Chapter 4: Problem 122
Simplify the expression \((\sin x+\cos x)^{2}-\sin (2 x)\).
Short Answer
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Step by step solution
01
- Use Trigonometric Identities
First, recall and write down the relevant trigonometric identities. We have the square of a sum identity \[ (\text{a}+\text{b})^2 = \text{a}^2+2\text{ab}+\text{b}^2 \]and the double-angle identity for sine, \[ \text{sin}(2x) = 2\text{sin}(x)\text{cos}(x) \]
02
- Apply the Square of a Sum Identity
Apply the square of a sum identity to the given expression \[ (\text{sin}(x) + \text{cos}(x))^2 = \text{sin}^2(x) + 2\text{sin}(x)\text{cos}(x) + \text{cos}^2(x) \].
03
- Use Trigonometric Pythagorean Identity
Recall that the Pythagorean identity states \[ \text{sin}^2(x) + \text{cos}^2(x) = 1 \]. Use this to simplify part of the expression: \[ \text{sin}^2(x) + \text{cos}^2(x) = 1 \].
04
- Substitute and Simplify
Substitute the simplified part into the expression: \[ (\text{sin}(x) + \text{cos}(x))^2 = 1 + 2\text{sin}(x)\text{cos}(x) \].
05
- Substitute the Double-Angle Identity
Replace \(2\text{sin}(x)\text{cos}(x)\) with \(\text{sin}(2x)\) using the double-angle identity: \[ (\text{sin}(x) + \text{cos}(x))^2 = 1 + \text{sin}(2x) \].
06
- Simplify the Complete Expression
Subtract \(\text{sin}(2x)\) from \(1 + \text{sin}(2x)\): \[ 1 + \text{sin}(2x) - \text{sin}(2x) \].
07
- Final Answer
Simplify the expression to get: \[ 1 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Square of a Sum Identity
The square of a sum identity is a fundamental algebraic identity. It helps in simplifying expressions where two terms are added and then squared. The identity is given by:
- \[ (\text{a} + \text{b})^2 = \text{a}^2 + 2\text{ab} + \text{b}^2 \]
- \[ (\text{sin}(x) + \text{cos}(x))^2 = \text{sin}^2(x) + 2\text{sin}(x)\text{cos}(x) + \text{cos}^2(x) \]
Double-Angle Identity for Sine
Another key tool in your trigonometric toolkit is the double-angle identity for sine. It helps to rewrite products of sine and cosine as a single sine of a double angle. This identity states:
- \[ \text{sin}(2x) = 2\text{sin}(x)\text{cos}(x) \]
- \[ \text{sin}^2(x) + 2\text{sin}(x)\text{cos}(x) + \text{cos}^2(x) = 1 + 2\text{sin}(x)\text{cos}(x) \rightarrow 1 + \text{sin}(2x) \]
Pythagorean Identity
The Pythagorean identity is one of the most fundamental identities in trigonometry. It relates the square of sine and cosine to the number 1. The identity is:
- \[ \text{sin}^2(x) + \text{cos}^2(x) = 1 \]