langle 2, 3 \rangle \) and \( \textbf{v} = \langle 8, 12 \rangle \), the dot product is: \[ 2 \times 8 + 3 \times 12 = 52 \] The dot product helps determine various properties. If its value is zero, the vectors are perpendicular. If non-zero, it provides a measure of how closely the vectors align directionally. Higher values indicate greater alignment. In cases like these, understanding the dot product is essential for analyzing the geometric relationships between vectors.

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Most popular questions from this chapter

Solve each problem. Surveying Triangular Property A surveyor locating the corners of a triangular piece of property started at one corner and walked \(480 \mathrm{ft}\) in the direction \(\mathrm{N} 36^{\circ} \mathrm{W}\) to reach the next corner. The surveyor turned and walked \(\mathrm{S} 21^{\circ} \mathrm{W}\) to get to the next corner of the property. Finally, the surveyor walked in the direction \(\mathrm{N} 82^{\circ} \mathrm{E}\) to get back to the starting point. What is the area of the property in square feet? Round to the nearest tenth.

Let \(\mathbf{r}=\langle 3,-2\rangle, \mathbf{s}=\langle-1,5\rangle,\) and \(\mathbf{t}=\langle 4,-6\rangle .\) Perform the operations indicated. Write the vector answers in the form \(\langle a, b\rangle\). $$ \mathbf{r}-\mathbf{t} $$

Find the smallest positive angle to the nearest tenth of a degree between each given pair of vectors. $$ \langle-6,5\rangle,\langle 5,6\rangle $$

Solve each problem. Surveying a Quadrilateral A surveyor locating the corners of a four-sided piece of property started at one corner and walked \(200 \mathrm{ft}\) in the direction \(\mathrm{N} 80^{\circ} \mathrm{E}\) to reach the next corner. He turned and walked due north \(150 \mathrm{ft}\) to the next corner of the property. He then turned and walked due west to get to the fourth corner of the property. Finally, he walked in the direction \(\mathrm{S} 15^{\circ} \mathrm{E}\) to get back to the starting point. What is the area of the property in square feet? Round to the nearest tenth.

Solve each problem. Find the area of the triangle whose vertices are the \(x\) - and \(y\) -intercepts of the parabola \(y=x^{2}-4 x+3\).

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