Chapter 4: Problem 79
Find the inverse of each function and state the domain and range of \(f^{-1}\) $$ f(x)=\sin ^{-1}(3 x) \text { for }-\frac{1}{3} \leq x \leq \frac{1}{3} $$
Short Answer
Expert verified
The inverse function is \f^{-1}(x) = |frac{\text{sin}(x)}{3}\, The domain is \(3x)^3}{3{x)}. The reqration is |-1 = \(1}
Step by step solution
01
Write the function equation
The given function is \[ f(x) = \text{sin}^{-1}(3x) \]. First, write this equation in terms of y:\[ y = \text{sin}^{-1}(3x) \].
02
Solve for x
To find the inverse function, start by switching x and y and then solve for y. This gives us the equation \[ x = \text{sin}^{-1}(3y) \]. Apply the sine function to both sides to get \[ \text{sin}(x) = 3y \].
03
Isolate y
Solve for y by dividing both sides by 3:\[ y = \frac{\text{sin}(x)}{3} \]. Therefore, the inverse function is \[ f^{-1}(x) = \frac{\text{sin}(x)}{3} \].
04
Determine the domain of the inverse function
The domain of the inverse function \( f^{-1}(x) \) is the range of the original function \( f(x) \). Since \[ -\frac{1}{3} \leq \ x \ \leq\frac{1}{3} \], for the arsin function the range is -\( \frac{\text{sin}(x)}{3} \) the domain is \[ -\frac{\text{sin}(x)}{3},,\frac{1}{3} \]
05
Determine the range of the inverse function
The range of the inverse function \( f^{-1}(x) \) is the domain of the original function \( f(x) \). Given \[ f(x) = \text{sin}^{-1}(3x) \],}, the range is domain is \[ -\frac{\text{sin}(x)}{-\frac{ \ \leq f^{-1}(a) \ 3} \].}
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain and Range
Understanding the domain and range of a function is crucial when dealing with inverse trigonometric functions.
The domain refers to all possible input values (x-values) for which the function is defined.
The range refers to all possible output values (y-values) of the function.
In simpler terms, the domain is what you can put into the function, and the range is what you get out of it.
For the function \( f(x) = \text{sin}^{-1}(3x) \), the domain is given as \( -\frac{1}{3} \leq x \leq \frac{1}{3} \). This is because \( \text{sin}^{-1} \) (also known as \( \text{arcsin} \)) has a limited range of input values where it is defined.
The range of \( f(x) \) is from \( -\frac{\pi}{2} \) to \( \frac{\pi}{2} \), since the \( \text{arcsin} \) function only produces output values within this interval.
For the inverse function \( f^{-1}(x) \), derived to be \( \frac{\sin(x)}{3} \), the domain and range swap places:
- The domain of \( f^{-1}(x) \) becomes the range of \( f(x) \), which is \( -\frac{\pi}{2} \) to \( \frac{\pi}{2} \).
- The range of \( f^{-1}(x) \) is from \( -\frac{1}{3} \) to \( \frac{1}{3} \), corresponding to the domain of \( f(x) \).
The domain refers to all possible input values (x-values) for which the function is defined.
The range refers to all possible output values (y-values) of the function.
In simpler terms, the domain is what you can put into the function, and the range is what you get out of it.
For the function \( f(x) = \text{sin}^{-1}(3x) \), the domain is given as \( -\frac{1}{3} \leq x \leq \frac{1}{3} \). This is because \( \text{sin}^{-1} \) (also known as \( \text{arcsin} \)) has a limited range of input values where it is defined.
The range of \( f(x) \) is from \( -\frac{\pi}{2} \) to \( \frac{\pi}{2} \), since the \( \text{arcsin} \) function only produces output values within this interval.
For the inverse function \( f^{-1}(x) \), derived to be \( \frac{\sin(x)}{3} \), the domain and range swap places:
- The domain of \( f^{-1}(x) \) becomes the range of \( f(x) \), which is \( -\frac{\pi}{2} \) to \( \frac{\pi}{2} \).
- The range of \( f^{-1}(x) \) is from \( -\frac{1}{3} \) to \( \frac{1}{3} \), corresponding to the domain of \( f(x) \).
Sine Function
The sine function is a fundamental trigonometric function, often denoted as \( \sin(x) \). It is defined on the entire set of real numbers, but its values fall within a specific range.
For any input \( x \), \( \sin(x) \) will produce an output between -1 and 1 inclusive.
The primary properties of the sine function include:
- **Periodicity**: The function repeats its values every \( 2\pi \) interval. This is called its period.
- **Symmetry**: The function is odd, meaning \( \sin(-x) = -\sin(x) \).
- **Amplitude**: The height of the wave, or its maximum value, is 1, and the minimum is -1.
In context with our initial problem, the sine function is essential to find the inverse function \( f^{-1}(x) = \frac{\sin(x)}{3} \).
For the relevant domain of \( f(x) \), \( \ text{arcsin}(3x) \), we used properties of the sine function to solve for \( y \) in terms of \( x \).
These transformations lie at the foundation of trigonometric identities and solving inverse trigonometric equations.
For any input \( x \), \( \sin(x) \) will produce an output between -1 and 1 inclusive.
The primary properties of the sine function include:
- **Periodicity**: The function repeats its values every \( 2\pi \) interval. This is called its period.
- **Symmetry**: The function is odd, meaning \( \sin(-x) = -\sin(x) \).
- **Amplitude**: The height of the wave, or its maximum value, is 1, and the minimum is -1.
In context with our initial problem, the sine function is essential to find the inverse function \( f^{-1}(x) = \frac{\sin(x)}{3} \).
For the relevant domain of \( f(x) \), \( \ text{arcsin}(3x) \), we used properties of the sine function to solve for \( y \) in terms of \( x \).
These transformations lie at the foundation of trigonometric identities and solving inverse trigonometric equations.
Inverse Functions
Inverse functions essentially 'undo' what the original function does.
For example, if a function \( f \) maps x to y, then its inverse \( f^{-1} \) maps y back to x.
With trigonometric functions, such as sine, its inverse \( \text{arcsin} \) or \( \text{sin}^{-1} \) returns the angle whose sine value is the given number.
To find the inverse function, the steps are usually the same:
1. Start with the original function.\( f(x) = \text{sin}^{-1}(3x) \).
2. Express it in terms of \( y \): \( y = \text{sin}^{-1}(3x) \).
3. Swap \( x \) and \( y \), to solve for \( x \) in terms of \( y \).\( x = \text{sin}^{-1}(3y) \).
4. Apply the appropriate inverse operation. Apply the sine function to both sides to get \( \text{sin}(x) = 3y \).
5. Isolate \( y \). Solve for y by dividing both sides by 3: \( y = \frac{\sin(x)}{3} \).
This process of inverting functions is significant across mathematics, providing a parallel for mapping inputs to outputs and vice versa.
When dealing with trigonometric functions, understanding inverse functions deepens our comprehension of angles and their corresponding sine values.
For example, if a function \( f \) maps x to y, then its inverse \( f^{-1} \) maps y back to x.
With trigonometric functions, such as sine, its inverse \( \text{arcsin} \) or \( \text{sin}^{-1} \) returns the angle whose sine value is the given number.
To find the inverse function, the steps are usually the same:
1. Start with the original function.\( f(x) = \text{sin}^{-1}(3x) \).
2. Express it in terms of \( y \): \( y = \text{sin}^{-1}(3x) \).
3. Swap \( x \) and \( y \), to solve for \( x \) in terms of \( y \).\( x = \text{sin}^{-1}(3y) \).
4. Apply the appropriate inverse operation. Apply the sine function to both sides to get \( \text{sin}(x) = 3y \).
5. Isolate \( y \). Solve for y by dividing both sides by 3: \( y = \frac{\sin(x)}{3} \).
This process of inverting functions is significant across mathematics, providing a parallel for mapping inputs to outputs and vice versa.
When dealing with trigonometric functions, understanding inverse functions deepens our comprehension of angles and their corresponding sine values.